5 Tìm số nguyên x , biết
a) x + 49 = - 97
b) x - 53 = - 61
c) 158 - x = - 92
d) - 218 + x = 147
e) - 135 - x = 41
f) x + 215 = - 315
g) 148 - x = 942
h) 47 - ( - x ) = 18
i) - x + 45 = - 14
Tìm số nguyên x, biết: − 7 15 + − 5 3 + 2 15 ≤ x ≤ 4 7 + 1 + 33 − 21
Ta có: − 7 15 + − 5 3 + 2 15 ≤ x ≤ 4 7 + 1 + 33 − 21 ⇔ − 7 − 25 + 2 15 ≤ x ≤ 12 + 21 − 33 21 ⇔ − 2 ≤ x ≤ 0 mà x ∈ ℤ ⇒ x ∈ − 2 ; − 1 ; 0
Tìm x biết 59-x \41 + 57-x\ 43 + 55-x\45 + 53-x\47 + 51-x\49 = -5 . Giúp mình mình like cho . Ok. <3
Tìm x E Z biết
59-x/41 +57-x/43 +55-x/45 + 53-x/47 +51-x/49=-5
\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{41}+\dfrac{100-x}{43}+\dfrac{100-x}{45}+\dfrac{100-x}{47}+\dfrac{100-x}{49}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\right)=0\)
Mà \(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\ne0\)
\(\Leftrightarrow100-x=0\Leftrightarrow x=100\)
Vậy x = 100
59-x/41+57-x/43+55-x/45+53-x/47+51-x/49=-5
\(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\Leftrightarrow\dfrac{59-x}{41}+1+\dfrac{57-x}{43}+1+\dfrac{55-x}{45}+1+\dfrac{53-x}{47}+1+\dfrac{51-x}{49}+1=0\)
=>100-x=0
hay x=100
Câu 2: (2 điểm) Tim x, biết:
1) (x−1)/2009+(x−2)/2008=(x−3)/2007+(x−4)/2006
2) (59−x)/41+(57−x)/43+(55−x)/45+(53−x)/47+(51−x)/49=−5
1, \(\dfrac{x-1}{2009}+\dfrac{x-2}{2008}=\dfrac{x-3}{2007}+\dfrac{x-4}{2006}\)
\(\Leftrightarrow\left(\dfrac{x-1}{2009}-1\right)+\left(\dfrac{x-2}{2008}-1\right)=\left(\dfrac{x-3}{2007}-1\right)+\left(\dfrac{x-4}{2006}-1\right)\) ( Trừ mỗi vế cho 2 ta được phương trình như này nhé ! )
\(\Leftrightarrow\dfrac{x-2010}{2009}+\dfrac{x-2010}{2008}=\dfrac{x-2010}{2007}+\dfrac{x-2010}{2006}\)
\(\Leftrightarrow\dfrac{x-2010}{2009}+\dfrac{x-2010}{2008}-\dfrac{x-2010}{2007}-\dfrac{x-2010}{2006}=0\)
\(\Leftrightarrow\left(x-2010\right)\left(\dfrac{1}{2009}+\dfrac{1}{2008}-\dfrac{1}{2007}-\dfrac{1}{2006}\right)=0\)
Do \(\dfrac{1}{2009}+\dfrac{1}{2008}-\dfrac{1}{2007}-\dfrac{1}{2006}\ne0\) nên \(x-2010=0\Leftrightarrow x=2010\)
2, \(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\left(\dfrac{59-x}{41}+1\right)+\left(\dfrac{57-x}{43}+1\right)+\left(\dfrac{55-x}{45}+1\right)+\left(\dfrac{53-x}{47}+1\right)+\left(\dfrac{51-x}{49}+1\right)=0\)
\(\Leftrightarrow\dfrac{100-x}{41}+\dfrac{100-x}{43}+\dfrac{100-x}{45}+\dfrac{100-x}{47}+\dfrac{100-x}{49}=0\) \(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\right)=0\) Do \(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\ne0\) nên \(100-x=0\Leftrightarrow x=100\)
Tính hợp lí:
a) 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21.
b) 5 x 7 x 77- 7 x 60 + 49 x 25 - 15 x 42
c) ( 43 x 52 - 43 ) : ( 4 x 42 )
d) ( 2 + 5 + 11 +...+ 47 + 65
đ) ( 45 x 16 - 17 ) : ( 28 + 45 x 15 )
a, 53 * 39 + 47 * 59 - 53 * 21 - 47 * 21 c, (43 * 52 - 43 ) : ( 4 * 42 )
= ( 53 + 47 ) * 39 - ( 53 + 47 ) * 21 = ( 64 * 25 - 64 ) : ( 4 * 16 )
= 100 * 39 - 100 * 21 = ( 1600 - 64 ) : 64
= ( 39 - 21 ) * 100 = 1536 : 64
= 18 * 100 = 24
= 1800
Tính hợp lí:
a) 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21.
b) 5 x 7 x 77- 7 x 60 + 49 x 25 - 15 x 42
c) ( 43 x 52 - 43 ) : ( 4 x 42 )
d) ( 2 + 5 + 11 +...+ 47 + 65
đ) ( 45 x 16 - 17 ) : ( 28 + 45 x 15 )
Đọc tiếp...
giải phương trình: (59-x/41) + (57-x/43) + (55-x/45) + (53-x/47) + (51-x/49) = -5
ta có: (59-x)/41 +(57-x)/43 +(55-x)/45 +(53-x)/47 +(51-x)/49 =-5
<=>[(59-x)/41 +1 ] +[(57-x)/43 +1] +[(55-x)/45 +1] +[(53-x)/47 +1] +[(51-x)/49 +1] =0
<=>(59-x-41)/41 + (57-x-43)/43 +(55-x-45)/45 +(53-x-47)/47 +(51-x-49)/49 =0
<=>(100-x)/41 + (100-x)/43 + (100-x)/45 +(100-x)/47 + (100-x)/49 =0
<=>(100-x).( 1/41 + 1/43 + 1/45 + 1/47 + 1/49 ) =0
mà (1/41 + 1/43 + 1/45 + 1/47 + 1/49) khác 0 nên 100-x =0 <=>x=100
vậy nghiệm của pt là x=100
Tìm số nguyên x, biết:
a) (135 + x) - 135 = 0; b) ( -562) - ( x- 562) = 0;
c) 61 + ( x - 23) = 91; d) 11- ( -53 + x) = 97.
a) 135 + x -135 = 0 => (135 - 135) + x = 0 => x = 0.
b) -562 - x + 562 = 0 => (-562 + 562) - x = 0 => - x = 0 => x = 0.
c) 61 + x - 23 = 91=> (61 - 23) + x = 91=>38 + x = 91=> x = 53.
d) 11 + 53 - x = 97 => 64 - x = 97 => x = 64 - 97 => x = - 33
Tìm số nguyên x, biết: a) (135 + x) - 135 = 0; b) ( -562) - ( x- 562) = 0; c) 61 + ( x - 23) = 91; d) 11- ( -53 + x) = 97.