Ta có : \(\frac{6^3+3.6^2+3^3}{-13}\) 

   \(=\frac{\left(3.2\right)^3+3.\left(2.3\right)^2+3^3}{-13}\) 

   \(=\frac{3^3.2^3+3.3^2.2^2+3^3}{-13}\) 

    \(=\frac{3^3.2^3+3^3.2^2+3^3.1}{-13}\) 

     \(=\frac{3^3\left(2^3+2^2+1\right)}{-13}\) 

      \(=\frac{3^3.13}{-13}\) 

       \(=\frac{3^3.13}{\left(-1\right).13}\) 

        \(=-3^3\) 

         \(=-27\)

(6²+3)(1+3³)/-13=39.28/-13=-84

6³ + 3 . 6² + 3³ / -13

= 2³ . 3³ + 3 . 2² . 3² + 3³ / -13

= 3³ . 8 + 3³ . 4 + 3³ / -13

= 3³ . (8 + 4 + 1) / -13

= 27 . 13 / -13

= -27

kết quả là -27

4^6.9^5+6^9.120/8^4.3^12-6^11

=(3.2)3+3.(3.2)2+33−13 =33.23+33.3.22+33−13 =33(23+3.22+1)−13 =27.21−13 =−56713 

\(\frac{6^3+3.6^2+3^3}{-13}=\frac{3^3.2^3+3.2^2.3^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3=-27\)\(27\)

Đáp án :

= ( 3.2 ) 3 +3 . ( 3.2 ) 2 + 33 - 13 = 33.23 + 33.3.22 + 33 - 13 = 33 ( 23 +3 . 22 + 1 ) - 13 = 27.21 - 13 = 567137

Đáp án : 567137

a) \(\frac{2^7}{6^5}\times\frac{9^3}{8^8}=\frac{2^7}{2^5\times3^5}\times\frac{3^6}{2^{24}}=\frac{2^7\times3^6}{2^{29}\times3^5}=\frac{3}{4194304}\)

b) \(\frac{6^3+3\times6^2+3^3}{-13}=\frac{2^3\times3^3+3\times2^2\times3^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27\times13}{-13}=-27\)

\(\frac{6^3+3.6^2+3^3}{-13}=\frac{3^3\left(8+4+1\right)}{-13}=\frac{27.13}{-13}=-27\)

\(=\frac{2^3.3^3+3^3.2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3=-27\)

                                     Đặt \(A=\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2.\left(6+3.1\right)+3^3}{-13}=\frac{6^2.9+3^3}{-13}=\frac{6^2.3^2+3^3}{-13}\)                                                                    \(=\frac{3^2.\left(6^2.1+3\right)}{-13}=\frac{9.\left(36+3\right)}{-13}=\frac{9.13.3}{-1.13}=\frac{9.3}{-1}=-27\)

                                                         Ủng hộ mk nha!!!!

a,3/16

b,-6399/325

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{2^4}=\frac{3}{16}\)

\(\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(3.2\right)^3+3.\left(3.2\right)^2+3^3}{-13}=\frac{3^3.2^3+3.3^2.2^2+3^3}{-13}\)\(=\frac{3^3.\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3=-27\)