(y x 5 -19)+(y x 3+24)=125
Tìm XX biết: (X \times 5 - 19) + (X \times 3 + 24) = 125.(X×5−19)+(X×3+24)=125. \Trả lời: X =X=
( X x 5 - 19 ) +( X x 3 + 24 ) = 125
Mình làm lun nhé
X x 5 -19 + X x 3 + 24 =125(PHá ngoặc)
X x(5+3) +24-19=125
X x 8 +5=125
X x 8 =125 -5
X x 8 =120
\(5x-19+3x+24=125\)
\(5x+3x=125+19-24\)
\(8x=120\)
\(x=120:8\)
\(x=15\)
(x * 5 - 19) + (x * 3 + 24) = 125
x * 5 - 19 + x * 3 + 24 = 125
x * (5 - 19) + 24 = 125
x * (-14) + 24 = 125
x * (-14) = 125 - 24
x * (-14) = 149
x = 149/(-14)
Tìm X biết: (X x 5 - 19) + (X x 3 + 24) = 125
=>5x-19+3x+24=125
=>8x+5=125
hay x=15
Tìm X biết: (X x 5 - 19) + (X x 3 + 24) = 125
( 5 x − 19 ) + ( 3 x + 24 ) = 125
. 5 x − 19 + 3 x + 24 = 125
8 x + 5 = 125
8 x = 120
x = 15
(x+5-19)+(x+3+24)=125
\(\left(x+5-19\right)+\left(x+3+24\right)=125\)
\(x+5-19+x+3+24=125\)
\(2x+8+5=125\)
\(2x+13=125\)
\(2x=125-13\)
\(2x=112\)
\(x=112\div2\)
\(x=56\)
(x+5-19)+(x +3 +24)=125
x-(19-5) + x+27 =125
x-14 + x+27=125
x+x-14+27=125
x x2 +27-14=125
x x2 +13=125
x x2=125-13=112
x=112 :2=56
\(\left(x+5-19\right)+\left(x+3+24\right)=125\)
\(\Rightarrow x-14+x+27=125\)
\(\Rightarrow\left(x+x\right)+\left(27-14\right)=125\)
\(\Rightarrow2\times x+13=125\)
\(\Rightarrow2\times x=125-13\)
\(\Rightarrow2\times x=112\)
\(\Rightarrow x=112:2\)
\(\Rightarrow x=56\)
Vậy \(x=56\)
~ Ủng hộ nhé
(X×5-19)+(X×3+24)=125
( X x 5 - 19 ) + ( X x 3 + 24 ) = 125 Tìm X ..........................
X x 5 +X X 3 +24-19 =125
8 x X +5 =125
8 x X=120
X=15
5 x X +3 x X +24-19 =125
8 x X +5 =125
8 x X=120
X=15
Tìm X biết (X * 5 - 19 )+(X * 3 + 24 ) = 125
( X * 5 - 19 ) + ( X * 3 +24 ) = 125
x*5 - 19 + x*3 + 24 = 125
x*5 + x*3 - 19 +24 =125
8*x -19 = 125-24
8*x -19 = 101
8*x = 101+19
8*x = 120
x = 120 : 8
x = 15
Tìm x biết:( X x 5 -19) + (X x 3 + 24) = 125
\(\left(5x-19\right)+\left(3x+24\right)=125\)
.\(5x-19+3x+24=125\)
\(8x+5=125\)
\(8x=120\)
\(x=15\)
ta có x *8 =125+19-24
x*8=120
x=120\8
x=15