Tìm biết:( X x 5 -19)+(X x 3+24) = 125
Tìm XX biết: (X \times 5 - 19) + (X \times 3 + 24) = 125.(X×5−19)+(X×3+24)=125. \Trả lời: X =X=
Tìm X biết: (X x 5 - 19) + (X x 3 + 24) = 125
=>5x-19+3x+24=125
=>8x+5=125
hay x=15
Tìm X biết: (X x 5 - 19) + (X x 3 + 24) = 125
( 5 x − 19 ) + ( 3 x + 24 ) = 125
. 5 x − 19 + 3 x + 24 = 125
8 x + 5 = 125
8 x = 120
x = 15
Tìm x biết:( X x 5 -19) + (X x 3 + 24) = 125
\(\left(5x-19\right)+\left(3x+24\right)=125\)
.\(5x-19+3x+24=125\)
\(8x+5=125\)
\(8x=120\)
\(x=15\)
ta có x *8 =125+19-24
x*8=120
x=120\8
x=15
tìm x biết:( x x 5 - 19) - x x 3 +24 = 125
( X x 5 - 19) - X x 3 +24 = 125
(X x 5- 19) - X x 3 =125 - 24 = 101
X x 5 - 19 =101 + X x 3
X x 5- X x 3 =101 + 19 = 120
X x 2 =120
X =60
Tìm X biết (X * 5 - 19 )+(X * 3 + 24 ) = 125
( X * 5 - 19 ) + ( X * 3 +24 ) = 125
x*5 - 19 + x*3 + 24 = 125
x*5 + x*3 - 19 +24 =125
8*x -19 = 125-24
8*x -19 = 101
8*x = 101+19
8*x = 120
x = 120 : 8
x = 15
Tìm x , biết .
( X x 5 - 19 ) + ( X x 3 +24 ) = 125.
(5x - 19) + (3x + 24) = 125
5x - 19 + 3x + 24 = 125
8x + 5 = 125
8x = 120
x = 15
Tìm X biết: ( X × 5 - 19) + ( X × 3 + 24) = 125.
đ/s x=15 vì
125 - (24-19) =120
x x5 + x x3 =120
=x x(5+3)=120
=x x8=120
x=120:8
x=15
(nhớ k cho mình nha)
( X x 5 - 19 ) + ( X x 3 + 24 ) = 125
X x 8 = 125 - 24 + 19
X x 8 = 120
X = 120 : 8
X = 15
\(\left(x.5-19\right)+\left(x.3+24\right)=125\)
\(\Rightarrow5x-19+3x+24=125\)
\(\Rightarrow2x+5=125\)
\(\Rightarrow2x=120\)
\(\Rightarrow x=60\)
Vậy x = 60
( X x 5 - 19 ) + ( X x 3 + 24 ) = 125 Tìm X ..........................
X x 5 +X X 3 +24-19 =125
8 x X +5 =125
8 x X=120
X=15
5 x X +3 x X +24-19 =125
8 x X +5 =125
8 x X=120
X=15