Ta có:

 A = [15 x (1-1/7-1/12-1/98)] / [ 18 x (1-1/7-1/12-1/98)]

  = 15/18 = 5/6

\(A=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}=\frac{15}{18}=\frac{15:3}{18:3}=\frac{5}{6}\)

k cho mk nha

giải:  12/15(2/7+3/7+1/7+1/7)=12/15.7/7=12/15=4/5

\(=\frac{12}{15}.\left(\frac{2}{7}+\frac{3}{7}+\frac{1}{7}+\frac{1}{7}\right)\)

\(=\frac{12}{15}.1\)

\(=\frac{12}{15}=\frac{4}{5}\)

https://vn.answers.yahoo.com/question/index?qid=20100907070553AAEawEd

lời giải rõ ràng rồi đó bạn ^_~

\(\frac{15-\frac{15}{7}-\frac{15}{12}}{3-\frac{3}{7}-\frac{3}{12}}\)

\(=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}\right)}{3\left(1-\frac{1}{7}-\frac{1}{12}\right)}\)

\(=\frac{15}{3}\)

K  nha 

A=15x(1/7-1/12-1/98)/18(1/7-1/12-1/98)

A=15/18

A=5/6

h nhe!!!

\(A=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}\)

\(A=\frac{15}{18}=\frac{5}{6}\)

\(A=\frac{15-\frac{15}{7}-\frac{15}{12}-\frac{15}{98}}{18-\frac{18}{7}-\frac{18}{12}-\frac{18}{98}}\)

\(\Rightarrow A=\frac{15\left(\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}\)

\(\Rightarrow A=\frac{15}{18}=\frac{5}{6}\)

mk làm chuẩn rồi nha

\(A=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{18}\right)}=\frac{15}{18}\)

\(A=\frac{15\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}{18\left(1-\frac{1}{7}-\frac{1}{12}-\frac{1}{98}\right)}=\frac{15}{18}=\frac{5}{6}\)

\(a,=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

\(=1+-1\)

\(=0\)