Tìm X
1440 : [ 41 - ( 2x - 5 ) ] = 48
Tìm số tự nhiên x , biết:
a) 36 : x - 5 = 2 2
b) 3 . 70 - x + 5 : 2 = 46
c) 450 : 41 - 2 x - 5 = 3 2 . 5
d) 230 + 2 4 + x - 5 = 315 . 2018 0
e) 2 x + 2 x + 1 = 48
f) 3 x + 1 + 3 x = 2430
Tìm số tự nhiên x , biết:
a, 36:(x–5) = 2 2
b, [3.(70–x)+5]:2 = 46
c, 450:[41–(2x–5)] = 3 2 .5
d, 230+[ 2 4 +(x–5)] = 315. 2018 0
e, 2 x + 2 x + 1 = 48
f, 3 x + 2 + 3 x = 2430
a, 36:(x–5) = 2 2
(x–5) = 9
x = 14
b, [3.(70–x)+5]:2 = 46
[3.(70–x)+5] = 92
70–x = 29
x = 41
c, 450:[41–(2x–5)] = 3 2 .5
41–(2x–5) = 10
2x–5 = 31
2x = 36
x = 18
d, 230+[ 2 4 +(x–5)] = 315. 2018 0
16+(x–5) = 315–230
x–5 = 85–16
x = 69+5
x = 74
e, 2 x + 2 x + 1 = 48
2 x .(2+1) = 48
2 x = 16 = 2 4
x = 4
f, 3 x + 2 + 3 x = 2430
3 x . 3 2 + 1 = 2430
3 x = 2430:10 = 243 = 3 5
x = 5
b) 1500.(x – 7) = 0
c) (2.x – 4).(48 – 12.x) = 0
d) (x + 12).(x – 1) =0
Bài 2: Tìm x biết:
a) 128- 3(x+ 4) = 23
b) [(14x+ 26). 3+ 55]: 5= 35
d) 720: [41- (2x- 5)]= 23. 5
b. 1500(x-7)=0
x-7=0
x=7
c. (2x-4)(48-12x)=0
2x-4=0 hoặc 48-12x=0
x=2 hoặc x=4
d. (x+12)(x-1)=0
x+12=0 hoặc x-1=0
x=-12 hoặc x=1
bài 2 :
a . 128-3(x+4)=23
3(x+4)=105
x+4=35
x=31
b. [(14X+26).3+55]:5=35
(14x+26).3+55=175
(14x+26).3=120
14x+26=40
14x=14
x=1
d. 720:[41-(2X-5)]=23.5
41-(2x-5)=720:(23.5)
41-(2x-5)=144/23
2x-5=799/23
2x=914/23
x=457/23
b, 1500.(x – 7) = 0
<=>1500x-10500=0
<=>1500x=10500
<=>x=7
Vậy x=7
c,(2.x – 4).(48 – 12.x) = 0
\(\Leftrightarrow\)\(\left\{{}\begin{matrix}2x-4=0\\48-12x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\12x=48\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
Vậy x=2 hoặc x=4
d, (x + 12).(x – 1) =0
\(\Leftrightarrow\left\{{}\begin{matrix}x+12=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-12\\x=1\end{matrix}\right.\)
Vậy x=-12 hoặc x=1
Bài 2:
a) 128- 3(x+ 4) = 23
\(\Leftrightarrow\)128-(3x+12)=23
\(\Leftrightarrow\)128-3x-12=23
\(\Leftrightarrow\)116-3x=23
\(\Leftrightarrow\)3x=116-23
\(\Leftrightarrow\)3x=93
\(\Leftrightarrow\)x=31
Vậy x=31
b) [(14x+ 26). 3+ 55]: 5= 35
\(\Leftrightarrow\)(14x+ 26). 3+ 55=175
\(\Leftrightarrow\)42x+78+55=175
\(\Leftrightarrow\)42x+133=175
\(\Leftrightarrow\)42x=175-133
\(\Leftrightarrow\)42x=42
\(\Leftrightarrow\)x=1
Vậy x=1
d, 720: [41- (2x- 5)]= 23. 5
\(\Leftrightarrow\)720: 41- (2x- 5)=115
\(\Leftrightarrow\)41-(2x- 5)=720:115
\(\Leftrightarrow\)41-(2x- 5)=\(\dfrac{144}{23}\)
\(\Leftrightarrow\)2x-5=\(\dfrac{799}{23}\)
\(\Leftrightarrow\)2x=\(\dfrac{914}{23}\)
\(\Leftrightarrow\)x=\(\dfrac{457}{23}\)
Vậy x=\(\dfrac{457}{23}\)
1. Tìm x biết
a. 1440:[41-(2x-5)] =2^4 x3
b, 3x(1-4x)+2x(6x-1) =x-18
c, (2x+1)^3 -72 = (-45)
d, 4^2x-1 +18 = 48+36
e, Tìm x thuốc Z để 2x-1/ x-3 nguyên
1e) Để \(\frac{2x-1}{x-3}\) nguyên thì \(2x-1⋮x-3\)
\(\Leftrightarrow2x-6+5⋮x-3\)
\(\Leftrightarrow2\left(x-3\right)+5⋮x-3\)
Do \(2\left(x-3\right)⋮x-3\) \(\Rightarrow5⋮x-3\)
\(\Rightarrow x-3\in\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow x\in\left\{-2;2;4;8\right\}\)
Vậy:...................
tìm x biết 720 : [ 41- (2x -5) ] = 2^3 .5
720:[41-(2x - 5)]=23.5
720:[41-(2x - 5)]=8.5
720:[41-(2x - 5)]=40
41-(2x - 5)=720:40
41-(2x - 5)=18
2x - 5=41-18
2x - 5=23
2.x=23+5
2.x=28
x=28:2
x=14
Tìm x
23+3x=125
41-(2x-5)=18
23+3x=125
3x=125-23
3x= 102
x= 102:3
x= 34
41-(2x-5)=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
720:(41-2x-5)=23,5
Tìm x
\(720:\left(41-2x-5\right)=23,5\)
<=> \(41-2x-5=\frac{1440}{47}\)
<=> \(x=2,680851064\)
\(720:\left(41-2x-5\right)=23,5\)
\(\Leftrightarrow720:36-720:2x=23,5\)
\(\Leftrightarrow20-720:2x=23,5\)
\(\Leftrightarrow-720:2x=23,5-20\)
\(\Leftrightarrow-720:2x=3,5\)
\(\Leftrightarrow2x=\frac{-1440}{7}\)
\(\Leftrightarrow x=\frac{-720}{7}\)
720 : ( 41 - 2x - 5 ) = 23.5
41 - 2x - 5 = 720 : 23.5
41 - 2x - 5 = 1440/47
36 - 2x = 1440/47
2x = 36 - 1440/47
2x = 252/47
x = 252/47 : 2
x = 126/47
tìm x biết [ 41 -(2x -5)] = 2^3.5
[ 41 -(2x -5)] = 2^3.5
[ 41 -(2x -5)] = 8.5
[ 41 -(2x -5)] = 40
2x -5= 41 - 40
2x -5 = 1
2x = 1 + 5
2x = 6
x = 6 : 2
x = 3
HOk tốt
\(41-\left(2x-5\right)=2^3.5\)
\(\Rightarrow41-\left(2x-5\right)=8.5\)
\(\Rightarrow41-\left(2x-5\right)=40\)
\(\Rightarrow2x-5=41-40\)
\(\Rightarrow2x-5=1\)
\(\Rightarrow2x=1+5\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=6:2\)
\(\Rightarrow x=3\)
Vậy x = 3
_Chúc bạn học tốt_
\(41-\left(2x-5\right)=2^3.5\)
\(\Leftrightarrow41-2x+5=8.5\)
\(\Leftrightarrow-2x+5=40-41\)
\(\Leftrightarrow-2x+5=-1\)
\(\Leftrightarrow-2x=-1-5\)
\(\Leftrightarrow-2x=-6\)
\(\Leftrightarrow x=-6:\left(-2\right)=3\)
Vậy \(x=3\)
Tìm x biết 720:[41-(2x-5)]=120
=> 41 - ( 2x - 5) = 720 : 160 = 6
=> 2x - 5 = 41 - 6
=> 2x - 5 = 35
=>2x = 40
=> x = 20
Vậy x = 20
Ta co:
720:[41-(2x-5)]=120
41-(2x-5) = 720 : 120
41 - (2x-5) = 6
2x - 5 = 41 -6
2x -5 = 35
2x = 35 +5
2x = 40
x = 40 :2
x =20
Vậy x bằng 20
720 : [ 41 - ( 2x - 5 ) ] = 120
=> 41 - ( 2x - 5 ) = 720 : 120 = 6
=> 2x - 5 = 41 - 6 = 35
=> 2x = 35 + 5 = 40
=> x = 40 : 2 = 20
đúng nha !!!