dat thua so chung la 87

roi giai

=87*(1000-900+9+11-20+80-60-20)

=87*100=8700

Đáp án là 8700

12 : 35 = \(\frac{12}{35}\)

112 : 63 = \(\frac{112}{63}\)

41 : 100 = \(\frac{41}{100}\)

217 : 100 = \(\frac{217}{100}\)

11 : 45 = \(\frac{11}{45}\)

416 : 87 = \(\frac{416}{87}\)

12 : 35 = 12/35

112 : 63 = 112/63

217: 100 = 217/100

11 : 45 = 11/45

416: 87 = 416/87

tự làm đi có làm thì mới có ăn chứ

a) \(3119\cdot121-3119\cdot11\cdot11\)

\(=3119\cdot121-3119\cdot\left(11\cdot11\right)\)

\(=3119\cdot121-3119\cdot121\)

\(=3119\left(121-121\right)\)

\(=0\)

b) \(24\cdot\left(123\cdot87\right)+\left(87\cdot123\right)\cdot76\)

\(=\left(123\cdot87\right)\cdot\left(76+24\right)\)

\(=\left(123\cdot87\right)\cdot100\)

\(=1070100\)

 $\frac{x-11}{89}+\frac{x-13}{87}+\frac{x-15}{85}+\frac{x-17}{83}=4$$=>\left(\frac{x-11}{89}-1\right)+\left(\frac{x-13}{87}-1\right)+\left(\frac{x-15}{85}-1\right)+\left(\frac{x-17}{83}-1\right)=0$$=>\frac{x-100}{89}+\frac{x-100}{87}+\frac{x-100}{85}+\frac{x-100}{83}=0$$=>\left(x-100\right)\left(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\right)=0$=> x-100 =0 => x=100Vậy nghiệm là 100 

ta có 0=\(\frac{x-11}{89}-1+\frac{x-13}{87}-1+\frac{x-15}{85}-1+\frac{x-17}{83}-1=0\)

0=\(\frac{x-11-89}{89}+\frac{x-13-87}{87}+\frac{x-15-85}{85}+\frac{x-17-83}{83}\)

0=\(\frac{x-100}{89}+\frac{x-100}{87}+\frac{x-100}{85}+\frac{x-100}{83}\)

0=(x-100)(\(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\))

vì \(\frac{1}{89}+\frac{1}{87}+\frac{1}{85}+\frac{1}{83}\)khác 0      suy ra x-100=0 

                                                                                    x=100

x−11/89+x−13/87+x−15/85+x−17/83=4

=>(x−11/89−1)+(x−13/87−1)+(x−15/85−1)+(x−17/83−1)=0

=>x−100/89+x−100/87+x−100/85+x−100/83=0

=>(x−100)(1/89+1/87+1/85+1/83)=0

=> x-100 =0 

Vậy nghiệm là 100

\(S=\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.85}\)

\(S=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}+\frac{1}{19}-\frac{1}{32}+\frac{1}{32}-\frac{1}{57}+\frac{1}{57}-\frac{1}{87}\)

\(S=\frac{1}{3}-\frac{1}{87}\)

\(S=\frac{28}{87}\)

`B=5/[3.7]+5/[7.11]+5/[11.15]+....+5/[83.87]+5/[87.101]`

`B=5/4(4/[3.7]+4/[7.11]+4/[11.15]+....+4/[83.87]+4/[87.101])`

`B=5/4(1/3-1/7+1/7-1/11+1/11-1/15+....+1/83-1/87+1/87-1/101)`

`B=5/4(1/3-1/101)`

`B=5/4 . 98/303=245/606`

Số hạng tử của B là : ( 89 - 11 ) : 2 + 1 = 40 ( hạng tử )

\(B=11+13+15+...+87+89\)

\(=\left(11+98\right).40:2\)

\(=2180\)

B = 11 + 13 + 15 + ... + 87 + 89

Ta có : B = 11 + 13 + 15 + ... + 87 + 89 (có 40 số )

               = (89 + 11) . 40 : 2

               = 2000

B = ( 89 + 11 ) x[ ( 89 - 11 ) : 2 + 1] : 2 = 2000 

hok tốt

Bài này chắc chắn không phải của lớp 3 , phải là lớp 6

40 nha bé

k anh đi

ĐANG HỌC LỚP 2 Ý CÁC BẠN AH

11+1+11x2:1+1=35

87+234=321

321