2011:25+2009:25

=(2011+2009):25

=4020:25

=160,8

=80.44+80.36

=160.8

a, 2³  + (-2)³+ 8^-1

= 8 + (-8)+ 1/8

= 0 +1/8

= 1/8

b, (-1)²⁰¹⁹ + (-1)²⁰²⁰

= (-1) + 1

= 0

c,(-3)⁴ +2³

= 81 + 8

=  89

d, 125² : 25
= (25x5)² : 25

= 25² x 5²  : 25

=  (25²:25) x 5²

⁼ 25 x 25

= 625

=

a) \(2^3+\left(-2\right)^3+8^{-1}=2^3-2^3+\frac{1}{8}\)

                                             \(=\frac{1}{8}\)

b) \(\left(-1\right)^{2019}+\left(-1\right)^{2020}=-1+1\)

                                                    \(=0\)

c) \(\left(-3\right)^4+2^3=81+8\)

                              \(=90\)

d) \(125^2\div25=\frac{\left(25.5\right)^2}{25}\)

                           \(=\frac{25^2.5^2}{25}\)

                           \(=25.25\)

                           \(=625\)

\(2^3+\left(-2\right)^3+8^{-1}=8+\left(-8\right)+\frac{1}{8}=\frac{1}{8}\)

\(\left(-1\right)^{2019}+\left(-1\right)^{2020}=\left(-1\right)+1=0\)

\(\left(-3\right)^4+2^3=81+8=89\)

\(125^2\div25=\left(5^3\right)^2\div5^2=5^6\div5^2=5^4=625\)

thiếu đề rồi bạn

thiếu đề bài

Thiếu đề bài rồi bn êy

\(\frac{1}{8}=12,5\%\)  ;  \(\frac{1}{16}=6,25\%\) ; \(\frac{1}{2}=50\%\) ; \(\frac{1}{4}=25\%\) 

Thay vào trên mà tính.

= \(1+\left(\frac{3\left(1x2+2x4x2\right)}{3\left(5+5x3x25\right)}+1\right)-\left(1+\frac{18}{54}\right)-1\) = \(\frac{18}{380}-\frac{18}{54}\)  

\(125^4:25^3=\left(5^4\right)^4:\left(5^2\right)^3=5^{16}:5^6=5^{10}\)

\(8^4x16^5x5^{40}=2^{12}x2^{20}x5^{40}=2^{32}x5^{40}\)

18^3 : 9^3 = 5832 : 729 = 8

125^3 : 25^3 = (5^3)^3 : (5^2)^3 = 5^9 : 5^6 = 5^3 = 125

có quy luật hay lắm

\(18^3:9^3=\left(18:9\right)^3=2^3=8\)

\(125^3:25^3=\hept{\begin{cases}\left(5^3\right)^3:\left(5^2\right)^3=5^9:5^6=5^3=125\\\left(5^3\right)^3:\left(5^2\right)^3=\left(5^3:5^2\right)^3=5^3=125\end{cases}}\)chọn cách nào thì tùy bạn

\(\left(10^3+10^4+125^3\right):5^3=\left[10^3+10^3.10+\left(5^2\right)^3\right]:5^3\)

\(=\left(10^3.11+5^6\right):5^3\)

\(=10^3.11:5^3+5^6:5^3\)

\(=\left(10^3:5^3\right).11+5^3\)

\(=2^3.11+5^3\)

\(=88+125=213\)

\(\left(2^{43}+2^4\right):\left(2^{39}+1\right)=\)tương tự mà làm

MÀY

vào câu hỏi tương tự .

Ok?

x-4867=(175.2050.70):25+23

x-4867=25112500:25+23

x-4867=1004500+23

x-4867=1004523

       x = 1004523+4867

       x = 1009390

a: \(27^{2-x}< =9\)

=>\(\left(3^3\right)^{2-x}< =3^2\)

=>\(3^{6-3x}< =3^2\)

=>6-3x<=2

=>-3x<=-4

=>\(x>=\dfrac{4}{3}\)

b: \(7^{3-x}< 49\)

=>\(7^{3-x}< 7^2\)

=>3-x<2

=>-x<2-3=-1

=>x>1

c: \(27^{3-x}>9\)

=>\(\left(3^3\right)^{3-x}>3^2\)

=>\(3^{9-3x}>3^2\)

=>9-3x>2

=>-3x>-7

=>\(x< \dfrac{7}{3}\)

d: \(2^{3-x}< 2^3\)

=>3-x<3

=>-x<0

=>x>0

e: \(27^{3-x^2}< 27^{x+1}\)

=>\(3-x^2< x+1\)

=>\(-x^2-x+2< 0\)

=>\(x^2+x-2>0\)

=>(x+2)(x-1)>0

=>\(\left[{}\begin{matrix}x>1\\x< -2\end{matrix}\right.\)

=27x(3+2+1+1)

=27x7

=189

bằng 189

27x3+27x2+27+27=81+54+27+27=189