\(\dfrac{2}{30}\)

`(1 xx 2 xx 3 xx 4)/(3 xx 4 xx 5 xx 6)`

`= (1 xx 2)/(5 xx 6)`

`= 2/12`

`= 1/6`

Bổ sung:

`(1 xx 2)/(5 xx 6)`

`= 2/30`

`= 1/15`

b)0,5x+2/3x+2/3=7/2

   1/2x+2/3x+2/3=7/2

     x(1/2+2/3)+2/3=7/12

     x.7/6+2/3       =7/12

     x.7/6              =7/12-2/3

    x.7/6               =-1/12

    x                     =-1/12:7/6

    x                    =-1/14

b)3/5-2/15:x=1/2

   2/15:x       =3/5-1/2

   2/15:x       =1/10

   x                =2/15:1/10

   x                = 4/3

cậu giải thích giùm mình đoạn này với P(x)=x^7-(x+1)x^6+(x+1)x^5-(x+1)x^4+(x+1)x^3-(x+1)x^2+(x+1)x+15

P(x)=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x+15

P(x)=x+15=79+15=94

hay giai giup mk may phan nay nhe

cmr cac bieu thuc sau ko phu thuoc vao x:

c)C=x(x^3+x^2-3x-2)-(x^2-2)(x^2+x-1)

e)E=(x+1)(x^2-x+1)-(x-1)(x^2+x+1)

tinh gia tri cua da thuc

b)Q(x)=x^14-10x^13=10x^12-10x^11+...+10x^2-10x+10   voi x=9

c)R(x)=x^4-17x^3+17x^2_17x+20   või=16

d)S(x)=x^10-13x^9+13x^8-13X^7+...+13x^2-13x+10     voi 12

bạn đăng tách cho mn cùng giúp nhé 

Bài 1 : 

a, \(\Leftrightarrow11-x=12-8x\Leftrightarrow7x=1\Leftrightarrow x=\dfrac{1}{7}\)

b, \(\Leftrightarrow2x\left(x^2+4x+4\right)-8x^2=2\left(x^3-8\right)\)

\(\Leftrightarrow2x^3+8x^2+8x-8x^2=2x^3-16\Leftrightarrow x=-2\)

c, \(\Leftrightarrow3-2x=-x-4\Leftrightarrow x=7\)

d, \(\Leftrightarrow x^3-6x^2+12x-8+9x^2-1=x^3+3x^2+3x+1\)

\(\Leftrightarrow3x^2+12x-9=3x^2+3x+1\Leftrightarrow x=\dfrac{10}{9}\)

e, \(\Leftrightarrow2x^2-x-3=2x^2+9x-5\Leftrightarrow x=5\)

f, \(\Leftrightarrow x^3-3x^2+3x-1-x^3-2x^2-x=10x-5x^2-11x-22\)

\(\Leftrightarrow-5x^2+2x-1=-5x^2-x-22\Leftrightarrow3x=-21\Leftrightarrow x=-7\)

h) \(PT\Leftrightarrow x^2+4x-3x-12-6x+4=x^2-8x+16\)

\(\Leftrightarrow3x=24\)

\(\Leftrightarrow x=8\)

Vậy: \(S=\left\{8\right\}\)

j) \(PT\Leftrightarrow x^3-x^2+x+x^2-x+1-2x=x^3-x\)

\(\Leftrightarrow x=1\)

Vậy: \(S=\left\{1\right\}\)

\(\frac{4}{5}x\frac{1}{4}+\frac{1}{2}x\frac{4}{5}\)

\(\frac{4}{5}x\left(\frac{1}{4}+\frac{1}{2}\right)\)

\(\frac{4}{5}x\frac{3}{4}=\frac{3}{5}\)

\(\frac{3}{4}x\frac{4}{5}+\frac{5}{6}x\frac{6}{7}x\frac{7}{8}\)

\(\frac{3}{5}+\frac{5}{8}=\frac{49}{40}\)

A) 4/5 x 1/4 + 1/2 x 4/5

 = 4/5 x (1/4 + 1/2)

 = 4/5 x (1/4 + 2/4)

 = 4/5 x 3/4

 = 3/5

\(\frac{4}{5}x\left(\frac{1}{2}+\frac{1}{4}\right)=\frac{4}{5}x\frac{3}{4}=\frac{3}{5}\)

\(a.\frac{19}{5}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{19}{5}-\frac{4}{5}\)

\(=\frac{19}{5}\cdot\left(\frac{4}{7}+\frac{3}{7}\right)-\frac{4}{5}\)

\(=\frac{19}{5}\cdot1-\frac{4}{5}\)

\(=\frac{19}{5}-\frac{4}{5}=\frac{15}{5}=3\)

\(b.2\frac{2}{7}\cdot5\frac{2}{5}+\frac{16}{7}\cdot1\frac{3}{5}+\frac{1}{2}\)

\(=\frac{16}{7}\cdot\frac{27}{5}+\frac{16}{7}\cdot\frac{8}{5}+\frac{1}{2}\)

\(=\frac{16}{7}\cdot\left(\frac{27}{5}+\frac{8}{5}\right)+\frac{1}{2}\)

\(=\frac{16}{7}\cdot7+\frac{1}{2}\)

\(=16+\frac{1}{2}=\frac{33}{2}\)

\(c.\frac{3}{7}\cdot3\frac{3}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\frac{15}{4}-\frac{3}{7}\cdot\frac{5}{4}-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\left(\frac{15}{4}-\frac{5}{4}\right)-\frac{1}{4}\)

\(=\frac{3}{7}\cdot\frac{5}{2}-\frac{1}{4}\)

\(=\frac{15}{14}-\frac{1}{4}=\frac{23}{28}\)

Chú ý: \(\cdot:\times\)

(2/3 x 4/5) x 5/6

=   8/15     x 5/6

=             4/9

(2/3 x 4/5) x 5/6 

= (5/6 x 4/5) x 2/3

=        2/3     x 2/3

=              4/9

(1/2 + 1/3) x 1/5

=   5/6        x 1/5

=               1/6

(1/2 + 1/3) x 1/5

= (1/2 x 1/5) + (1/3 x 1/5)

=       1/10    +        1/15

=                 1/6

4A6?

Đây bạn nhé

cách1\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\)=\(\frac{8}{15}\times\frac{5}{6}\)=\(\frac{4}{9}\)cách2 =\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\)\(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{40}{90}\)=\(\frac{4}{9}\)

cách1\( \left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{1}{5}\)= \(\frac{5}{6}\times\frac{1}{5}\)=\(\frac{1}{6}\)cách2\( \left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{1}{5}\)=\(\frac{1}{2}\times\frac{1}{5}+\frac{1}{3}\times\frac{1}{5}\)=\(\frac{1}{10}+\frac{1}{15}\)=\(\frac{25}{150}\)=\(\frac{1}{6}\)

cách1\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\)=\(\frac{2}{3}\times\left(\frac{4}{5}\times\frac{5}{6}\right)\)=\(\frac{2}{3}\times\frac{2}{3}\)=\(\frac{4}{9}\) cách 2 \(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\)=\(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)

cách1\(\left(1\times2+\frac{1}{3}\right)\times\frac{1}{5}\)=\(\frac{7}{3}\times\frac{1}{5}\)=\(\frac{7}{15}\) cách2\(\left(1\times2+\frac{1}{3}\right)\times\frac{1}{5}\)=\(1\times\left(2+\frac{1}{3}\right)\times\frac{1}{5}\)=\(1\times\frac{7}{3}\times\frac{1}{5}\)=\(\frac{7}{3}\times\frac{1}{5}\)=\(\frac{7}{15}\)

/HT\

a)5.x.(1-2.x)-3.x.(x+18)=0
   x.[5.(1-2.x)-3.(x+18)] =0
   x.[5- 10.x -3.x -54]    =0
   x.[-13.x-49]              =0
=>x=0 hoặc -13.x-49=0
    x=0 hoặc      x     = -49/13

b)5.x-3{4.x-2[4.x-3(5.x-2)]}=182
   5.x-3{4.x-2[-11.x+6]}     =182
   5.x-3{26.x-12}               =182
   5.x-78.x+36                  =182
   x.(5-78)                        = 146
   -73.x                            =146
    x                                = 2