a ) \(x+7\frac{4}{5}=9\frac{7}{15}\)

\(x+\frac{39}{5}=\frac{142}{15}\)

\(x=\frac{142}{15}-\frac{39}{5}\)

\(x=\frac{5}{3}\)

b ) \(x-4\frac{9}{11}=\frac{2121}{2222}\)

\(x-\frac{53}{11}=\frac{21}{22}\)

\(x=\frac{21}{22}+\frac{53}{11}\)

\(x=\frac{127}{22}\)

ai đúng trả lời trước mik sẽ kick cho ^^

câu a kêt quả bằng 

x+ 117/15=142/15

x=142/15+117/15

x=25/15=3/5

kết quả câu b bằng 

x-10706/2222=2121/2222

x=2121/2222+10706/2222

x=12824/2222

mình tra rloiw fsong rùi bn k nhé

\(x+7\frac{4}{5}=9\frac{7}{15}\)

\(x=9\frac{7}{15}-7\frac{4}{5}\)

\(x=9\frac{7}{15}-7\frac{12}{15}\)

\(x=-2\frac{1}{3}\)

\(x-4\frac{9}{11}=\frac{2121}{2222}\)

\(x-4\frac{9}{11}=\frac{101.21}{101.22}\)

\(x-\frac{53}{11}=\frac{21}{22}\)

\(x=\frac{21}{22}+\frac{53}{11}\)

\(x=\frac{127}{22}=5\frac{17}{22}\)

\(x+7\dfrac{4}{5}=9\dfrac{7}{15}\)

\(=>x+\dfrac{39}{5}=\dfrac{142}{15}\)

\(=>x=\dfrac{142}{15}-\dfrac{39}{5}=\dfrac{142}{15}-\dfrac{117}{15}\)

\(=>x=\dfrac{25}{15}=\dfrac{5}{3}\)

___________

\(x-4\dfrac{9}{11}=\dfrac{2121}{2222}\)

\(=>x-\dfrac{53}{11}=\dfrac{21}{22}\)

\(=>x=\dfrac{21}{22}+\dfrac{53}{11}=\dfrac{21}{22}+\dfrac{106}{22}\)

\(=>x=\dfrac{127}{22}\)

\(x+7\dfrac{4}{5}=9\dfrac{7}{15}\)

\(x=9\dfrac{7}{15}-7\dfrac{4}{5}\)

\(x=\left(9-7\right)+\left(\dfrac{7}{15}-\dfrac{4}{5}\right)\)

\(x=2\dfrac{-1}{3}=\dfrac{5}{3}\)

\(x=\dfrac{2121:101}{2222:101}+4\dfrac{9}{11}\)

\(x=\dfrac{21}{22}+4\dfrac{18}{22}\)

\(x=\dfrac{21+4\cdot22+18}{22}=\dfrac{127}{22}\)

\(a.\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}b.\frac{3}{5}\cdot\frac{7}{9}+\frac{3}{5}\cdot\frac{2}{9}=\frac{3}{5}\cdot\left(\frac{7}{9}+\frac{2}{9}\right)=\frac{3}{5}\cdot1=\frac{3}{5}\)

\(a)x+30\%x=-1,31\)

\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)

\(\Leftrightarrow10x+3x=-13,1\)

\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)

\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)

\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)

\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)

\(\Leftrightarrow\frac{6x-3}{2}=9\)

\(\Leftrightarrow6x-3=18\)

\(\Leftrightarrow x=\frac{7}{2}\)

\(c)\frac{1}{2}x-\frac{3}{4}=\frac{14}{9}.\frac{3}{7}\)

\(\Leftrightarrow\frac{x}{2}-\frac{3}{4}=\frac{2}{3}\)

\(\Leftrightarrow\frac{x}{2}=\frac{17}{12}\)

\(\Leftrightarrow12x=34\Leftrightarrow x=\frac{17}{6}\)

\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)

\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)

\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)

\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)

\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)

\(\Rightarrow-1\le x< 6\)

\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)

Bài b tương tự

bạn ơi bạn giải câu b được ko. mk ko biết làm câu b

1)

a)

\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)

\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)

\(\frac{-20}{5}< x< \frac{-3}{10}\)

\(\frac{-40}{10}< x< \frac{-3}{10}\)

\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)

\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)

\(\frac{25}{3}< x< \frac{-4}{7}.\frac{1}{1}\)

\(\frac{-25}{3}< x< \frac{-4}{7}\)

\(\frac{-175}{21}< x< \frac{-12}{21}\)

\(\Rightarrow Z\in\left\{-13;-14;-15;-16;...;-174\right\}\)

2)

a)

\(\left(\frac{9}{10}-\frac{15}{16}\right).\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)

\(=\left(\frac{72}{80}-\frac{75}{80}\right).\left(\frac{25}{60}-\frac{44}{60}-\frac{21}{60}\right)\)

\(=\frac{-3}{80}.\frac{-40}{60}\)

\(=\frac{-1}{-2}.\frac{-1}{-20}\)

\(=\frac{1}{40}\)

\(A=\left(-\frac{5}{11}\right).\frac{7}{15}+\frac{11}{-5}.\frac{30}{33}\)

\(A=-\frac{7}{33}+-2\)

\(A=-\frac{73}{33}\)

[ A] = -2

làm đc hết rùi phần b thui

\(D=\frac{1}{3}-\left[\left(-\frac{5}{4}\right)-\left(\frac{1}{4}+\frac{3}{8}\right)\right]\)

\(D=\frac{1}{3}-\left[\left(-\frac{5}{4}\right)-\frac{5}{8}\right]\)

\(D=\frac{1}{3}-\left(-\frac{15}{8}\right)\)

\(D=\frac{53}{24}\)

\(\left[D\right]=2\)