bài 1:
\(\frac{288}{72}=\frac{?}{24}=\frac{16}{?}\frac{?}{18}\)
\(\frac{7}{9}\)= \(\frac{35}{ }\)= \(\frac{ }{180}\)= \(\frac{77}{ }\)
\(\frac{288}{72}\)= \(\frac{ }{24}\)= \(\frac{16}{ }\)= \(\frac{ }{18}\)
7/9 = 35/45 = 140/180 = 77/99
288/72 = 96/24 = 16/4 = 112/18
k đúng cho mình nha bn
\(\frac{7}{9}\)=\(\frac{35}{45}\)=\(\frac{140}{180}\)=\(\frac{77}{99}\)
\(\frac{288}{72}\)=\(\frac{96}{24}\)=\(\frac{16}{4}\)=\(\frac{112}{18}\)
Bài 1:
a, \(\frac{2}{5}.\frac{1}{3}-\frac{2}{15}:\frac{1}{5} +\frac{3}{5}.\frac{1}{3}\)
b, \(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
c,\(\left(4-\frac{5}{12}\right):2+\frac{5}{24}\)
a) -1/3
b)8/3
c)2
k cho mk nha mk cảm ơn nhiều
từ tỉ lệ thức\(\frac{12}{18}\)=\(\frac{24}{36}\)=sosanh chung với các tỉ số \(\frac{12}{18}\)và\(\frac{36}{54}\)
\(\frac{12+24+72}{18+36+108}\) ; \(\frac{12-24+72}{18-36+108}\)
\(\dfrac{12}{18}=\dfrac{24}{36}=\dfrac{72}{108}=\dfrac{12+24+72}{18+36+108}=\dfrac{12-24+72}{18-36+108}\)
\(\frac{-5}{x}=\frac{y}{16}=\frac{-18}{72}\)
-18/72=-2/8=-4/16. Suy ra x=-4
-5/x=-2/8.Suy ra -5.8=-2.x
-40=-2x
x=20
\(\frac{9+\frac{9}{11}+\frac{18}{23}-\frac{27}{37}}{8+\frac{8}{11}+\frac{16}{23}-\frac{24}{37}}-\frac{2+\frac{16}{29}-\frac{24}{13}-\frac{32}{11}}{3+\frac{24}{29}-\frac{36}{13}-\frac{48}{11}}\)
Thuc hien phep tinh
Đặt \(A=\frac{9+\frac{9}{11}+\frac{18}{23}-\frac{27}{37}}{8+\frac{8}{11}+\frac{16}{23}-\frac{24}{37}}-\frac{2+\frac{16}{29}-\frac{24}{13}-\frac{32}{11}}{3+\frac{24}{29}-\frac{36}{13}-\frac{48}{11}}\)\(=\frac{9\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}{8\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}-\frac{2\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}{3\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}\)
\(=\frac{9}{8}-\frac{2}{3}\)(do \(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37};1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\ne0\))
\(=\frac{27}{24}-\frac{16}{24}=\frac{11}{24}.\)
Vậy A = \(\frac{11}{24}.\)
Rut gon: \(A=\frac{9+\frac{9}{11}+\frac{18}{23}-\frac{27}{27}}{8+\frac{8}{11}+\frac{16}{23}-\frac{24}{37}}-\frac{2+\frac{16}{29}-\frac{24}{13}-\frac{32}{11}}{3+\frac{24}{29}-\frac{36}{13}-\frac{48}{11}}\)
\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}+\frac{16}{24}+\frac{2}{3}\)
=\(\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(=\frac{8}{3}\)
\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(=\frac{9}{27}+\frac{8}{24}+\frac{18}{27}+\frac{16}{24}+\frac{2}{3}\)
\(=\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(=\left[\frac{1}{3}+\frac{2}{3}\right]+\left[\frac{1}{3}+\frac{2}{3}\right]+\frac{2}{3}\)
\(=1+1+\frac{2}{3}=2+\frac{2}{3}=\frac{8}{3}\)
\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(\frac{2}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(\frac{8}{3}\)
\(2+\frac{1}{8}+\frac{1}{32}+\frac{1}{72}+\frac{1}{128}+\frac{1}{200}+\frac{1}{288}< \frac{9}{4}\)
P/s làm ơn mai em kiểm tra òi
Tìm các số x, y biết
a) \(x=-\frac{18}{24}+\frac{15}{21}\)
b) \(\frac{-1}{3}-x=\frac{1}{2}-\frac{1}{-4}\)
c) \(\frac{-5}{x}=\frac{-y}{8}=\frac{18}{72}\)
Help me, please!!!
\(\frac{-5}{x}=\frac{-y}{8}=\frac{18}{72}\)
\(\Leftrightarrow\frac{-5}{x}=\frac{-y}{8}=\frac{1}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}-\frac{5}{x}=\frac{1}{4}\\-\frac{y}{8}=\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-5.4:1\\-y=8.1:4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-20\\-y=2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-20\\y=-2\end{cases}}}\)
vậy x=-20 và y=-2
\(-\frac{1}{3}-x=\frac{1}{2}-\frac{1}{-4}\)
\(-\frac{1}{3}-x=\frac{1}{2}-\frac{-1}{4}\)
\(-\frac{1}{3}-x=\frac{2}{4}-\frac{-1}{4}\)
\(-\frac{1}{3}-x=\frac{3}{4}\)
\(x=-\frac{1}{3}-\frac{3}{4}\)
\(x=-\frac{4}{12}-\frac{9}{12}\)
\(x=-\frac{13}{12}\)
\(x=-\frac{18}{24}+\frac{15}{21}\)
\(x=-\frac{3}{4}+\frac{5}{7}\)
\(x=-\frac{21}{28}+\frac{20}{28}\)
\(x=-\frac{1}{28}\)