Math: Easy
8 + 6 =
3 + 9 =
7 + 4 =
9 + 2 =
Tính
a)\(2^9×9^2+3^4×6^3:10^6\)
b)\(9^8:9^7+2^{18}:3^4+6×5\)
\(\left(\dfrac{2}{3}+\dfrac{2}{13}+\dfrac{2}{11}+\dfrac{2}{6}\right)\) \(\left(\dfrac{5}{4}+\dfrac{5}{7}+\dfrac{5}{6}+\dfrac{5}{11}\right)\)
___________________ X ___________________
\(\left(\dfrac{4}{3}+\dfrac{4}{13}+\dfrac{4}{11}+\dfrac{4}{6}\right)\) \(\left(\dfrac{9}{4}+\dfrac{9}{7}+\dfrac{9}{6}\dfrac{9}{11}\right)\)
ta có
\(2.\left(\dfrac{1}{3}+\dfrac{1}{13}+\dfrac{1}{11}+\dfrac{1}{6}\right)\) \(5.\left(\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{1}{6}+\dfrac{1}{11}\right)\)
_______________________ X ________________________
\(4.\left(\dfrac{1}{3}+\dfrac{1}{13}+\dfrac{1}{11}+\dfrac{1}{6}\right)\) \(9.\left(\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{1}{6}\dfrac{1}{11}\right)\)
= \(\dfrac{2}{4}X\dfrac{5}{9}\)= \(\dfrac{10}{36}\)= \(\dfrac{5}{18}\)
bài 1 : tính phân số:
a) \(\frac{5}{7}+\frac{4}{9}=?;\frac{4}{5}-\frac{2}{3}=?;\frac{9}{11}+\frac{3}{8}=?;\frac{16}{25}-\frac{2}{5}=?\)=?
b)\(5+\frac{3}{5}=?;10-\frac{9}{16}=?;\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=?\)
c)\(\frac{5}{7}+\frac{7}{6}=?;\frac{7}{12}+\frac{17}{18}=?;\frac{9}{8}+\frac{15}{32}=?;4+\frac{35}{45}=?\)
d)\(\frac{11}{4}-\frac{15}{16}=?;\frac{5}{6}-\frac{5}{8}=?;\frac{196}{64}-2=?;3-\frac{13}{9}=?\)
e)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2=?;3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}=?\)
a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)
\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)
Tính:
9 + 1 = … | 8 + 2 = … | 7 + 3 = … | 6 + 4 = … |
1 + 9 = … | 2 + 8 = … | 3 + 7 = … | 4 + 6 = … |
9 – 1 = … | 8 – 2 = … | 7 – 3 = … | 6 – 4 = … |
9 – 9 = … | 8 – 8 = … | 7 – 7 = … | 6 – 6 = … |
Lời giải chi tiết:
9 + 1 = 10 | 8 + 2 = 10 | 7 + 3 = 10 | 6 + 4 = 10 |
1 + 9 = 10 | 2 + 8 = 10 | 3 + 7 = 10 | 4 + 6 = 10 |
9 – 1 = 8 | 8 – 2 = 6 | 7 – 3 = 4 | 6 – 4 = 2 |
9 – 9 = 0 | 8 – 8 = 0 | 7 – 7 = 0 | 6 – 6 = 0 |
1+5+1+=?
1+3+8=?
2+4+9=?
9+2+5+3+7+8+4+7+4+7+2+4+2+9+6+4+65+6+7+4+6+4+6+3+7+4+8+5+9+08+87+1+2+3+4+2+3+2+5+6+767+5+75+6+4+6+5+66+5+7+546+46+43+6+3+6+4+6+7+8878+68+68+6+7+9+9
\(9+2+5+3+7+8+4+2+9+6+4+65+6+7+4+6+3+7+4+8+5+9+08+87+1+2+3+4+2+3+2+5+6+767+5+75+6+4+6+5+66+5+7+546+46+43+6+3+6+4+6+7+8878+68+68+6+7+9+9=10961\)
Tính
\(\frac{1+2+3+4+5+6+7+8+9\cdot0}{1+2+3+4+5+6+7+8+9\cdot0}\)
\(\frac{1+2+3+4+5+6+7+8+9.0}{1+2+3+4+5+6+7+8+9.0}\)
= 1
( Vì tử và mẫu đều giống nhau )
Các bn có nhầm ko vậy.khi nào rảng học lại phần phân số đi
Tính:
a)\(2^3.7+3^2.6=\)
b)\(7^3-6^3-5^3=\)
c)\(6^4-2^5.3^3=\)
d)\(\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right)\left(2^4-4^2\right)=\)
a)56+48=104
b)343-216-125=2
c)1296-32*27=1296-864=432
d)=0(vì các số *với 0 đều =0(\(2^4\)-4\(^2\)=0)
a) \(2^3.7+3^2.6=8.7+9.6\)
\(=56+54\)
\(=110\)
b) \(7^3-6^3-5^3=343-216-125\)
\(=2\)
c) \(6^4-2^5.3^3=1296-32.27\)
\(=1296-864\)
\(=432\)
d) \(\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right)\left(2^4-4^2\right)\)
\(=\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right).0\)
\(=0\)
NHỚ K CHO MÌNH NHÉ !
Tính:
8 + 1 = 7 + 2 = 6 + 3 = 5 + 4 =
1 + 8 = 2 + 7 = 3 + 6 = 4 + 5=
9 - 8 = 9 - 7 = 9 - 6 = 9 - 5 =
9 - 1 = 9 - 2 = 9 - 3 = 9 - 4 =
8 + 1 = 9 7 + 2 = 9 6 + 3 = 9 5 + 4 = 9
1 + 8 = 9 2 + 7 = 9 3 + 6 = 9 4 + 5= 9
9 - 8 = 1 9 - 7 = 2 9 - 6 = 3 9 - 5 = 4
9 - 1 = 8 9 - 2 = 7 9 - 3 = 6 9 - 4 = 5
1+2+3+4+5+6+7+8+9+0+1+2+3+4+5+6+7+8+9+9+8+7+6+5+4+3+2+1+1+34+4+6+7+8+97+6+4+3+32+4+57+7+8+8+6+65+4+3+3+46+7+8+7+64+3+3+5+68+8+6+3+3+5+78+8+6+54+5+7+8+852+3+5+89+8+5+45+7×9×9×9×9×9×9×9×9×9×9×9×8×8×7×9×9×7×7×87×7×8×7×7×8×7×7×8