112 + 134 + x = 946 - 269 x - 123 = 400 + 56 - 75 962 - x = 869 - 28
Tìm số thay cho dấu x
Tìm x, biết:
a. 113 + 142 + x = 999 – 103
b. x – 124 = 400 + 56
c. 963 – x = 869 – 28 : 4
a. 113 + 142 + x = 999 – 103
255 + x = 896
x = 896 – 255
x = 641
b. x – 124 = 400 + 56
x – 124 = 456
x = 456 + 124
x = 580
c. 963 – x = 869 – 28 : 4
963 – x = 869 – 7
963 – x = 862
x = 963 – 862
x = 101
Tìm x ∈ ℕ , biết:
a ) 5 6 + 1 6 ≤ x ≤ 13 4 + 14 8 b ) − 5 6 + 8 3 + 29 − 6 ≤ x ≤ − 1 2 + 2 + 5 2 c ) 79 15 + 7 5 + − 8 3 ≤ x ≤ 10 3 + 15 4 + 23 12
a) 1 ≤ x ≤ 5 => x ∈ {1;2;3;4;5}
b) -3 ≤ x ≤ 4 =>x ∈ {0;1;2;3;4}
c) 4 ≤ x ≤ 9 => x ∈ {4;5;6;7;8;9}
Tìm x thuộc N, biết:
a ) 5 6 + 1 6 ≤ x ≤ 13 4 + 14 8 b ) − 5 6 + 8 3 + 29 − 6 ≤ x ≤ − 1 2 + 2 + 5 2 c ) 79 15 + 7 5 + − 8 3 ≤ x ≤ 10 3 + 15 4 + 23 12
Tìm x thuộc Z, biết:
a) 5 6 + 1 6 ≤ x ≤ 13 4 + 14 8
b) − 5 6 + 8 3 + 29 − 6 ≤ x ≤ − 1 2 + 2 + 5 2
c) 79 15 + 7 5 + − 8 3 ≤ x ≤ 10 3 + 15 4 + 23 12
a) 5 6 + 1 6 ≤ x ≤ 13 4 + 14 8 ⇔ 1 ≤ x ≤ 5 ⇔ x ∈ 1 ; 2 ; 3 ; 4 ; 5
b) − 5 6 + 8 3 + 29 − 6 ≤ x ≤ − 1 2 + 2 + 5 2 ⇔ − 3 ≤ x ≤ 4 ⇔ x ∈ − 3 ; − 2 ; − 1 ; 0 ; 1 ; 2 ; 3 ; 4
c) 79 15 + 7 5 + − 8 3 ≤ x ≤ 10 3 + 15 4 + 23 12 ⇔ 4 ≤ x ≤ 9 ⇔ x ∈ 4 ; 5 ; 6 ; 7 ; 8 ; 9
BÀI 3: TÍNH BẰNG CÁCH THUẬN TIỆN NHẤT
245 x 11 + 11 x 365 78 x 75 + 75 x 89 + 75 x 123 2 x 250 x 50 x 8
(76 : 7) x 4 (372 x 15) x 9 (56 x 23 x 4) : 7
1. Tích sau có tận cùg là chữ số nào?
a) 103 x 113 x 123 x ... 2013 x 2023
b) 49 x 69 x 89 x ... x 869 x 889
tìm số tự nhiên x, biết:
2/1.5+2/5.9+2/9.13+...+2/x.(x+4) = 56/113
(lưu ý: dấu chấm ở giữa các mẫu số thay cho dấu nhân). Giup mình với nha. ai xong trước mình tích cho
Ta có \(\dfrac{2}{1\cdot5}+\dfrac{2}{5\cdot9}+\dfrac{2}{9\cdot13}+...+\dfrac{2}{x\left(x+4\right)}=\dfrac{56}{113}\)
\(\dfrac{1}{2}\left(\dfrac{4}{1\cdot5}+\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}+...+\dfrac{4}{x\left(x+4\right)}\right)=\dfrac{56}{113}\)
\(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}+...+\dfrac{1}{x}-\dfrac{1}{x+4}=\dfrac{56}{113}:\dfrac{1}{2}\)
\(1-\dfrac{1}{x+4}=\dfrac{112}{113}\)
\(\dfrac{1}{x+4}=1-\dfrac{112}{113}=\dfrac{1}{113}\)
x + 4 = 113 ⇒ x = 109
\(\dfrac{2}{1.5}+\dfrac{2}{5.9}+...+\dfrac{2}{x\left(x+4\right)}=\dfrac{56}{113}\)
Xét: \(A=\dfrac{2}{1.5}+\dfrac{2}{5.9}+...+\dfrac{2}{x\left(x+4\right)}\)
\(A=\dfrac{1}{2}.\left(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+...+\dfrac{1}{x-4}-\dfrac{1}{x}+\dfrac{1}{x}-\dfrac{1}{x+4}\right)\)
\(A=\dfrac{1}{2}.\left(1-\dfrac{1}{x+4}\right)\)
Với \(A=\dfrac{56}{113}\) thì
\(\dfrac{1}{2}.\left(1-\dfrac{1}{x+4}\right)=\dfrac{56}{113}\)
\(\left(1-\dfrac{1}{x+4}\right)=\dfrac{112}{113}\)
\(\dfrac{1}{x+4}=\dfrac{1}{113}\)
\(x=109\)
\(\dfrac{2}{1.5}\) + \(\dfrac{2}{5.9}\) + \(\dfrac{2}{9.13}\)+...+ \(\dfrac{2}{x\left(x+4\right)}\) = \(\dfrac{56}{113}\)
(\(\dfrac{2}{1.5}+\dfrac{2}{5.9}+\dfrac{2}{9.13}+....+\dfrac{2}{x\left(x+4\right)}\) ) \(\times\) 2 = \(\dfrac{56}{113}\) \(\times\) 2
\(\dfrac{4}{1.5}\) + \(\dfrac{4}{5.9}\) +\(\dfrac{4}{9.13}\)+...+ \(\dfrac{4}{x\left(x+4\right)}\) = \(\dfrac{112}{113}\)
\(\dfrac{1}{1}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{9}\) - \(\dfrac{1}{13}\) +...+ \(\dfrac{1}{x}\) - \(\dfrac{1}{x+4}\) = \(\dfrac{112}{113}\)
1 - \(\dfrac{1}{x+4}\) = \(\dfrac{112}{113}\)
\(\dfrac{1}{x+4}\) = 1 - \(\dfrac{112}{113}\)
\(\dfrac{1}{x+4}\) = \(\dfrac{1}{113}\)
\(x\) + 4 = 113
\(x\) = 113 - 4
\(x\) = 109
cho x+5:2 x khác 28 và -28
tìm x sao cho A>2
\(A>2\Leftrightarrow\dfrac{x+5}{2}>2\Rightarrow x+5>4\Rightarrow x>-1\)
cho A= \(\dfrac{x+5}{-2}\) x khác +-28
tìm x sao cho A>2
Để A>2\(\Rightarrow\dfrac{x+5}{-2}>2\Rightarrow x+5>-4\Rightarrow x>-9\)