( 2/3-1)(2/5-1)(2/7-1)....(2/2001-1)
D= 2 3/4 . ( -0,4) - 1 3/5 . 2,75 + ( -1,2) : 4/11
E= (23 . 5 . 7 ) . ( 52 . 73)
__________________________
( 2 .5 .72 ) 2
- So sánh biểu thức:
A= 2000/ 2001 + 2001/2002
B= 2000+2001/ 2001+2002
a/ 1 13/5 . ( 0,5)2 . 3 + ( 8/5 - 1 19/60) : 1 23/24
b/ 112 / 200 + 0,415) : 0,01
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1/2 - 37,25 + 3 1/6
a) 1 + 2+ 3+ 4 +....+ n b) 2+4+6+8+...+2.n
c) 1+3+5+7+...+(2.n +1) d) 1+4+7+10+..+2005
e) 2+5+8+...+2006 f) 1+5+9+..+2001
a) 1 - 2 - 3 + 4 +5 - 6 - 7 + ..... + 2001 - 2002 -2003 + 2004
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ..... + 2001 + 2002 - 2003 - 2004
a) \(1-2-3+4+5-6-7+...+2001-2002-2003+2004\)
\(=\left(1-2-3+4\right)+\left(5-6-7+8\right)+...+\left(2001-2002-2003+2004\right)\)
\(=0+0+...+0=0\)
b) \(1+2-3-4+5+6-7-8+...+2001+2002-2003-2004\)
\(=\left(1+2-3-4\right)+\left(5+6-7-8\right)+...+\left(2001+2002-2003-2004\right)\)
\(=\left(-4\right)+\left(-4\right)+...+\left(-4\right)\)
\(=\left(-4\right)\cdot501=\left(-2004\right)\)
1+(-2)+3+(-4)+....+2001+(-2002)
1+(-3)+5+(-7)+....+(-1999)+2001
1+(-2)+3+(-4)+...+2001+(-2002)
=[1+(-2)]+[3+(-4)]+...+[2001+(-2002)]
=(-1)+(-1)+...+(-1) (có 1001 số hạng)
=(-1).1001
=-1001
Bài 1:D=1000+998+996+...+2-999-997-995-1
E=100+98+96+94+...+2-97-95-93-...-1
G=1-3+5-7+...+2005-2007+2009
H=1-3+5-7+...+2001-2003+2005
I=1+0-3-4+5+6-7-8+9+...-299+300+301+302
K=1-2+3-4+...+2017-2018+2019
L=1-2-3+4+5-6-7+...+1997+1998-1999+2000+2001
M=1-2+3-4+5-6+...+99-100+101
Bài 2:A=1+2+3+...+x
B=2+4+6+...+2.x
C=1+3+5+7+...+(2x-1)
S1= 1 + (-2) + 3 + (-4) +...+ 2001 +(-2002)
S2= 1 + (-3) = 5 = (-7) = ...=(-1999) + 2001
Bài 2:tính tổng
a/ S1 = 1 + (-2) + 3 + (-4) + .. . + 2001 + ( -2002)
b/ S2 = 1 + (-3) + 5 + (-7) + .. . + (-1999) + 2001
c/ S 3 = 1 + (-2) + (-3) + 4 + 5 + (-6) + (-7) + 8 + .. . + 1997 + (-1008) + (-1999) + 2000
a/ S1 = 1 + (-2) + 3 + (-4) + .. . + 2001 + ( -2002)
S1 = [1 + (-2)] + [3 + (-4)] + .. . + [2001 + ( -2002)]
S1 = (-1) + (-1) + ... + (-1)
2002 : 2 = 1001
S1 = (-1) . 1001
S1 = (-1001)
b/ S2 = 1 + (-3) + 5 + (-7) + .. . + (-1999) + 2001
S2 = [1 + (-3)] + [5 + (-7)] + .. . + [1997 + (-1999)] + 2001
S2 = (-2) + (-2) + ... + (-2) + 2001
(1991 - 1) : 2 + 1 = 996 : 2 = 498
S2 = (-2) . 498 + 2001
S2 = (-996) + 2001
S2 = 1005
c/ S3 = 1 + (-2) + (-3) + 4 + 5 + (-6) + (-7) + 8 + .. . + 1997 + (-1998) + (-1999) + 2000
S3 = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... + 1997 + 1998 - 1999 - 2000
S3 =(1 + 2 - 3 - 4)+(5 + 6 - 7 - 8)+ ... +(1997 + 1998 - 1999 - 2000)
S3 = (-4) + (-4) + ... + (-4)
2000 : 4 = 500
S3 = (-4) . 500
S3 = -2000
1 S=1-3+5-7+....+2001-2003
2 S=1+3-5-7+9+11-.....-405-407
3 S=2-5+8-11+...110-113
a) 1−3+5−7+...+2001−2003+2005=(−2)+(−2)+...+(−2)+2005 (501 số −2) =501.(−2)+2005=1003
Tính tổng :
a) S1 = 1 + (-2) + 3 + (-4) + ... + 2001 + (-2002)
b) S2 = 1 + (-3) + 5 = (-7) + ... + (-1999) + 2001
c) S3 = 1 + (-2) + (-3) + 4 + 5 + (-6) + (-7) + 8 + ... + 1997 + (-1008) + (-1999) + 2000
hãy tính tổng S , biết : S = 1+2+ 3+....2000+2001+2002