MÌNH ĐANG CẦN GẤP

5.[3/4-2/3x]-13/4=-2{(5/4)²-5/2.1/4+(1/16)²

5.[3/4-2/3x]-13/4=2{25/16-5/8+1/256}

........................=2{400/256-160/250+1/256}

........................=2.241/256

........................=241/128

5.[3/4-2/3x]=241/128+13/4

5.[3/4-2/3x]=241/128+416/128

[3/4-2/3x]=657/128:5

[3/4-2/3x]=657/640

vậy 3/4-2/3x=657/640 và 3/4-2/3x=-657/640

th1:3/4-2/3x va th2:3/4-2/3x=-657/640

còn lại bạn chỉ cần tính kết quả mà dấu[..] là giá tri tuyệt đối đó

2,3 x 5 + 2,3 x 4 + 2,3

= 2,3 x ( 5 + 4 + 1 )

= 2,3 x 10

=23

4,3 x 4 + 0,43 x 10 - 4,3 x 2 

= 4,3 x 4 + 4,3 - 4,3 x 2 

= 4,3 x ( 4 + 1 - 2 ) 

= 4,3 x 3

= 12,9

câu còn lại tương tự nha

    2,3 x 5 + 2,3 x 4 + 2,3 

=  2,3 x ( 5+4+1 )

=  2,3 x 10

=  23

    4,3 x 4 + 0,43 x10 - 4,3 x 2

=  4,3 x 4 + 4,3 - 4,3 x 2

=  4,3 x ( 4+1-2)

=  4,3 x 1

= 4,3

2,3 x 5 + 2,3 x 4 + 2,3

=2,3 x ( 5+ 4 +1 )

= 2,3 x 10 

= 23

4,3 x 4 + 0,43 x 10 - 4,3 x2

= 4,3 x 4 + 4,3 - 4,3 x 2

=4,3 x ( 4 + 1 -2 )

= 12.9

a,3,25+0,9-x=0,97

4,15-x=0,97

x=4,15-0,97

x=3,18

b,4,4-9,2+x=1,2

-4,8+x=1,2

x=1,2-(-4,8)

x=6

c,7/5+x-2/5=4

7/5+x=4+2/5

7/5+x=22/5

x=22/5-7/5

x=15/5

x=3

d,1 3/4+x-7/8=5

7/4+x-7/8=5

7/4+x=5+7/8

7/4+x=47/8

x=47/8-7/4

x=47/8-14/8

x=33/8

a,3,25+0,9-x=0,97

4,15-x=0,97

x=4,15-0,97

x=3,18

b,4,4-9,2+x=1,2

-4,8+x=1,2

x=1,2-(-4,8)

x=6

c,7/5+x-2/5=4

7/5+x=4+2/5

7/5+x=22/5

x=22/5-7/5

x=15/5

x=3

d,1 3/4+x-7/8=5

7/4+x-7/8=5

7/4+x=5+7/8

7/4+x=47/8

x=47/8-7/4

x=47/8-14/8

x=33/8

(3,25 -2/3x):(-7/4)=-3 tim x

x - 5 / 6 = 12 / 7

       x    = 12 / 7 + 5 / 6

       x    = 107 / 42

x + 4 / 5 = 8 / 3

       x     = 8 / 3 - 4 / 5

       x     = 28 / 15

x * 3 / 9 = 11 / 7 - 3 / 4

x * 3 / 9 = 23 / 28

       x    = 23 / 28 : 3 / 9

       x    = 69 / 28

5 / 9 : x = 1 / 3 + 2 / 5

5 / 9 : x = 11 / 15

          x = 5 / 9 : 11 / 15

          x = 25 / 33

\(1\frac{3}{4}-x=\frac{3}{8}\)

              x    = 11 / 8

15 , 21 - x = 5 , 6 + 1 , 2

15 , 21 - x = 6 , 8

              x = 15 , 21 - 6 , 8

              x = 8 , 41

C1 : ( 6 , 75 + 3 , 25 ) * 42

= 10 * 42

= 420

C 2 : ( 6 , 75 + 3 , 25 ) * 42

= 6,75 * 42 + 3,25 * 42

= 283 , 5 + 136 , 5

= 4200

C 1 : ( 9 , 6 - 4 , 2 ) * 3 , 6

= 5 , 4 * 3 , 6

= 19 , 44

C 2 : ( 9 , 6 - 4 , 2 ) * 3 , 6

= 9 , 6 * 3 , 6 - 4 , 2 * 3 , 6

= 34 , 56 - 15 , 12

= 19 , 44

Bài 2:

a,4x25x0,25x\(\frac{1}{5}\) x \(\frac{1}{2}\) x 2

 =4x25x0,25x0,2x0,5x2

 =(4x0,25)+(25x0,2)+(0,5x2)

 =      1     +     5             1

 =7

X + 1/2 + X + 1/4 + X + 1/8 + X + 1/8 +X +1/16 

= X + 8/16 + X + 4/16 + X + 2/16 + X + 2/16 +X + 1/16 

= X + ( 8/16 + 4/16 + 2/16 + 2/16 )  + X +1/16 

= X + 1 + X + 1/16 

= X + ( 1 + 1/16 ) 

=  X + 1 VÀ 1/16 

b, 3,25+4,75+6,25+...+19,75+21,15

  Khoảng cách của dãy số trên là:

   4,75=3,25=1,5

Dãy số trên là dãy số cách đều 1,5 

Số số hạng dãy trên là :áp dụng công thức tính SSH ( SC-SĐ):k/c+1

Tổng ( SĐ+SC)XSSH:2

\(1,\Leftrightarrow x\left(x-9\right)=0\Leftrightarrow\left[{}\begin{matrix}x=9\\x=0\end{matrix}\right.\\ 2,\Leftrightarrow x^2-4x-x^2=7\Leftrightarrow-4x=7\Leftrightarrow x=-\dfrac{7}{4}\\ 3,\Leftrightarrow3x+2x-10=5\Leftrightarrow5x=15\Leftrightarrow x=3\\ 4,\Leftrightarrow\left(5x-1\right)\left(5x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=-\dfrac{1}{5}\end{matrix}\right.\\ 5,\Leftrightarrow\left(x-2\right)\left(3x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{5}{3}\end{matrix}\right.\\ 6,\Leftrightarrow\left(x-7\right)\left(3x+4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{4}{3}\end{matrix}\right.\)

\(7,\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\\ 8,\Leftrightarrow\left(x-4\right)\left(10x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{5}\\x=4\end{matrix}\right.\\ 9,\Leftrightarrow2x^2-5x-2x^2=0\Leftrightarrow x=0\\ 10,\Leftrightarrow2x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\\ 11,\Leftrightarrow\left(4x-3\right)\left(3-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{3}{2}\end{matrix}\right.\\ 12,\Leftrightarrow2x^2-10x-2x^2=3\Leftrightarrow-10x=3\Leftrightarrow x=-\dfrac{3}{10}\)

\(1,\Leftrightarrow x\left(x-9\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\\ 2,\Leftrightarrow x^2-4x-x^2=7\\ \Leftrightarrow-4x=7\\ \Leftrightarrow x=\dfrac{-7}{4}\\ 3,\Leftrightarrow3x+2x-10=5\\ \Leftrightarrow5x=15\\ \Leftrightarrow x=3\\ 4,\Leftrightarrow\left(5x-1\right)\left(5x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=-\dfrac{1}{5}\end{matrix}\right.\)

\(5,\Leftrightarrow\left(x-2\right)\left(3x-5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{5}{3}\end{matrix}\right.\\ 6,\Leftrightarrow\left(3x+4\right)\left(x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{4}{3}\\x=7\end{matrix}\right.\\ 7,\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

\(8,\Leftrightarrow10x\left(x-4\right)+2\left(x-4\right)=0\\ \Leftrightarrow\left(x-4\right)\left(10x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{1}{5}\end{matrix}\right.\\ 9,\Leftrightarrow2x^2-5x-2x^2=0\\ \Leftrightarrow-5x=0\\ \Leftrightarrow x=0\\ 10,\Leftrightarrow2x\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

\(11,\Leftrightarrow\left(2x-3\right)\left(4x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{3}{4}\end{matrix}\right.\\ 12,\Leftrightarrow2x^2-10x-2x^2=3\\ \Leftrightarrow-10x=3\\ \Leftrightarrow x=-\dfrac{3}{10}\)

1) \(x^2-9x=0\Rightarrow x\left(x-9\right)=0\Rightarrow x=0;9\)

2) \(x\left(x-4\right)-x^2=7\Rightarrow-4x=7\Rightarrow x=-\dfrac{7}{4}\)

3) \(3x+2\left(x-5\right)=5\Rightarrow5x-10=5\Rightarrow5x=15\Rightarrow x=3\)

4) \(25x^2-1=0\Rightarrow x^2=\dfrac{1}{25}\Rightarrow x=\pm\dfrac{1}{5}\)

5) \(3x\left(x-2\right)-5\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(3x-5\right)=0\Rightarrow x=2;\dfrac{5}{3}\)

6) \(3x\left(x-7\right)+4\left(x-7\right)\Rightarrow\left(3x+4\right)\left(x-7\right)=0\Rightarrow x=-\dfrac{4}{3};7\)

7) \(4x^2-9=0\Rightarrow x^2=\dfrac{9}{4}\Rightarrow x=\pm\dfrac{3}{2}\)

8) \(10x\left(x-4\right)+2x-8=0\Rightarrow2\left(x-4\right)\left(5x+1\right)=0\Rightarrow x=4;-\dfrac{1}{5}\)

9) \(x\left(2x-5\right)-2x^2=0\Rightarrow x\left(2x-5-2x=0\right)\Rightarrow x=0\)

10) \(2x^2-4x=0\Rightarrow2x\left(x-2\right)=0\Rightarrow x=0;2\)

11) \(2x\left(3-4x\right)+3\left(4x-3\right)=0\Rightarrow2x\left(4x-3\right)-3\left(4x-3\right)=0\Rightarrow\left(4x-3\right)\left(2x-3\right)=0\Rightarrow x=\dfrac{3}{4};\dfrac{3}{2}\)

12) \(2x\left(x-5\right)-2x^2=3\Rightarrow-10x=3\Rightarrow x=-\dfrac{3}{10}\)

\(1,\)

\(2x\left(x-3\right)-\left(3-x\right)=0\)

\(\Leftrightarrow2x\left(x-3\right)+\left(x-3\right)=0\)

\(\Leftrightarrow\left(2x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-3=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=3\end{cases}}\)

\(2,\)

\(3x\left(x+5\right)-6\left(x+5\right)=0\)

\(\Leftrightarrow\left(3x-6\right)\left(x+5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\x+5=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-5\end{cases}}\)

\(3,\)

\(x^4-x^2=0\)

\(\Leftrightarrow x^2\left(x^2-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2=0\\x^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)

\(4,\)

\(x^2-2x=0\)

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)

\(5,\)

\(x\left(x+6\right)-10\left(x-6\right)=0\)

\(\Leftrightarrow x^2+6x-10x+60=0\)

\(\Leftrightarrow x^2-4x+60=0\)

\(\Leftrightarrow x^2-4x+4+56=0\)

\(\Leftrightarrow\left(x-2\right)^2=-56\)(Vô lý)

=> Phương trình vô nghiệm