Sửa đề: y+y:0,5+y:0,2+y:0,1=5

=>y+2y+5y+10y=5

=>18y=5

=>y=5/18

a, y \(\times\) \(\dfrac{4}{3}\) = \(\dfrac{16}{9}\)

    y         =    \(\dfrac{16}{9}\) : \(\dfrac{4}{3}\)

    y         = \(\dfrac{4}{3}\)

b, ( y - \(\dfrac{1}{2}\)) + 0,5 = \(\dfrac{3}{4}\)

    y - 0,5 + 0,5 = \(\dfrac{3}{4}\)

   y                   = \(\dfrac{3}{4}\)

c, \(\dfrac{4}{5}-\dfrac{2}{5}y\) = 0,2

   0,8 - 0,4y = 0,2

           0,4y = 0,8 - 0,2

           0,4y  = 0,6

               y = 1,5

d, (y + \(\dfrac{3}{4}\)) \(\times\) \(\dfrac{5}{7}\) = \(\dfrac{10}{9}\)

    y + \(\dfrac{3}{4}\)           = \(\dfrac{10}{9}\) : \(\dfrac{5}{7}\)

   y + \(\dfrac{3}{4}\)            = \(\dfrac{14}{9}\)

y                    = \(\dfrac{14}{9}\) - \(\dfrac{3}{4}\)

 y                   =   \(\dfrac{29}{36}\)

e, y : \(\dfrac{5}{4}\)         = \(\dfrac{9}{5}\)  + \(\dfrac{1}{2}\)

   y : \(\dfrac{5}{4}\)         =   \(\dfrac{23}{10}\)

  y                =      \(\dfrac{23}{10}\)

  y               =   \(\dfrac{23}{8}\)

f, y \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{3}{2}\) \(\times\) y   = \(\dfrac{4}{5}\)

   y \(\times\) ( \(\dfrac{1}{2}+\dfrac{3}{2}\))      =  \(\dfrac{4}{5}\)

   2y                       = \(\dfrac{4}{5}\)

    y                        = \(\dfrac{2}{5}\)

a) \(2,5:4x=0,5:0,2\)

\(2,5:4x=\frac{5}{2}\)

\(4x=2,5:\frac{5}{2}\)

\(4x=1\)

\(x=\frac{1}{4}\)

Vậy \(x=\frac{1}{4}\)

b) \(\frac{1}{5}.x:3=\frac{2}{3}:0,25\)

\(\frac{1}{5}.x:3=\frac{8}{3}\)

\(\frac{1}{5}.x=\frac{8}{3}.3\)

\(\frac{1}{5}.x=8\)

\(x=8:\frac{1}{5}\)

\(x=40\)

Vậy \(x=40\)

a) \(\frac{2,5}{4x}=\frac{0,5}{0,2}\)

\(=>4x=\frac{0,2.2,5}{0,5}=1\)

\(=>x=\frac{1}{4}\)

b) \(\frac{1}{5}.\frac{x}{3}=\frac{2}{3}:0,25\)

\(=>\frac{x}{15}=\frac{4}{3}\)

\(=>x=\frac{4.15}{3}=20\)

thiên tài cũng phát ngất

f(x)=x+5
=) x\(^2\)+5=x+5
=)x\(^2\)=x
=)x\(^2\)-x=0
=)x(x-1)=0
=)x=0 hoặc x=1

chúc bạn học tốt

bo chiu

đề ở câu đầu:

x-3/0,2=2x-1/-0,5

3x-1/2x+3=3x+2/2x-1

a: =>-0,5x+1,5=0,4x-0,2

=>-0,9x=-1,7

=>x=17/9

3x-1/2x+3=3x+2/2x-1

=>6x^2-3x-2x+1=6x^2+4x+9x+6

=>-5x+1=13x+6

=>-8x=5

=>x=-5/8

b: \(\Leftrightarrow\left(4x-1\right)\left(-x+7\right)=\left(4x+5\right)\left(-x-2\right)\)

=>\(-4x^2+28x+x-7=-4x^2-8x-5x-10\)

=>29x-7=-13x-10

=>42x=-3

=>x=-1/14

c: =>7x=5y và 2x-y=15

=>7x-5y=0 và 2x-y=15

=>x=25; y=35