\(39+\dfrac{13}{84}+57=\dfrac{8077}{84}\)

\(78+\dfrac{26}{168}+114=\dfrac{16141}{84}\)

hay chung to rang cac phan so sau deu bang nhau:1945 -19/1999 va 194545-1945/19990

1/3 va 34000-68/102000-204

39+13/84+57  và   78+26/168+114

=52/141                 =104/282

                              =52/141

ta có:52/141 = 52/141=>39+13/84+57 = 78+26/168+114

vậy 39+13/84+57 = 78+26/168+114

Ta có

39+13/84+57

= 2(39+13)/2(84+57)

=78+266/168+114

\(\frac{\left(39+13\right)x2}{\left(84+57\right)x2}=\frac{78+26}{168+104}\)

=52/78 nhe bn

26/39=

B 52/78

 \(\dfrac{143}{363}\) = \(\dfrac{143:11}{363:11}\) = \(\dfrac{13}{33}\) (đpcm)

\(\dfrac{1212}{2727}\) = \(\dfrac{1212:101}{2727:101}\) = \(\dfrac{12}{27}\) (đpcm)

\(\dfrac{13}{33}\)  và \(\dfrac{143}{363}\)

\(\dfrac{13}{33}=\dfrac{13\times11}{33\times11}=\dfrac{143}{363}\)

\(\dfrac{143}{363}=\dfrac{143\times1}{363\times1}=\dfrac{143}{363}\)

\(\dfrac{1212}{2727}\)  và \(\dfrac{12}{27}\)

\(\dfrac{12}{27}=\dfrac{12\times101}{27\times101}=\dfrac{1212}{2727}\)

\(\dfrac{1212}{2727}=\dfrac{1212\times1}{2727\times1}=\dfrac{1212}{2727}\)

đó là toán mà

26/39 = 2/3

30/42=5/7

38/57=2/3

51/85=3/5

39/65=3/5

20/28=5/7

=> 39/65=51/85

=> 20/28=30/42

=> 26/39=38/57

k nhé