mình bí

A= 80.(3⁴ + 1)(3⁸ + 1)(3¹⁶ + 1)(3³² + 1)

A = (3⁴ - 1)(3⁴ + 1)(3⁸ + 1)(3¹⁶ + 1)(3³² + 1)

A = (3⁸ - 1)(3⁸ + 1)(3¹⁶ + 1)(3³² + 1)

A = (3¹⁶ - 1)(3¹⁶ + 1)(3³² + 1)

A = (3³² - 1)(3³² + 1)

A = 3⁶⁴ - 1 < 3⁶⁴ = B

=> A < B

\(A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\frac{1}{2}\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\frac{1}{2}\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(=\frac{1}{2}\left(3^4-1\right)\left(3^4+1\right)\)

\(=\frac{1}{2}\left(3^8-1\right)\)

Vậy A < B

\(A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(2A=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)

\(2A=\left(3^8-1\right)\)

\(A=\frac{3^8-1}{2}< B\)

Nó hơi dài cậu chờ tí nka !

Mình ghi nhầm đề bài 1 tí đề bài là :

So sánh 2 số A và B biết : 

A = (3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) và B = 3^32 - 1

A = (2-1)(2+1)(2^2 + 1 ) (2^4 + 1 ) ( 2^8 + 1) ( 2^16 + 1)

A = (2^2 - 1)(2^2 + 1 ) ( 2^4 + 1 )(2^8 + 1 )(2^16 + 1) 

A= ( 2^4 - 1 )( 2^4 + 1 )(2^8 + 1 )(2^16 + 1 )

A = (2^8 - 1 )(2^8 + 1 )(2^16 + 1 )

A = (2^16 - 1 )(2^16 + 1 )

A =  2^32 - 1 < 2^32 = B
Vậy A = B
k mik nka !