bạn viết lại đầu bài đi. Viết thế ai biết gì mà giải chứ

a,  0,4 : x = x : 0,9

<=> x² = 0,4 . 0,9

<=> x² = 0,36

<=> x = 0,6 hoặc -0,6

b, \(13\frac{1}{3}\div1\frac{1}{3}=26\div\left(2x-1\right)\)

\(\Leftrightarrow\frac{40}{3}\div\frac{4}{3}=26\div\left(2x-1\right)\)

\(\Leftrightarrow10=26\div\left(2x-1\right)\)

\(\Leftrightarrow2x-1=\frac{13}{5}\)

\(\Leftrightarrow2x=\frac{18}{5}\)

\(\Leftrightarrow x=\frac{9}{5}\)

c, \(0,2\div1\frac{1}{5}=\frac{2}{3}\div\left(6x+7\right)\)

\(\Leftrightarrow\frac{1}{5}\div\frac{6}{5}=\frac{2}{3}\div\left(6x+7\right)\)

\(\Leftrightarrow\frac{1}{6}=\frac{2}{3}\div\left(6x+7\right)\)

\(\Leftrightarrow6x+7=4\)

\(\Leftrightarrow6x=-3\)

\(\Leftrightarrow x=\frac{-1}{2}\)

d, \(\frac{37-x}{x+13}=\frac{3}{7}\) 

\(\Leftrightarrow7\left(37-x\right)=3\left(x+13\right)\)

\(\Leftrightarrow259-7x=3x+39\)

\(\Leftrightarrow-10x=-220\)

\(\Leftrightarrow x=22\)

a: \(\dfrac{0.4}{x}=\dfrac{x}{0.9}\)

nên \(x^2=\dfrac{9}{25}\)

=>x=3/5 hoặc x=-3/5

b: \(\dfrac{26}{2x-1}=13\dfrac{1}{3}:1\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{26}{2x-1}=\dfrac{40}{3}:\dfrac{4}{3}=10\)

=>2x-1=13/5

=>2x=18/5

hay x=9/5

c: \(\Leftrightarrow\dfrac{2}{3}:\left(6x+7\right)=\dfrac{1}{5}:\dfrac{6}{5}\)

\(\Leftrightarrow\dfrac{2}{3}:\left(6x+7\right)=\dfrac{1}{6}\)

=>6x+7=4

=>6x=-3

hay x=-1/2

d: \(\dfrac{37-x}{x+13}=37\)

=>37(x+13)=37-x

=>37x+481=37-x

=>38x=-444

hay x=-222/19

a)\(\dfrac{0,4}{x}=\dfrac{x}{0,9}\Rightarrow x^2=0,4.0,9=0,36\Rightarrow x=0,6;-0,6\)

\(b)\dfrac{0,2}{1\dfrac{1}{5}}=\dfrac{\dfrac{2}{3}}{6x+7}\Rightarrow6x+7=\dfrac{1\dfrac{1}{5}.\dfrac{2}{3}}{0,2}=4\Rightarrow6x=-3\Rightarrow x=-\dfrac{3}{6}=-\dfrac{1}{2}\)

c)\(\dfrac{13\dfrac{1}{3}}{1\dfrac{1}{3}}=\dfrac{26}{2x+1}\Rightarrow2x+1=\dfrac{1\dfrac{1}{3}.26}{13\dfrac{1}{3}}=2,6\Rightarrow2x=1,6\Rightarrow x=0,8\)

d) mk ko hiểu

e)\(\dfrac{-2,6}{x}=\dfrac{-12}{42}\Rightarrow x=\dfrac{-2,6.42}{-12}=9,1\)

f)\(\dfrac{x^2}{6}=\dfrac{24}{25}\Rightarrow x^2=\dfrac{6.24}{25}=5,76\Rightarrow x=-2,4;2,4\)

n)mk chịu thua

xin lỗi bạn nha

a) 0,4:x=x:0,9

0,4.0,9=x²

0,36 =x²

\(\sqrt{0,36}\)=x

0,6 =x

a) 0,4 : x = x : 0,9 x^2=0,9 . 0,4 x^2=(0,6)^2 =>x=+_6