cho tam giac ABC co AB=12cm . Duong phan giac goc A cat BC tai D, biet BD=9cm . Tren canh AC lay diem E sao cho CE=12,5 cm
Cho tam giac ABC co AB=12cm . Duong phan giac goc A cat BC tai D, biet BD=9cm . tren canh AC lay diem E sao cho CE=12,5 cm a)Tinh do dai cac doan thang DC,BC b)Chung minh DE song song voi AB; tinh do dai doan thang DE
Cho tam giac ABC co AB=9cm, AC=12cm, BC=15cm
a) Chung minh ABC la tam giac vuong
b) Tren canh BC lay diem D sao cho CD=CA, qua D ve duong thang vuong goc voi BC cat AB tai E va cat duong thang AC tai F. Chung minh AB=DF.
c) Chung minh tia CE la tia phan giac goc ACB.
d) So sanh AE va BE
cho tam giac abc vuong tai a co goc b bang 60 do tren canh bc lay diem h sao cho hb=ab duong vuong goc voi bc tai h cat ac tai d
a/ cm bd la tia phan giac cua goc adc
b/ chung to tam giac bdc can
1)cho tam giac abc co goc b=goc c.goi i la trung diem cua canh bc.tren canh ab laydiem d,tren tia di lay diem e sao cho i la trung diem de.cm:
a,bd=ce;
b,cb la tia phan giac cua goc ace
cho tam giac ABC co goc A=90 do va AB=AC.Tren canh AB,AC lay tuong ung 2 diem D va E sao choAD=AE.Tu A va D ke duong vuong goc voi BE cat BC tai M va N.Tia ND cat CA o I.CM:
a,A la trung diem cua CI.
b,CM=MN
Cho tam giac ABC vuong tai A ( AB<AC) ve duong cao AH (H thuoc BC)
A) cm tam giac ABH dong dang tam giac CBA suy ra AB binh =BH.BC
B) Cho AB =6cm , AC=8cm. Tinh BC .Tren canh BC lay diem E sao cho CE=4cm, cm BE binh =BH.HC
C) Tinh dien tich tam giac ABH
D) Duong phan giac cua goc AHB cat AB tai D duong phan giac cua goc AHC cat AC tai F duong thanh DF cat AH tai I va cat CB tai K. Cm DI .FK=DK.FI
A) Xét \(\Delta_VABH\) và \(\Delta_vCBA\):
\(\widehat{B}\): chung
\(\Rightarrow\Delta_vABH\sim\Delta_vCBA\left(gn\right)\)
B) Đề sai vì BC\(=\sqrt{6^2+8^2}=10\left(cm\right)\)
\(\Rightarrow BE=10-4=6\left(cm\right)\)
\(AH=\frac{6.8}{10}=4,8\left(cm\right)\)
mà \(AH^2=BH.HC\) nên AH=BE
Vậy đề sai.
C) Có: \(BH=\frac{AB^2}{BC}=\frac{6^2}{10}=3,6\left(cm\right)\)
\(S_{ABH}=\frac{1}{2},3,6.4,8=8,64\left(cm^2\right)\)
1.cho tam giac ABC can tai dinh A, trung truc cua canh AC cat CB tai diem D (D nam ngoai doan BC). tren tia doi cua tia AD lay diem E sao cho AE= BD. chung minh tam giac DEC can.( goi y can chung minh CD = CE)
2. cho tam giac ABC co AB < AC, lay diem E tren canh CA sao cho CE=BA, cac duong trung truc cua cac doan thang BE va CA cat nhau tai I
a)chung minh tam giac AIB = tam giac CIE
b)chung minh AI la tia phan giac cua goc BAC
cho tam giac ABC vuong tai A ve phan giac cua goc ABC tia nay cat canh AC tai K tren canh BC lay diem D sao cho BD= BA a)chung minh KA=KD b)duong thang AB cat duong thang DK tai E chung minh tam giac KDC c) chung minh tam giac BEC can tai c
cho tam giac ABC vuong tai A biet AB = 9cm BC= 15cm tinh ACroi so sanh cac goc cua tam giac ABC
tren BC lay diem D sao cho BD = BA . Tu D ve duong thang vuong goc voi BC cat AC tai E
cm tam giac EBA = tam giac EBD
lay diem F sao cho D la trung diem cua EF
từ D vẽ DM Vuông góc với CE tại M , DN vuong goc voi CF tai N
cho góc ECF = 60 độ CD = 10cm . tính MN
a) theo đl pytago:
AB^2+AC^2=BC^2
=> AC^2=BC^2-AB^2
=>AC^2=144
=>AC=căn 144 = 12cm
Vì BC>AC>AB=>góc A > góc B > góc C
Xet tam giac ABC co goc A = 90 do (gt)
Ta co AB^2 + AC^2 = BC^2 (dinh ly Pi-ta-go)
=>AC^2 = BC^2 - AB^2 = 15^2 - 9^2 = 225 - 81 = 144
=>AC = can bac 2 cua 144 = 12
Vi BC > AC > AB => goc A > goc B > goc C
Xet tam giac ABC co:
BA = BD (gt) (1)
goc BAE = goc BDE = 90 do (gt) (2)
BE (canh chung) (3)
Tu (1), (2), (3) => tam giac EBA = tam giac EBD (canh huyen-canh goc vuong)
Cau hoi tiep theo tui bo tay.com
cho tam giac ABC vuong tai A(AB<AC). Tia phan giac cua goc B cat AC o E. TRen BC lay diem d sao cho BD=BA. Duong thang DE at duong thang AB tai F.
a, CM ED vuong gic voi BC
b,CMR tam giac BCF can tai b
c, Goi H la giao diem cua BE va FC. TINH BC biet BH=8cm, FC=12cm
d, CM AD song song voi FC