Ta có: 999/556-1= 443/556

100/557-1=443/557

Vì 443/556>443/557 nên 999/556>100/557

1 - \(\frac{999}{556}\) = \(\frac{-443}{556}\)

1 - \(\frac{1000}{557}\) = \(\frac{-443}{557}\)

Vì \(\frac{-443}{556}\) < \(\frac{-443}{557}\) nên \(\frac{999}{556}\) > \(\frac{1000}{557}\)

First we have :

\(\frac{999}{556}=\frac{999\cdot557}{556\cdot557}\)

Then : \(999\cdot557=999\cdot556+999\)

Next we have : \(1000\cdot556=999\cdot556+556\)

As you see : \(999\cdot556+556< 999\cdot556+999\)

So :\(\frac{999}{556}< \frac{1000}{557}\)

Nhầm : \(\frac{999}{556}>\frac{1000}{557}\)

Ta có : 999/556 = 999 : 556

                        = 1,7967625....

1000/577 = 1000 : 577

               = 1,7331022....

Ta thấy : 1,7967625... > 1,7331022

Vậy : 999/556 > 1000/577

Ta có : \(\frac{999}{556}=1+\frac{443}{556}\)

           \(\frac{1000}{577}=1+\frac{423}{577}\)

Ta thấy : \(\frac{443\cdot577}{556\cdot577}=\frac{443}{556}\)

             \(\frac{423\cdot556}{577\cdot556}=\frac{423}{577}\)

Ta có : \(443\cdot577=443\cdot\left(556+21\right)=443\cdot556+443\cdot21\)

Ta thấy : \(423\cdot556\)< \(443.556+21\cdot556\)

=>\(\frac{423\cdot556}{577\cdot556}< \frac{443\cdot577}{556\cdot577}\)

=>\(\frac{1000}{577}< \frac{999}{556}\)

Vậy \(\frac{999}{556}>\frac{1000}{557}\)

Ta có:
\(\dfrac{998}{555}=1+\dfrac{443}{555}\)
\(\dfrac{999}{556}=1+\dfrac{443}{556}\)
So sánh phân số \(\dfrac{443}{555}\) và \(\dfrac{443}{556}\)
Vì \(555< 556\) nên \(\dfrac{1}{555}>\dfrac{1}{556}\)
\(\Rightarrow1+\dfrac{443}{555}>1+\dfrac{443}{556}\)
Vậy \(\dfrac{998}{555}>\dfrac{999}{556}\)

 Ta có một công thức tổng quát là nếu có phân số \(\dfrac{a}{b}>1\) và \(a,b>0\)thì \(\dfrac{a+1}{b+1}< \dfrac{a}{b}\). Thật vậy, điều này tương đương với \(b\left(a+1\right)< a\left(b+1\right)\Leftrightarrow b< a\), luôn đúng vì \(\dfrac{a}{b}>1\).

 Như vậy, trở lại bài toán, ta thấy \(\dfrac{998}{555}>1\) nên \(\dfrac{999}{556}< \dfrac{998}{555}\).

tất nhiên 1000x1000 lớn hơn rồi

999x1001=999x(1000+1)=999x1000+999x1

1000x1000=(999+1)x1000=999x1000+1000x1

vì 999x1>1000x1 nên : 999x1000+999x1>999x1000+1000x1

hay 999x1001>1000x1000

1000^999>999^1000

Ta có \(x=\frac{357}{-352}\)

\(\Rightarrow-x=\frac{357}{352}=1+\frac{2}{352}=\frac{1}{176}\)

Ta có \(y=\frac{-1000}{999}\)

\(\Rightarrow-y=\frac{1000}{999}=1+\frac{1}{999}\)

Vì \(\frac{1}{176}>\frac{1}{999}\Rightarrow1+\frac{1}{176}>1+\frac{1}{999}\Rightarrow-x>-y\Rightarrow x< y\)

Khi đó x < y

Vậy....

\(-x=\frac{357}{352}=1+\frac{5}{352}\)

\(-y=\frac{1000}{999}=1+\frac{1}{999}\)

\(\frac{5}{352}>\frac{5}{999}>\frac{1}{999}\)

\(=>\frac{357}{352}>\frac{1000}{999}=>-x>-y\)

\(=>x< y\)

Cộng cả x và y với 1 ta được

x + 1 = \(\frac{-357}{352}+1=\frac{-5}{352}\)< \(\frac{-1}{352}\)

y + 1 = \(\frac{-1000}{999}+1=\frac{-1}{999}\)>\(\frac{-1}{352}\)

Như vậy x + 1 < y + 1 hay x < y