30%+y+y=52
30%.y+y=52.Tìm y
\(30\%\times y+y=52\)
\(0,3\times y+y\times1=52\)
\(\left(0,3+1\right)\times y=52\)
\(1,3\times y=52\)
\(y=52:1,3\)
\(y=40\)
tk ủng hộ tớ nha
30% *y+y = 52 .tìm y
30% x y +y =52 tim y
Đổi 30% = 3/10
Ta có: 3/10 x y + y = 52
y x (3/10 + 1) = 52
y x 13/10 = 52
y = 52 : 13/10
y = 40
40 đó bạn mình chắc chắn 100000% luận đó
30% x y + y = 52 tìm y
30%*y+y=52
30%y+y=52
130%y=52
y=52/130*100
y=40
30% x Y + Y = 52
30% x Y+Y=52
\(\frac{3}{10}\) x Y+Y=52
(\(\frac{3}{10}\)+1) x Y=52
\(\frac{13}{10}\) x Y=52
Y=52:\(\frac{13}{10}\)
Y=40
30 % x Yx2=52
30 %x Y= 54:2
30% xY= 27
Y = 27:30%
Y =90
30 % xY x 2 = 52
30 % xY = 54 :2
30% x Y =27
Y = 27 : 30 %
Y = 90
30% x y +y =52
30% x y + y = 52
3/10 x y + y = 52
( 3/10 + 1 ) x y = 52
13/10 x y = 52
y = 52 : 13/10
y = 40
30% x y + y = 52
3/10 x y + y = 52
( 3/10 + 1 ) x y = 52
13/10 x y = 52
y = 52 : 13/10
y = 40
30% x y + y = 52
30% x y + y = 52
( 3/10 x y ) + y = 52
13/10 x y = 52
y = 52 : 13/10
y = 40
30% x y + y = 52
y x 130% = 52
y = 52 : 130% = 40
Đáp số: 40
30% x y +y=52