Ta có:x(3x²+4x-7)=x[(3x²-3x)+(7x-7)]=x[3x(x-1)+7(x-1)]=x(x-1)(3x+7)

Dễ mà ^_^:  3x²-7x+2=3x² -x-6x+2=(3x²-x)-(6x-2)=x(3x-1)-2(3x-1)=(3x-1)(x-2) 

\(3x^2-7x+2=\left(3x^2-6x\right)-\left(x-2\right)=3x\left(x-2\right)-\left(x-2\right)=\left(3x-1\right)\left(x-2\right)\)

\(3x^2-7x-10\)

\(=3x^2+3x-10x-10\)

\(=3x\left(x+1\right)-10\left(x+1\right)\)

\(=\left(x+1\right)\left(3x-10\right)\)

3x² - 7x - 10 = 3x² + 3x - 10x - 10 = 3x(x + 1) - 10(x + 1) = (3x - 10)(x + 1)

\(3x^2-7x-10\)

\(=3x^2-3x+10x-10\)

\(=3x\left(x-1\right)+10\left(x-1\right)\)

\(=\left(x-1\right)\left(3x+10\right)\)

(x^2+3x+2)(x^2+7x+12)

=(x²+x+2x+2)(x²+3x+4x+12)

=[x.(x+1)+2.(x+1)][x.(x+3)+4.(x+3)]

=(x+1)(x+2)(x+3)(x+4)

\(3x^2+7x+2\)

\(=3x^2+6x+x+2\)

\(=3x\left(x+2\right)+\left(x+2\right)\)

\(=\left(3x+1\right)\left(x+2\right)\)

\(3x^2+7x+2\)

\(=3x^2+x+6x+2\)

\(=x\left(3x+1\right)+2\left(3x+1\right)\)

\(=\left(3x+1\right).\left(x+2\right)\)

\(3x^4+11x^3-7x^2-2x+1=\left(3x^4+12x^3-3x^2-3x\right)+\left(-x^3-4x^2+x+1\right)\)

\(=\left(3x-1\right)\left(x^3+4x^2-x-1\right)\)

\(=2x^4+6x^3-3x^3-9x^2-3x^2-9x+2x+6\)

\(=2x^3\left(x+3\right)-3x^2\left(x+3\right)-3x\left(x+3\right)+2\left(x+3\right)\)

\(=\left(x+3\right)\left(2x^3-4x^2+x^2-2x-x+2\right)=\left(x+3\right)\left(x-2\right)\left(2x^2+x-1\right)\)

\(=\left(x+3\right)\left(x-2\right)\left(2x^2+2x-x-1\right)=\left(x+3\right)\left(x-2\right)\left(x+1\right)\left(2x-1\right)\)

2x^4+3x^3-12x^2-7x+6 = (2x^4-x^3)+(4x^3-2x^2)-(10x^2-5x)-(12x-6)

= x^3.(2x-1)+2x^2.(2x-1)-5x.(2x-1)-6.(2x-1) = (2x-1).(x^3+2x^2-5x-6) 

= (2x-1).[ (x^3+x^2)+(x^2+x)-(6x+6) ] = (2x-1).(x+1).(x^2+x-6) = (2x-1).(x-1).[(x^2-2x)+(3x-6)]

= (2x-1).(x+1).(x-2).(x+3)

k mk nha

\(2x^4+3x^3-12x^2-7x+6\)

\(=\left(2x^4+2x^3\right)+\left(x^3+x^2\right)-\left(13x^2+13x\right)+\left(6x+6\right)\)

\(=\left(x+1\right)\left(2x^3+x^2-13x+6\right)\)