tui o bít nhưng ai kb vs tui o

uk

a)x=30

b)x=65

a) x-\(\left(\frac{50x}{100}+\frac{25x}{200}\right)\)=\(11\frac{1}{4}\)

<=>x - \(\frac{1}{2}x-\frac{1}{8}x\)=\(\frac{11.4+1}{4}\)

<=>\(\frac{3}{8}x=\frac{45}{4}\)

<=>x=\(\frac{45}{4}:\frac{3}{8}\)

<=>x=30

Vậy x=30

c) (x-5).\(\frac{30}{100}\)=\(\frac{20x}{100}+5\)

<=>(x-5).\(\frac{3}{10}\)=\(\frac{x}{5}\)+5

<=>\(\frac{3x}{10}-\frac{15}{10}=\frac{x}{5}+5\)

<=>\(\frac{3x}{10}-\frac{x}{5}=5+\frac{15}{10}\)

<=>\(\frac{x}{10}=\frac{13}{2}\)

<=>x=\(\frac{13.10}{2}\)

<=>x=65

Vậy: x=65

\(c,\frac{x+1}{2}=\frac{8}{x+1}\)

\(\Rightarrow(x+1)(x+1)=2.8\)

\(\Rightarrow(x+1)^2=16\)

\(\Rightarrow(x+1)^2=4^2\)

\(\Rightarrow x+1=4\)

\(\Rightarrow x=4-1\)

\(\Rightarrow x=3\)

\(a,x-(\frac{50x}{100}+\frac{25x}{200})=11\frac{1}{4}\)

\(\Rightarrow x-\frac{50x+25x}{100}=\frac{45}{4}\)

\(\Rightarrow\frac{100x}{100}-\frac{75x}{100}=\frac{45}{4}\)

\(\Rightarrow\frac{100x-75x}{100}=\frac{1125}{100}\)

\(\Rightarrow25x=1125\)

\(\Rightarrow x=45\)

\(b,(x-5)\frac{30}{100}=\frac{200x}{100}+5\)

\(\Rightarrow\frac{30x}{100}-\frac{3}{2}=\frac{200x}{100}+5\)

\(\Rightarrow\frac{30x}{100}-\frac{200x}{100}=5+\frac{3}{2}\)

\(\Rightarrow\frac{-170x}{100}=\frac{13}{2}\)

\(\Rightarrow\frac{-170x}{100}=\frac{650}{100}\)

\(\Rightarrow-170x=650\)

\(\Rightarrow x=\frac{-65}{17}\)

 \(x-\left(\frac{50x}{100}+\frac{25x}{100}\right)=\frac{45}{4}\)

      \(x-\left(\frac{50x+25x}{100}\right)=\frac{45}{4}\)

                    \(x-\frac{75x}{100}=\frac{45}{4}\)

               \(x-x\times\frac{3}{4}=\frac{45}{4}\)

         \(x\times\left(1-\frac{3}{4}\right)=\frac{45}{4}\)

                       \(x\times\frac{1}{4}=\frac{45}{4}\)

                                 \(x=\frac{45}{4}\div\frac{1}{4}\)

                                 \(x=45\)

\(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=\frac{45}{4}\)

\(x-\left(\frac{100x}{200}+\frac{25x}{200}\right)=\frac{45}{4}\)

\(x-\left(\frac{100x+25x}{200}\right)=\frac{45}{4}\)

\(x-\frac{125x}{200}=\frac{45}{4}\)

\(x-x\frac{5}{8}=\frac{45}{4}\)

\(x\left(1-\frac{5}{8}\right)=\frac{45}{4}\)

\(x.\frac{3}{8}=\frac{45}{4}\)

\(x\)=\(\frac{45}{4}:\frac{3}{8}\)

\(x\)=\(30\)

a) \(2^{x+2}-2^2=96\)

 <=> \(2^x.2^2-2^x=96\)

 <=> \(2^x\left(4-1\right)=96\)

<=> \(3.2^x=96\)

<=> \(2^x=32\)

<=> \(2^x=2^5\)

<=> x = 5 

b, \(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\)

\(\Rightarrow x-\left(\frac{1x}{2}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\left(\frac{4x}{8}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{8x}{8}-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{3x}{8}=\frac{45}{4}\Rightarrow x=\frac{45}{4}\div\frac{3}{8}=30\)

Vậy x = 30