\(\frac{8}{11}+\frac{8}{33}\)x\(\frac{3}{4}\)
Giup mik nha!
\(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(3\frac{1}{3}.x-6\frac{3}{4}=3\frac{1}{4}\)
giúp mik nha mai mik kiểm tra rồi
a) \(\frac{x}{3}\)\(-\)\(\frac{1}{8}\)\(=\)\(\frac{5}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)=\(\frac{5}{8}+\frac{1}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)\(=\frac{3}{4}\)
\(\Rightarrow\) x=3.3:4
\(\Rightarrow\) x=2,25
Vậy x=2,25
b) \(3\frac{1}{3}\).x-\(6\frac{3}{4}=3\frac{1}{4}\)
\(\Rightarrow\)\(\frac{10}{3}\).x-\(\frac{27}{4}=\frac{13}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=\(\frac{13}{4}+\frac{27}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=10
\(\Rightarrow\) x=\(10\div\frac{10}{3}\)
\(\Rightarrow\) x=3
Vậy x=3
Ủng hộ mik nha mọi người !
Ta có : \(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{5}{8}-\frac{1}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}.\frac{1}{3}=\frac{1}{6}\)
\(\frac{x}{3}-\frac{1}{8}+\frac{5}{8}\)
\(\frac{x}{3}=\frac{5}{8}+\frac{1}{8}=\frac{6}{8}=\frac{3}{4}\)
\(x=\frac{3}{4}.3=\frac{9}{4}\)
\(3\frac{1}{3}x-6\frac{3}{4}=3\frac{1}{4}\)
\(\frac{10}{3}x=3\frac{1}{4}+6\frac{3}{4}=10\)
\(x=10:\frac{10}{3}=3\)
4\(\frac{3}{4}\) -0,37+\(\frac{1}{8}\)-1,28-2,5+3\(\frac{1}{12}\)
caccau giup mik nha
= 19/4 - 0,37 + 1/8 - 1,28 - 2,5 + 37/12
= 19/4 - 37/100 + 1/8 - 32/25 - 5/2 + 37/12
= 219/50 + (-231/200) - 67/12
= 129/40 - 67/12
=(-283/120)
bạn k cho mình đi làm ơn đó
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
\(=\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
\(=\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{2500}{1000}+\frac{37}{12}\)
\(=\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
\(=\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=\frac{457}{120}=3\frac{97}{120}\)
--Good luck--
\(4\frac{3}{4}-0,37+\frac{1}{8}-1,28-2,5+3\frac{1}{12}\)
= \(\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{37}{12}\)
= \(\frac{4750}{1000}-\frac{370}{1000}+\frac{125}{1000}-\frac{1280}{1000}-\frac{1500}{1000}+\frac{37}{12}\)
= \(\frac{4750-370+125-1280-2500}{1000}+\frac{37}{12}\)
=\(\frac{29}{40}+\frac{37}{12}=\frac{87}{120}+\frac{370}{120}=3\frac{97}{120}\)
Good luck
Tìm x biết:
\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
Giup mik với mik đag gấp lắm mik like cho nha giải chi tiết nhé
\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\)\(:16\frac{2}{3}=0\)
\(\Rightarrow\)\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)=0\)
\(\Rightarrow\)\(5\frac{3}{8}+x-7\frac{5}{24}=2\)
\(\Rightarrow5\frac{3}{8}+x=9\frac{5}{24}\)
\(\Rightarrow x=3\frac{5}{6}\)
( Cách làm thì đúng rồi nhưng đáp án tớ ko chắc chắn )
Bài 1
\(\frac{10}{17}-\frac{5}{13}+\frac{7}{17}+\frac{-8}{13}-\frac{11}{25}\)
1-2+3-4+5-6+.........+2011-2012
bài 2
\(\frac{2}{3}-x=\frac{5}{4}\)
[124-(20-4x)]:30+7=11
Giúp mik nha mai mik kiểm tra rồi
=10/17+-5/13+7/17+-8/13+-11/25
=1+-1+-11/25
=11/25
b ,
= 1+-2+3+-4+5+-6+......2011+-2012
=1+1+1+1+1.........+-2012
=1.2011+-2012
=2011+-2012
=-1
2.
2/3-x = 5/4
=>x=2/3-5/4
=>x=-7/12
b,
[124-(20-4x)]:30+7=11
=>124-(20-4x)] :30 =11-7
=>[124-(20-4x)]:30=4
=>124-(20-4x)=4x30
=>124-(20-4x)=120
=>20-4x=120-124
=>20-4x=4
=>4x=20-4
=>4x=16
=>x=16:4
=>x=4
bài 1
a, ghép cặp phân số 10/17 + 7/17 và 5/13 + -8/13
b, 1-2+3-4+5-6+.....+2011-2012
= ( 1-2) + ( 3-4) + ( 5-6) +....+(2011-2012)
= (-1) + (-1) + (-1) + ....+ (-1)
< từ 1 đến 2012 có 2012 số số hạng, suy ra có 1006 cặp mà mỗi cặp có giá trị = (-1) Suy ra tổng trên = (-1) * 1006=-1006
Bài 2:
a,2/3 - x =5/4
x=2/3 - 5/4
x= -7/12
tim x
a)\(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
b)\(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
giup mik vs
a) \(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
\(\left(-\frac{3}{4}+\frac{1}{6}\right).x=1-\frac{23}{9}\)
\(-\frac{7}{12}.x=-\frac{14}{9}\)
\(x=-\frac{14}{9}:\left(-\frac{7}{12}\right)\)
\(x=\frac{8}{3}\)
Vậy x = ...
b) \(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
\(\left|2x-\frac{3}{8}\right|+\frac{11}{4}=\frac{49}{16}\)
\(\left|2x-\frac{3}{8}\right|=\frac{49}{16}-\frac{11}{4}\)
\(\left|2x-\frac{3}{8}\right|=\frac{5}{16}\)
\(\Rightarrow\left|2x-\frac{3}{8}\right|\in\text{{}\frac{5}{16};-\frac{5}{16}\)}
Nếu, \(2x-\frac{3}{8}=\frac{5}{16}\)
\(2x=\frac{11}{16}\)
\(x=\frac{11}{32}\)
Nếu, \(2x-\frac{3}{8}=-\frac{5}{16}\)
\(2x=\frac{1}{16}\)
\(x=\frac{1}{32}\)
Vậy \(x\in\text{{}\frac{1}{32};\frac{11}{32}\)}
\(\frac{3}{8\times11}+\frac{4}{11\times15}+\frac{5}{15\times20}+\frac{6}{20\times26}+\frac{7}{26\times33}+\frac{8}{33\times41}+\frac{9}{41\times50}=\frac{2}{5}-2\times x\)
làm ơn giúp em giải bài toán này!!!!!!!!
Câu 1:
\(\frac{11}{12}.\frac{15}{33}+\frac{11}{12}.\frac{2}{22}\)
\(3/3\frac{1}{8}.11\frac{17}{19}-3\frac{1}{8}.13\frac{17}{19}\)
\(28\frac{2}{7}:\left(-\frac{3}{5}\right)+16\frac{2}{7}:\left(-\frac{3}{5}\right)\)
Câu 2: Tim x, y biêt
\(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
\(|2x-\frac{3}{4}|-\frac{1}{6}=5\)
\(\left(x+\frac{1}{3}\right)^3=\left(\frac{-1}{8}\right)\)
\(\frac{7}{9}\)x\(\frac{3}{4}:\frac{5}{8}\)
Giup mik nhé!
\(\frac{7}{9}.\frac{3}{4}:\frac{5}{8}=\frac{7}{12}:\frac{5}{8}=\frac{7}{12}.\frac{8}{5}=\frac{14}{15}\)
\(=\frac{7}{12}x\frac{8}{5}=\frac{14}{15}\)
\(\frac{75}{8}-\frac{36}{7}=\)giup mik nha cac bạn