\(\dfrac{x-3}{7}=\dfrac{2x-7}{13}\)

\(7\left(2x-7\right)=13\left(x-3\right)\)

\(14x-49=13x-39\)

\(14x-13x=49-39\)

\(x=10\)

Câu 13: 

Ta có: \(f\left(x\right)>0\Leftrightarrow3x-m>0\Leftrightarrow3x>m\)

Mà x>1 hay 3x>3

Vậy \(m\le3\)

Đáp án C

Câu 14:

(d): x-2y+1=0 hay \(\dfrac{1}{2}x+\dfrac{1}{2}=y\)

Gọi phương trình đường thẳng cần tìm là: y=ax+b

Phương trình cần tìm đi qua A nên ta có: 2=-2a+b

Để phương trình cần tìm vuông góc với (d) thì: \(a.\dfrac{1}{2}=-1\Rightarrow a=-2\)\(\Rightarrow b=-2\)

Vậy phương trình cần tìm là: \(y=-2x-2\)

Đáp án C

a

Tìm kiểu gì ạ?

(2x - 1)^2 + (x + 3)^2 - 5(x + 7)(x - 7) = 0
<=>4x^2-4x+1+x^2+6x+9-5x^2+245=0
<=>2x+255=0
<=>2x=-255
<=>x=-255/2

Ta có phương trình khí lí tưởng: \(\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\Leftrightarrow\dfrac{4.6}{293}=\dfrac{p.4}{313}\Rightarrow p=6,4\left(atm\right)\)

Đáp án A

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