738-429=
A=(3/429-1/1.3).(3/429-1/3.5).(3/429-1/5.7)...(3/429-1/121.123)
Đặt tính rồi tính:
83 738 + 12 533 137 736 + 902 138
96 271 - 83 738 1 039 874 - 902 138
Tính tích (3/429 - 1/1.3)(3/429 - 1/3.5)......(3/429 - 1/129.121)(3/429 - 1/121.123)
A=(3/429-1/1*3)*(3/429-1/3*5)*...*(3/429-1/121*123) = ?
\(\left(\frac{3}{429}-\frac{1}{1.3}\right)\left(\frac{3}{429}-\frac{1}{3.5}\right)....\left(\frac{3}{429}-\frac{1}{119.121}\right)\left(\frac{3}{429}-\frac{1}{121.123}\right)\)= ?
(3/429 - 1/1.3)(3/429 - 1/3.5) ... (3/429 - 1/121.123)
= (1/143 - 1/1.3)(1/143 - 1/3.5) ... (1/143 - 1/11.13) ... (1/143 - 1/121.123)
= (1/11.13 - 1/1.3)(1/11.13 - 1/3.5) ... (1/11.13 -1/11.13) ... (1/11.13 - 1/121.123)
= (1/11.13 - 1/1.3)(1/11.13 - 1/3.5) ... 0 ... (1/11.13 - 1/121.123)
= 0
=(1/143-1/1.3)...(1/143-1/121.123)
vì trong tích có thừa số (1/143-1/11.13)=0
nên cả tích =0
LÀM ƠN LIKE CHO MÌNH ĐI
Tính tích:
\(A=\left(\frac{3}{429}-\frac{1}{1\times3}\right)\times\left(\frac{3}{429}-\frac{1}{3\times5}\right)\times...\times\left(\frac{3}{429}-\frac{1}{119\times121}\right)\times\left(\frac{1}{429}-\frac{2}{121\times123}\right)\)
(3/429 - 1/1.3)(3/429 - 1/3.5) ... (3/429 - 1/121.123)
= (1/143 - 1/1.3)(1/143 - 1/3.5) ... (1/143 - 1/11.13) ... (1/143 - 1/121.123)
= (1/11.13 - 1/1.3)(1/11.13 - 1/3.5) ... (1/11.13 -1/11.13) ... (1/11.13 - 1/121.123)
= (1/11.13 - 1/1.3)(1/11.13 - 1/3.5) ... 0 ... (1/11.13 - 1/121.123)
= 0
bỏ ngoặc rồi tính :
(– 166 + 852 – 429) – ( 852 + 429 – 166)
(– 166 + 852 – 429) – ( 852 + 429 – 166)
\(=-166+852-429-852-429+\)166
=\(\left(-166+166\right)+\left(852+-852\right)+\left(-429-429\right)\)
=\(0+0+\left(-858\right)\)
= - 858
\(\left(-166+852-429\right)-\left(852+429-166\right)\)
\(=-166+852-429-852-429+166\)
\(=\left(-166+166\right)+\left(852-852\right)-\left(429+429\right)\)
\(=-858\)
\-2005\+(-680)+738+(-320)
= 2005 +(-680 ) + 738 + (-320 )
= [(-680 ) + (-320)] +(2005 + 738 )
= (-1000 ) + 2743
= 1743
k mk nha
738/287-1/3=?