Tính ra M to lắm bạn ơi so sánh với 1 đời nào

\(M=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{100.101.102}\)

\(\Rightarrow2M=\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{100.101.102}\)

\(\Rightarrow2M=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{100.101}-\frac{1}{101.102}\)

\(\Rightarrow2M=\frac{1}{1.2}-\frac{1}{101.102}\)

\(\Rightarrow M=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{101.102}\right)=1-\frac{1}{202.102}< 1\)

Vậy M < 1

Anh Kiệt ơi \(\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{101.102}\right)=\frac{1}{4}-\frac{1}{202.102}\)chứ ạ ???

\(M=\frac{1}{2}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{100.101.102}\right)\)

\(M=\frac{1}{2}.\left(1-\frac{1}{102}\right)\)

\(M=\frac{101}{204}< 1\left(đpcm\right)\)

Ta có: M=11.2.3  +12.3.4  +13.4.5  +...+1100.101.102  

         M=2.(11.2.3  +12.3.4  +13.4.5  +...+1100.101.102  ).12 

          M=(21.2.3  +22.3.4  +23.4.5  +...+2100.101.102  ).12 

          M=(11.2  -12.3  +12.3  -13.4  +13.4  -14.5 +...+1100.101 −1101.102  ).12 

          M=( 11.2 −1101.102 ).12 

          Mà 11.2 −1101.102 <1

         Và 12 <1 

        =>  (11.2 −1101.102  ) .12  <1

        => M <1

M=1/1x2x3 =1/2x3x4 +1/3x4x5 +..........+1/100x101x102

M=3-1/1x2x3 +4-2/2x3x4+5-3/3x4x5 + ......... +102-100/100x101x102

M=3/1x2x3 -1/1x2x3 +4/2x3x4 -2/2x3x4 +........... + 102/100x101x102 -100/100x101x102

M=1/1x2 -1/2x3 +1/2x3 -1/3x4 +......... + 1/100x101 -1/101x102

M=1/1x2 -1/101x102

M=2575/5151 < 1   suy ra M<1 

Vậy M<1

\(M=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+...+\frac{1}{100\cdot101\cdot102}\\ M=\frac{1}{2}\cdot\left(\frac{2}{1\cdot2\cdot3}+\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+...+\frac{2}{100\cdot101\cdot102}\right)\\ M=\frac{1}{2}\cdot\left(\frac{1}{1\cdot2}-\frac{1}{2\cdot3}+\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{100\cdot101}-\frac{1}{101\cdot102}\right)\\ M=\frac{1}{2}\cdot\left(\frac{1}{1\cdot2}-\frac{1}{101\cdot102}\right)\\ M=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{10302}\right)\\ M=\frac{1}{2}\cdot\left(\frac{5151}{10302}-\frac{1}{10302}\right)\\ M=\frac{1}{2}\cdot\frac{25}{51}\\ M=\frac{25}{102}\\ \Rightarrow M< 1\)

Vậy M < 1

M<1 ok?

A = 1 - 1/2 - 1/3 + 1/2 - 1/3 - 1/4 + ... + 1/2014 - 1/2015 - 1/2016

A = 1- 1/2016

A = 2015/2016

A > 1/4

A=4949/19800 và 1/4

4949/19800 < 1/4

Xong! t*** mik đê!!!

\(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2014.2015.2016}\)

\(A=\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2015.2016}\right)\)

\(A=0,2499998...<0,25\)

\(\Rightarrow A<\frac{1}{4}\)

bạn viết gì vậy? Mình ko thấy?

S = 1/1.2.3 + 1/2.3.4 + 1/3.4.5 + ...  + 1/23.24.25

2.S = 2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ...  + 2/23.24.25

      = 1/1.2 - 1/2.3 + 1/2.3 - 1/3.4 + ...+ 1/23.24 - 1/24.25

      = 1/1.2 - 1/24.25 = 1/2 - 1/600

=> S = (1/2 - 1/600) : 2 = 1/4 - 1/1200

Dễ thấy S < 1/4 Hay S < 0,25

1/2.(2/1.2.3+2/2.3.4+......2/23.24.25)

1/2.(1/1.2-1/2.3+1/2.3-1/3.4+……+1/23.24-1/24.25)

1/2.(1/1.2-1/24.25)

1/2.(1/2-1/600)

1/2.(300/600-1/600)

1/2.299/600

299/1200

Ta co 0.25=1/4

Nen ta so sanh 1/4 va 299/1200

Vi 300/1200>299/1200

Nen 1/4>299/1200

Ket luan 0,25>S

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