x= âm 43 chia 60 viết bằng phân số nhé bạn

\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right).462-\left[2,04:\left(x+1,05\right):0,12\right]=19\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right).462-\left[2,04:\left(x+1,05\right):0,12\right]=19\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{21}\right).462-\left[2,04:\left(x+1,05\right):0,12\right]=19\)

\(\Leftrightarrow\frac{10}{231}.462-\left[2,04:\left(x+1,05\right):0,12\right]=19\)

\(\Leftrightarrow20-\left[2,04:\left(x+1,05\right):0,12\right]=19\)

\(\Leftrightarrow2,04:\left(x+1,05\right):0,12=1\)

\(\Leftrightarrow2,05:\left(x+1,05\right)=0,12\)

\(\Leftrightarrow x+1,05=\frac{205}{12}\)

\(\Leftrightarrow x=\frac{205}{12}-1,05\)

\(\Leftrightarrow x=\frac{481}{30}\)

cái này cồng kềnh nhưng ko khó - >ngại. Bn tính 2/11*13+.... trước bằng cách rút gọn sau đó nhân ra -> dễ

\(\left(\dfrac{2}{11\cdot13}+\dfrac{2}{13\cdot15}+...+\dfrac{2}{19\cdot21}\right)\cdot462-\left[0,04:\left(x+1,05\right)\right]:0,12=19\)\(\Leftrightarrow\dfrac{2}{2}\cdot\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right)\cdot462-\left[\dfrac{1}{25}:\left(x+\dfrac{21}{20}\right)\right]:\dfrac{3}{25}=19\)\(\Leftrightarrow\left(\dfrac{1}{11}-\dfrac{1}{21}\right)\cdot462-\left[\dfrac{1}{25}:\left(x+\dfrac{21}{20}\right)\right]:\dfrac{3}{25}=19\)

\(\Leftrightarrow20-\left[\dfrac{1}{25}:\left(x+\dfrac{21}{20}\right)\right]:\dfrac{3}{25}=19\)

\(\Leftrightarrow\left[\dfrac{1}{25}:\left(x+\dfrac{21}{20}\right)\right]:\dfrac{3}{25}=1\)

\(\rightarrow\dfrac{1}{25}:\left(x+\dfrac{21}{20}\right)=\dfrac{3}{25}\)

\(\Leftrightarrow x+\dfrac{21}{20}=\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{1}{3}-\dfrac{21}{20}=-\dfrac{43}{60}\)

Vậy \(x=-\dfrac{43}{60}\)

Sao mk câu hỏi của bạn dùng mà tốn giấy vậy, tiết kiệm chút đi