\(\frac{2017}{2018}\)x\(\frac{7}{8}\)+\(\frac{2017}{2018}\)x\(\frac{3}{8}\)-\(\frac{2017}{2018}\)x\(\frac{1}{4}\)

= \(\frac{2017}{2018}\)x  (\(\frac{7}{8}\)+\(\frac{3}{8}\)-\(\frac{1}{4}\))

= \(\frac{2017}{2018}\)x  ( \(\frac{10}{8}\)- \(\frac{1}{4}\))

= \(\frac{2017}{2018}\)x ( \(\frac{10}{8}\)- \(\frac{2}{8}\))

= \(\frac{2017}{2018}\)x  1

= \(\frac{2017}{2018}\)

Chúc em học tốt nhé :>

=2017/2018*(7/8+3/8)-2017*1/4

=2017/2018*5/4+2017*-1/4

=2017/2018*(5/4-1/4)

=2017/2018*1

=2017/2018

\(2018\cdot2018-2017\cdot2019\)

\(=2018^2-\left(2018-1\right)\left(2018+1\right)\)

\(=2018^2-\left(2018^2-1\right)\)

\(=2018^2-2018^2+1\)

\(=1\)

\(2018.2018-2017.2019\)

\(=2018^2-\left(2018-1\right)\left(2018+1\right)\)

  \(=2018^2-\left(2018^2-1\right)\)

  \(=2018^2-2018^2+1\)

  \(=1\)

nhớ k đấy

2018*2018-2017*2019

=2018*(2019-1)-2017*2019

=2018*2019-2018-2017*2019

=2019-2018=1

=(8*125)*2019-(125*4)*2018

=1000*2019-1000*2018

=1000*(2019-2018)=1000*1=1000

8 x 2019 x125 - 250 x 2018 x 4

= ( 8x 125) - ( 250x 4)x 125

=1000-1000 x 125

0 x 125

= 0

mk chẳng bt đúng ko nữa

giúp mình nha, mình cần gấp

8 x 2.019 x 125 - 250 x 2.018 x 4

= (8 x 125) x 2.019 - (250 x 4) x 2.018

= 1.000 x 2.019 - 1.000 x 2.018

=2.019.000 - 2.018.000

= 1.000

nhớ tick nhe

\(\frac{2017}{2018}\times2015+\frac{2017}{2018}\times4-\frac{2017}{2018}.\)

\(=\frac{2017}{2018}\times2015+\frac{2017}{2018}\times4-\frac{2017}{2018}\times1\)

\(=\frac{2017}{2018}\times\left(2015+4-1\right)\)

\(=\frac{2017}{2018}\times2018\)

\(=\frac{2017\times2018}{2018\times1}\)

\(=\frac{2017}{1}=2017\)

2018x36+2018+2018x63

=2018x(36+1+63)

=2018x100

=201800

2018 x 36 + 2018 + 2018 x 63

= 2018 x 36 + 2018 x 1 + 2018 x 63

= 2018 x ( 36 + 1 + 63 )

=2018 x 100

= 201800

^HT^

2018 nhân 36 +2018 nhân 1 +2018 nhân 63

=2018 nhân [ 36 +63] +1

=2018 nhân 100

= 201800