A=4116-14/10290-35
B= 2929-101/2 +404
Rút gọn
A=4116-14 / 10290
B=2929-101 / 2x1919+404
\(A=\frac{4116-14}{10290}\)
\(A=\frac{14\times\left(294-1\right)}{735\times14}\)
\(A=\frac{294-1}{735}\)
\(A=\frac{293}{735}\)
Vậy A có giá trị \(\frac{293}{735}\)
\(B=\frac{2929-101}{2\times1919+404}\)
\(B=\frac{101\times\left(29-1\right)}{35\times\left(38+4\right)}\)
\(B=\frac{28}{42}\)
\(B=\frac{2}{3}\)
Vậy B có giá trị \(\frac{2}{3}\)
\(A=\frac{4116-14}{10290}\)
\(A=\frac{14.\left(294-1\right)}{735.14}\)
\(A=\frac{294-1}{735}\)
\(A=\frac{293}{735}\)
\(B=\frac{2929-101}{2.1919+404}\)
\(B=\frac{2828}{2.1919+2.202}\)
\(B=\frac{2.1414}{2.\left(1919+202\right)}\)
\(B=\frac{1414}{2121}\)
\(B=\frac{101.14}{101.21}\)
\(B=\frac{14}{21}\)
\(B=\frac{2}{3}\)
Rút gọn
A=4116-14/10290-35
B=2929-101/2.1919+404
Rút gon
A= 4116-14/10290-35
B= 2929-101/2.1919+404
\(A=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)
\(B=\frac{2929-101}{2.1919+404}=\frac{101\left(29-1\right)}{101\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)
rut gon:
A= 4116-14/10290-35
B= 2929-101/2.1919+404
Rút gọn :
a) 4116 - 14 phần 10290 -35
b) 2929 - 101 phần 21919 +404
Rút gọn
a)\(\frac{4116-14}{10290-35}\)
b)\(\frac{2929-101}{21919+404}\)
GIẢI
a)
=\(\frac{4102}{10255}\)
=\(\frac{4102:2051}{10255:2051}\)
=\(\frac{2}{5}\)
b)
=\(\frac{2828}{22323}\)
=\(\frac{2828:7}{22323:7}\)
=\(\frac{404}{3189}\)
rút gọn
a) 4116 - 14 / 10290 - 35
b) 2929 - 101 / 2.1919 + 404
c) 31 995 - 81 / 108 - 42 660
Rút gọn
A= \(\dfrac{4116-14}{10290-35}\) B=\(\dfrac{2929-101}{2.1919+404}\)
\(A=\dfrac{4116-14}{10290-35}=\dfrac{14\times\left(294-1\right)}{35\times\left(294-1\right)}=\dfrac{14}{35}\)
\(B=\dfrac{2929-101}{2\times1919+404}=\dfrac{101\times\left(29-1\right)}{101\times\left(38+4\right)}=\dfrac{29-1}{38+4}=\dfrac{28}{32}=\dfrac{7}{8}\)
Rút gọn phân số:
A= 4116 - 14
10290 - 35
B = 2929 - 101
2 x 1919 + 404
\(A=\frac{4116-14}{10290-35}=\frac{4102}{10255}=\frac{2}{5}\)
\(B=\frac{2929-101}{2\times1919+404}=\frac{2828}{4242}=\frac{2}{3}\)
Giúp mình với
Rút gọn:
A = 4116 - 14/10290 - 35 B = 2929 - 101/2.1919 + 404
A=4116-14/10290-35
=[14 x ( 294 -1 )]/[35 x (294-1)]
= 14/35
B =2929-101/2.1919+404
= [101 x (291-1)] / [101 x 38 + 101 x 4)]
= [ 101x (29 -1)] / [ 101 x (38+4)
= (29-1) / (38+4)
= 28/42 = 2/3
A=4116-14/10290-35=14.294-14.1/35.294-35.1=14.(291-1)/35.(294-1)=14/35=14:7/35:7=2/5
B=2929-101/2.1919+404=101.29-101.1/2.19.101+4.101=101.(29-1)/101.(2.19+4)=28/42=28:14/42:14=2/3