10 < 10 + 3

11 + 2=2 + 11

9 < 10 + 9

10 = 10 + 0

17 – 4 > 14 - 3

18 – 4 >12

15 > 15 – 1

17 + 1<17 + 2

12+ 5 > 16

16 =19 - 3

15 – 4 =10 + 1

19 – 3 >11

1+2+3+4+5+...+15+16+17+18+19+20

= ( 1 + 19 ) + ( 2 + 18 ) + ( 3 + 17 ) + ( 4 + 16 ) + ( 5 + 15 ) + ... + ( 9 + 11 ) +  ( 10 + 20 )

= 20 + 20 + 20 + 20 + ... + 20 + 30

= 180 + 30 = 210

Tính số phần tử:   \(\text{1+2+3+4+...+18+19+20}\) 
                              \(=\left(20-1\right):1+1\) \(=20\)

Tổng : \(\dfrac{\left(20+1\right)\times20}{2}=210\)

\(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)

Biến đổi tử số 

\(19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}\)

= 1 + \(\left(1+\dfrac{18}{2}\right)+\left(1+\dfrac{17}{3}\right)+\left(1+\dfrac{16}{4}\right)+...+\left(1+\dfrac{1}{19}\right)\)

= \(\dfrac{20}{20}+\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{1}{19}\)

= 20 x \(\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)\)

Vậy \(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)

= \(\dfrac{20\times\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}=20\)

Vậy A = 20

c.ơn nhìu a

1 + 2 + 3 +4 + 5 + 19 +18 +17 +16 +15

=[1+19]+[18+2]+[17+3]+[116+4]+[15+5]

=20+20+20+20+20

=100

100 nha

1+2+3+4+5+19+18+17+15=84

(19 + 1) + (18 + 2) + (17 + 3) + (16 + 4) + (15 + 5)

= 20 + 20 + 20 + 20 + 20

= 20 x 5 = 100

=20+20+20+20+20

=20x5

=100

20+20+20+20+20=20x5=100

k nhe

20-19+18-17+16-15+14-13+12-11+11-10+10-9+9-8+8-7+7-6+6-5+5-4+4-3+3-2+2-1

=1+1+1+1+1+1+1+1+1+1+1+1+1+1+1

=1x15

=15

tk nhé

20 - 19 + 18 - 17 + 16 - 15 + ... + 4 - 3 + 2 - 1

= ( 20 - 19 ) + ( 18 - 17 ) + ( 16 - 15 ) + ... + ( 4 - 3 ) + ( 2 - 1 )

=> Có 10 cặp số 1

<=> 1 x 10 

= 10

Đáp số: Kết quả là 10 

15