\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(\Rightarrow3A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)

\(\Rightarrow3A=1+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}\)

\(\Rightarrow3A=1+1-\frac{1}{32}\)

\(\Rightarrow3A=2-\frac{1}{32}\)

\(\Rightarrow A=\left(2-\frac{1}{32}\right):3=\frac{21}{32}\)

P/s : Đúng nha 

A= 1/3+1/3-1/6+1/6-1/12+1/12-1/24+1/24-1/48+1/48-1/96

A=1/3+1/3-1/96

A=2/3-1/96

A=63/32.

Bằng 63/32

1/3+1/6+1/12+1/24+1/48+1/96=21/32

21/32

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}=\frac{21}{32}\)

Nhớ click cho mik nha !!!!!!!!!!!!!!!!!!!!!

1/3 + 1/6+1/12+1/24+1/48+1/96
= 2/3 – 1/3 + 1/3 – 1/6+1/6- 1/12+1/12- 1/24+1/24-
1/48+1/48-1/96
=2/3_1/96

= 63/96
= 21/32

= 1-1/3+1/3-1/6+1/6-1/12+1/12-1/24+1/24-1/48+1/48-1/96+1/96-1/192 

 = 1-1/192 = 191 / 192 

1/3 +1/6+1/12+1/24 +1/48 + 1/96
= 1/3 + 1/3 – 1/6 + 1/6 – 1/12+1/12 – 1/24 +1/24 –
1/48+1/48 -1/96
=2/3 – 1/96
= 63/96
= 21/32

21/32=0,65625

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\frac{32}{96}+\frac{16}{96}+\frac{8}{96}+\frac{4}{96}+\frac{2}{96}+\frac{1}{96}\)

\(=\frac{63}{96}=\frac{21}{32}\)

Đặt tổng các phân số trên là A ta có

\(\frac{A}{2}=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)

\(\frac{A}{2}=A-\frac{A}{2}=\frac{1}{3}-\frac{1}{192}=\frac{63}{192}\Rightarrow A=\frac{2x63}{192}=\frac{126}{192}=\frac{21}{32}\)
 

1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96

= 1x32/2x32 + 1x16/6x16 + 1x8/12x8 + 1x4/24x4 + 1x2/48x2 + 1/96

= 32/96 + 16/96 + 8/96 + 4/96 + 2/96 + 1/96

= 63/96

1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96 + 1/192 + 1/384 = 85/128

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)

\(=\frac{5}{8}+\frac{1}{32}\)

\(=\frac{21}{32}\)

21/32

3/4 nha bạn đúng thì k mk nha