so sanh A=20/39+22/27+18/43 va B=14/39+22/29+18/41
giai mau giup minh voi
Cho hai phan so A=20/39 + 22/37 + 18/43 va B=14/39 + 22/29 + 18/41. So sanh A va B.
Ai nhanh nhat va dung nhat thi minh se tick va ket ban nhe!!!
So sanh AvaB
A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43},B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
Ta có: \(\dfrac{20}{39}>\dfrac{20}{41}>\dfrac{18}{41}\left(1\right)\)
\(\dfrac{22}{27}>\dfrac{22}{29}\left(2\right)\)
\(\dfrac{18}{43}=1-\dfrac{25}{43};\dfrac{14}{39}=1-\dfrac{25}{39}\)
Vì \(\dfrac{25}{43}< \dfrac{25}{39}\Rightarrow1-\dfrac{25}{43}>1-\dfrac{25}{39}\Rightarrow\dfrac{18}{43}>\dfrac{14}{39}\left(3\right)\)
Từ \(\left(1\right);\left(2\right);\left(3\right)\) ta suy ra : A>B
so sánh
a= 20/39 + 22/27 + 18/43
b= 14/39 +22/29 +18/41
Ta thấy :
\(\frac{20}{39}>\frac{14}{39}\)
\(\frac{22}{27}>\frac{22}{29}\)
\(\frac{18}{43}< \frac{18}{41}\)
\(\Rightarrow\frac{20}{39}+\frac{22}{27}+\frac{18}{43}>\frac{14}{39}+\frac{22}{29}+\frac{18}{41}\)
=> A > B
so sanh a va b
a, A=20/39 +22/27 + 18/43 B=14/39 +22/29+18/41
b, A=3/8^3 + 7/8^4 B= 7/8^3 + 3/8^4
so sánh \(A=\frac{20}{39}+\frac{22}{27}+\frac{18}{43};B=\frac{14}{39}+\frac{22}{29}+\frac{18}{41}\)
so sánh: A = \(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43}\) và B = \(\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)
so sánh A và B :
A = \(\frac{20}{39}+\frac{22}{27}+\frac{18}{43}\), B = \(\frac{14}{39}+\frac{22}{29}+\frac{18}{41}\)
ta có 20/39 > 14/39
22/27 > 22/29
18/43 < 18/41
=> 20/39+22/27+18/43 > 14/39+22/29+18/41
ta có 20/39 > 14/39
22/27 > 22/29
18/43 < 18/41
=> 20/39+22/27+18/43 > 14/39+22/29+18/41
Bằng dấu lớn ( > ) bạn nhé!^-^
Chúc bạn học tốt nha!^-^
So sánh A và B:
A=20/39+22/27+18/43 ; B=14/39+22/29+18/41
so sánh các phần sốsau :(kết hợp phương nhiều pháp
ko thực hiện phép tính cộng hay so sánh tổng m va n
m=21/23+12/27va n=57/59+3/8
m=20/39+22/27+18/43 va n=14/39+22/29+18/41