720: (x+3+x x 5) =6 giup toi tim x voi nhe
Tim x biet: 720:(x + 3 + x x 5) =6 giup toi giai bai toan nay voi
TIM X
a) (7/2+2x)x8/3=16/3
b) [2x+3]=5
c) x-2/4=5+x/3
lam on giup toi nhe ban
Giup minh voi toi nay minh rat can, dung thi minh tich cho, ca cach lam nua nhe.
Tim x,y
a, 2x.y+xy=7
b, xy + 2x - 7y = 14
c, x^3 - 64x = 0
Lam on giup toi voi:
tim x thuoc Z:
a, ( x + 1 ) . ( x + 5 ) < 0
(x+1).(x+5)<0
Ta xet cac truong hop
T/h1: x+1<0 => x<-1
x+5>0 => x>-5
Suy ra -1>x>-5 ; x=-2;-3;-4
T/h2 : x+1>0 => x>-1
x+5<0 => x<-5
Suy ra khong tim duoc x
Tich cho minh nha
a 9,15 x X + 2,85 = 47,685
giup toi giai bai toan tim X tren nhe
9 , 15 x X + 2 , 85 = 47 , 685
9 , 15 x X = 47 , 685 - 2 , 85
9 , 15 x X = 44 , 835
X = 44 , 835 : 9 , 15
X = 4 , 9
Vậy X = 4 , 9
Chúc bạn học tốt nha !!!
Tim x biet (x+1)(x+2)(x+3)+...+(x+100)=5750
giup minh voi nhe
( x + 1 ) + ( x + 2 ) + ( x + 3 ) +... + ( x + 100 ) = 5750
( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
( x . 100 ) + ( 1 . 100 ) . 100 : 2 = 5750
( x . 100 ) + 5050 = 5750
x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
Vậy x = 7
( x + 1 ) + ( x + 2 ) + ( x + 3 ) +... + ( x + 100 ) = 5750
( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750
( x . 100 ) + ( 1 . 100 ) . 100 : 2 = 5750
( x . 100 ) + 5050 = 5750
x . 100 = 5750 - 5050
x . 100 = 700
x = 700 : 100
x = 7
Vậy x = 7
Tim x biet 1+1/2(1+2)+1/3(1+2+3)+...+1/x(1+2+3+...+x)=115
Giup toi voi
\(1+\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+...+\frac{1}{x}.\left(1+2+3+...+x\right)=115\)
\(\Rightarrow1.\left(\frac{1.2}{2}\right)+\frac{1}{2}.\left(\frac{2.3}{2}\right)+\frac{1}{3}.\left(\frac{3.4}{2}\right)+....+\frac{1}{x}.\left[\frac{x\left(x+1\right)}{2}\right]=115\)
\(\Rightarrow\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+....+\frac{x+1}{2}=115\Rightarrow2+3+...+\left(x+1\right)=230\)
\(\frac{\Rightarrow\left[\frac{\left(x+1-2\right)}{1}+1\right].\left(x+1+2\right)}{2}=\frac{x.\left(x+3\right)}{2}=230\Rightarrow x.\left(x+3\right)=460\)
vì x và x+3 là 2 số tự nhiên cách nhau 3 đơn vị => \(x.\left(x+3\right)=460=20.23\Rightarrow x=20\)
Vậy x=20
{x^2 -[ 6^2-(8^2-9*7)^3-7*5 ]^3-5*3 }^3=1
giup toi nhe
Cac ban giup toi co loi giai doi voi bai toan nay nhE
(x-3)2=25
\(\left(x-3\right)^2=25\)
\(\Rightarrow\left(x-3\right)^2=5^2\)
\(\Rightarrow x-3=5\)
\(\Rightarrow x=8\)
(x - 3)2 = 25
(x - 3)2 = 52 = (-5)2
=> x - 3 thuộc {5 ; -5}
=> x thuộc {8 ; -2}
Vậy x thuộc {8 ; -2}
(x-3)2=25
x-3=5 (vì 25=52) hoặc x-3=-5 (vì 25=(-5)2
x=8 hoặc x=-2