Bạn tự hỏi rồi từ trả lời ! Bạn xem đầu bạn có nóng không ?

olm ko cho tự hỏi tự trả lời đâu nhoa.

`Answer:`

\(A=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-25^5\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)[5^{10}-\left(5^2\right)^5]\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-5^{10}\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right).0\)

\(=0\)

\(B=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(4^{10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(2^{2.10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right).0\)

\(=0\)

1)50+50+50+100/5

=50+50+50+20

=100+70

=170

2)100/100+20/10+5

=1+2+5

=3+5

=8

3)200/100+50/10+6

=2+5+6

=7+6

=13

minh tr nha ban

100⁵ : 100³ = 100²

10² . 10¹ = 10³

500²⁰⁰ . 500¹⁰ = 500²¹⁰

10⁵ . 10² = 10⁷

100³⁰ . 100¹⁰ = 100⁴⁰

200¹⁰⁰ : 200¹⁰ = 200⁹⁰

100²⁰ . 100¹⁰ = 100³⁰

300¹⁰⁰ . 300¹⁰⁰ = 300²⁰⁰

100⁵ : 100³

= 100^{5 - 3}

= 100²

10² . 10¹

= 10^{2 + 1}

= 10³

500²⁰⁰ . 500¹⁰

= 500^{200 + 10}

= 500²¹⁰

10⁵ . 10²

= 10^{5 + 2}

= 10⁷

100³⁰ . 100¹⁰

= 100^{30 + 10}

= 100⁴⁰

200¹⁰⁰ : 200¹⁰

= 200^{100 - 10}

= 200¹⁹⁰

100²⁰ . 100¹⁰

= 100^{20 + 10}

= 100³⁰

300¹⁰⁰ .300¹⁰⁰

= 300^{100 + 100}

= 300²⁰⁰

19/20x2/100+19/20x2/100

= [19/20+19/20]x2/100

= 38/20x2/100

= 19/500

75/76x102/100-75/76x2/100

= [102/100-2/100]x75/76

= 1x75/76

= 75/76

3x7/10+7/10x5+2x7/10

= [3+5+2]x7/10

= 10x7/10

= 7

giá trị biểu thức 

2/5+2/3x3/4

= 2/5+1/6

= 17/30

1/2x1/3-1/8

= 1/6-1/8

= 1/24

[1/2+1/3]:3/9

= 5/6:3/9

= 5/2

                       nhớ tick cho tớ nhé

rùi đó

a: \(1\dfrac{9}{10}=1,9\)

\(2\dfrac{66}{100}=2,66\)

\(3\dfrac{72}{100}=3,72\)

\(4\dfrac{999}{1000}=4,999\)

b: \(8\dfrac{2}{10}=8,2\)

\(36\dfrac{23}{100}=36,23\)

\(54\dfrac{7}{100}=54,07\)

\(12\dfrac{254}{1000}=12,254\)

đặt A=100^10+1/100^10-1

B=10^100+1/10^100-3

ta có:\(A=\frac{100^{10}+1}{100^{10}-1}=\frac{100^{10}-1+2}{100^{10}-1}=\frac{100^{10}-1}{100^{10}-1}+\frac{2}{100^{10}-1}=1+\frac{2}{100^{10}-1}\)

\(B=\frac{10^{100}+1}{10^{100}-3}=\frac{10^{100}-3+4}{10^{100}-3}=\frac{10^{100}-3}{10^{100}-3}+\frac{4}{10^{100}-3}=1+\frac{4}{10^{100}-3}=1+\frac{4}{100^{10}-3}\)

vì 100¹⁰-1>100¹⁰-3

=>\(\frac{4}{100^{10}-1}<\frac{4}{100^{10}-3}\)

=>A<B

 Arcobaleno sai

Ta có:

\(\frac{100^{10}+1}{100^{10}-1}=\frac{100^{10}-1+2}{100^{10}-1}=\frac{100^{10}-1}{100^{10}-1}+\frac{2}{100^{10}-1}=1+\frac{2}{10^{20}-1}=1+\frac{4}{2.10^{20}-2}\)

\(\frac{10^{100}+1}{10^{100}-3}=\frac{10^{100}-3+4}{10^{100}-3}=\frac{10^{100}-3}{10^{100}-3}+\frac{4}{10^{100}-3}=1+\frac{4}{10^{100}-3}=1+\frac{4}{10^{100}-3}\)

Thấy: \(2.10^{20}-2<10^{100}-3\)

\(\Rightarrow\frac{4}{2.10^{20}-1}>\frac{4}{10^{100}-3}\)

\(\Rightarrow\frac{100^{10}+1}{100^{10}-1}>\frac{10^{100}+1}{10^{100}-3}\)

a/ta gọi biểu thức trên là A.

ta có: A=1+2+2²+...+2¹⁰⁰

     2A= 2x(1+2+2²+...+2¹⁰⁰)

     2A= 2x1+2x2+2²x2+...+2¹⁰⁰x2

     2A= 2+2²+2³+....+2¹⁰¹

     2A-A=A=(2+2²+2³+....+2¹⁰¹)-(1+2+2²+...+2¹⁰⁰)

     A= 2¹⁰¹-1

b/ làm tương tụ như câu a nhưng cuối cùng phải thêm '':2'' (vì lúc đó ta tính ra 3A - A =2A nên phải chia 2)