3^x-1+5.3^x-1=162

=>3^x-1.(1+5)=162

=>3^x-1.6=162=>3^x-1=162:6=27=3³

=>x-1=3=>x=4

5^x+5^x+2=650

=>5^x+5^x.5²=650

=>5^x.(1+25)=650

=>5^x.26=650=>5^x=650:26=25=5²

=>x=2

3^{x - 1} + 5.3^{x - 1}=162

3^{x - 1} .(1+5)=162

3^{x - 1}=27

3^x :3¹=27

3^x=81

3^x=3⁴

=>  x=4

\(a)3^{x-1}+5\cdot3^{x-1}=162\)

\(\Rightarrow3^{x-1}(1+5)=162\)

\(\Rightarrow3^{x-1}.6=162\)

\(\Rightarrow3^{x-1}=27\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=4\)

Câu b tự làm nhé

3^x-1 + 5 . 3^x-1 = 162

3^x-1 . 1 + 5 . 3^x-1 = 162

3^x-1 . ( 1 + 5 ) = 162

3^x-1 . 6 = 162

3^x-1 = 162 : 6

3^x-1 = 27

3^x-1 = 3³

=> x - 1 = 3

=> x = 3 + 1

=> x = 4

2x+ 3= x+ 2
2x- x= 2- 3
x= -1
vậy x=-1
b) \(3^{x-1}+5.3^{x-1}=162 \) 

\(3^{x-1}.\left(1+5\right)=162\)

\(3^{x-1}.6=162\)

\(3^{x-1}=162:6\)\(\Rightarrow3^{x-1}=27\)

\(3^{x-1}=3^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=4\)

=0 nhe

3^x-1+5.3^x-1=162

3^x-1.(1+5)=162

3^x-1.6=162

3^x-1=162:6

3^x-1=27

3^x-1=3^3

x-1=3

x=3+1

x=4

3^-1 . 3^x + 5.3^{x - 1} = 162

=> 3^{x - 1} + 5.3^{x - 1} = 162

=> 3^{x - 1}. (1 + 5) = 162

=> 3^{x - 1} . 6 = 162

=> 3^{x - 1} = 162

=> 3^{x - 1} = 27

=> 3^{x - 1} = 3³

=> x - 1 = 3

=> x = 3 + 1

=> x =4

3^-1 . 3^x + 5.3^{x -1} = 162

=> 1/3 . 3^x + 5.3^x : 3 = 162

=> 1/3 . 3^x + 5/3 . 3^x = 162

=> 3^x . (1/3 + 5/3)     = 162

=> 3^x . 2                    = 162

=> 3^x                         = 162 : 2

=> 3^x                         = 81

=> 3^x                         = 3⁴

=>   x                        = 4

       \(3^{-1}.3^x+5.3^{x-1}=162\)

\(\Rightarrow3^{x-1}+5.3^{x-1}=162\)

\(\Rightarrow3^{x-1}.1+3^{x-1}.5=162\)

\(\Rightarrow3^{x-1}\left(5+1\right)=162\)

\(\Rightarrow3^{x-1}.6=162\)

\(\Rightarrow3^{x-1}=\frac{162}{2}\)

\(\Rightarrow3^{x-1}=27\)

\(\Rightarrow3^{x-1}=3^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=3+1=4\)

\(\text{Vậy }x=4\)

~Chúc bạn học tốt ^^~

(3x+1)^3=-216=(-6)^3

=>3x+1=-6

=>x=...

3^x-1+5.3^x-1=162

=>3^x-1.(1+5)=162

=>3^x-1.6=162

=>3^x-1=162:6=27

=>3^x-1=3^3

=>x-1=3

=>x=4