2^2010-2^2009-2^2008-2^2007-....-2-1
Những câu hỏi liên quan
2. So sánh A và B:
A= 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010
B=-1/2006*2007 - 1/2008*2009
tính tổng sau :\(c=\frac{\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}}{\frac{5}{2008}-\frac{5}{2009}-\frac{5}{2010}}+\)\(\frac{\frac{2}{2007}-\frac{2}{2008}-\frac{2}{2009}}{\frac{3}{2007}-\frac{3}{2008}-\frac{3}{2009}}\)
\(C=\frac{\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}}{\frac{5}{2008}-\frac{5}{2009}-\frac{5}{2010}}+\frac{\frac{2}{2007}-\frac{2}{2008}-\frac{2}{2009}}{\frac{3}{2007}-\frac{3}{2008}-\frac{3}{2009}}\)
\(=\frac{\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}}{5.\left(\frac{1}{2008}-\frac{1}{2009}-\frac{1}{2010}\right)}+\frac{2.\left(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2009}\right)}{3.\left(\frac{1}{2007}-\frac{1}{2008}-\frac{1}{2009}\right)}\)
\(=\frac{1}{5}+\frac{2}{3}\)
\(=\frac{13}{15}\)
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So sánh
bài 1 :A= 2006/2007-2007/2008+2008/2009-2009/2010
B= -1/2006*2007-1/2008*2009
bài 2: C= 2006/2007+2007/2008+2008/2009+2009/2006 với 4
2^2010-(2^2009+2^2008+2^2007+......+2^1+2^0)
Đặt :
\(A=2^{2009}+2^{2008}+......+2+1\)
\(\Leftrightarrow2A=2^{2010}+2^{2009}+......+2^2+2\)
\(\Leftrightarrow2A-A=\left(2^{2010}+2^{2009}+.....+2\right)-\left(2^{2009}+2^{2008}+.....+2+1\right)\)
\(\Leftrightarrow A=2^{2010}-1\)
\(\Leftrightarrow2^{2010}-A=2^{2010}-\left(2^{2010}-1\right)=2^{2010}-2^{2010}+1=1\)
Vậy..
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Đặt A=\(2^{2010}-\left(2^{2009}+2^{2008}+2^{2007}+...+2^1+2^0\right)\)
Khi đó:\(A=2^{2010}-2^{2009}-2^{2008}-...-2^1-2^0\\ \Rightarrow2A=2^{2011}-2^{2010}-2^{2009}-...-2^1\\ 2A-A=2^{2011}-2^{2010}-2^{2009}-...-2^1-\left(2^{2010}-2^{2009}-....-2^1-2^0\right)\\ A=2^{2011}-2^{2010}-...-2^1+2^{2010}+2^{2009}+...+2^0\\ A=2^{2011}-2.2^{2010}+2^0\\ A=1\)Vậy A=1
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Gọi M=\(2^{2010}-\left(2^{2009}+2^{2008}....+2^1+2^0\right)\)
\(2^{2010}-\)M=\(2^{2010}-2^{2009}-2^{2008}-2^{2007}-....2^1-2^0\)
2.(\(2^{2010}\)-M)=\(2^1+2^2+....+2^{2009}+2^{2010}\)
2.(\(2^{2010}\)-M)-(\(2^{2010}\) -M)=(\(2^1+2^2+....+2^{2009}+2^{2010}\))-(\(2^0+2^1+....+2^{2008}+2^{2009}\)
\(2^{2010}-\)M=\(2^{2010}-1\) M=\(2^{2010}-2^{2010}+1\) M=1
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\(C=\frac{2010+\frac{2009}{2}+\frac{2008}{3}+...+\frac{2}{2007}+\frac{1}{2008}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...\frac{1}{2008}+\frac{1}{2009}}.\)
có nhầm đề không vậy phải là 2010-
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1. So sánh
a) A=1/2019 - 3/11^2 - 5/11^ - 7/11^4 và B= -1/2019 - 7/11^2 - 5/ 11^3 - 3/11^4
b) A= 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010 và B= -1/2006 . 2007 - 1/2008 . 2009
1. 3/2/3+ 1/1/5 - 2/5/3 + 5/3/5
2. 1/2+ 1/6 + 1/12+ 1/20 + 1/30+ 1/42
3. 3/5 = 13-x/ x+11
4.12x + x45 = 468
5.Cho A = 2007/2008 + 2008/2009 + 2009/2010
Cho B = 2007 + 2008 + 2009/ 2008 + 2009 +2010
Hãy so sánh A và B.
Các bạn giúp mk với nhé, Mk căm ơn rất nhiều!!!!!!!
(2010-2009+2008-2007+......+2-1): (-5)
(2010-2009+2008-2007+......+2-1): (-5)
=[(2010-2009)+(2008-2007)+...+(2-1)] :(-5)
=(1+1+...+ 1+1) :(-5)
=(1.1005) :(-5)
= 1005:(-5)
= -201
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Tính tổng sau
A=1-2+3-4+5-....-2008+2009
B=1+2-3-4+5+6-7-...-2007-2008+2009+2010
Bài làm:
\(A=1-2+3-4+5-...-2008+2009\)
\(A=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(2007-2008\right)+2009\)
\(A=-1-1-1-...-1+2009\)(1004 số -1)
\(A=-1004+2009=1005\)
\(B=1+2-3-4+5+6-7-...-2007-2008+2009+2010\)
\(B=1+\left(2-3-4+5\right)+\left(6-7-8+9\right)+...+\left(2006-2007-2008+2009\right)+2010\)
\(B=1+0+0+...+0+2010\)
\(B=2011\)
Học tốt!!!!