D = 1.2 + 2.3 + 3.4 + ... + 99.100

3D = 1.2.3 + 2.3.3 + 3.4.3 + ... + 99.100.3

3D = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98)

3D = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100

3D = 99.100.101

D = 99.100.101 : 3 = ...

c) Đặt \(A=1\cdot2+2\cdot3+3\cdot4+...+99\cdot100\)

Ta có: \(A=1\cdot2+2\cdot3+3\cdot4+...+99\cdot100\)

\(\Leftrightarrow3A=3\cdot\left(1\cdot2+2\cdot3+3\cdot4+...+99\cdot100\right)\)

\(\Leftrightarrow3A=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+3\cdot4\cdot\left(5-2\right)+...+99\cdot100\cdot\left(101-98\right)\)

\(\Leftrightarrow3\cdot A=1\cdot2\cdot3-1\cdot2\cdot3+2\cdot3\cdot4-2\cdot3\cdot4+...+98\cdot99\cdot100-98\cdot99\cdot100+99\cdot100\cdot101\)

\(\Leftrightarrow3\cdot A=99\cdot100\cdot101\)

\(\Leftrightarrow A=33\cdot100\cdot101=333300\)

b) Ta có: \(1+2-3-4+...+97+98-99-100\)

\(=\left(1+2-3-4\right)+\left(5+6-7-8\right)+...+\left(97+98-99-100\right)\)

\(=\left(-4\right)+\left(-4\right)+...+\left(-4\right)\)

\(=-4\cdot25=-100\)

A= 1-2+3-4+4-5+...+99-100

A = ( 1 - 2 ) + ( 2 - 3 ) + ....+ ( 99 - 100 )

A = ( - 1 ) + ( - 1 ) +....+ ( - 1 )

A = ( - 1 ) . 50

A = - 50

B = 1.2 + 2.3 + 3.4 + 4.5 +...+ 99.100 
Nhân cả 2 vế với 3, ta được: 
3A=1.2.3+ 2.3.3+ 3.4.3+ 4.5.3+...... 99.100.3 
= 1.2.3 + 2.3(4-1) + 3.4.(5-2) +...+ 99.100.(101-98) 
= 1.2.3 + 2.3.4 -1.2.3 + 3.4.5-2.3.4 +...+ 99.100.101-98.99.100 
= 99.100.101 
=) B = (99.100.101) :3 
B = 333300  
Vậy  B= 333300 

A= 1-2+3-4+4-5+...+99-100

A = (1-2) + (3-4) + (4-5) + ... + (99-100)

A = (-1) + (-1) + (-1) + ...+ (-1)

A = (-1).50

A = 1

B = 1.2+2.3+3.4+4.5+...+99.100

3B = 1.2.3 +2.3.3+ 3.4.3+...+99.100.3 
3B = 1.2.3 +2.3(4-1)+ 3.4(5-2)+...+99.100(101-98) 
3B = 1.2.3 +2.3.4-1.2.3+ 3.4.5-2.3.4+...+99.100.101-98.99.100 
3B = 99.100.101

3B = 999900 
B = 999900 : 3

B = 333300

ta có \(3S=1\cdot2\cdot3+2\cdot3\cdot3+.....+99\cdot100\cdot3\)

\(3S=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)....+99\cdot100\cdot\left(101-98\right)\)

\(3S=1\cdot2\cdot3-1\cdot2\cdot3+2\cdot3\cdot4-......-98\cdot99\cdot100+99\cdot100\cdot101\)

\(3S=99.100.101\)

\(S=\frac{99\cdot100\cdot101}{3}\)

S=...

3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3

3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100

3S=99.100.101

S=33.100.101

S=333300

Vậy S=333300

( 99,1 - 1,2 ) : 1,1 + 1 = 90

S là :

( 99,1 + 1,2 ) x 90 : 2 = 4513,5

Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
 3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101  3S = 3.33.100.101 
 S=33.100.101= 333300

S = 1.2 + 2.3 + ... + 99.100

4S = 1.2.(3 - 0) + 2.3.(4 - 1) + ... + 99.100.(101 - 98)

4S = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 +...+ 99.100.101 - 98.99.100

4S = (1.2.3 + 2.3.4 +...+ 99.100.101) - (0.1.2 + 1.2.3 +...+ 98.99.100)

4S = 99.100.101 - 0.1.2

4S = 99.100.101

S = 99.25.101

S = 249975

\(S=1.2+2.3+3.4+4.5+5.6+...+99.100\)

\(3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3\)

\(3S=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+4.5.\left(6-3\right)+...+99.100.\left(101-98\right)\)\(1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101+98.99.100\)

\(3S=\left(1.2.3-1.2.3\right)+\left(2.3.4-2.3.4\right)+...+\left(98.99.100-98.99.100\right)+99.100.101\)

\(3S=99.100.101=9999000\)

\(S=9999000:3=3333000\)

\(\Rightarrow S=3333000\)

Ta có: A = 1.2 + 2.3 + 3.4 + 4.5 +.....+ 98.99

=> 3A = 1.2.(3 - 0) + 2.3.(4 - 1) + ..... +98.99.(100 - 97)

=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 98.99.100

=> 3A = 98.99.100

=> A = 98.99.100 / 3

=> A = 323400