Find a four-digit natural number that is less than 2015.If the thousands digit is erased,the number will be decreased by 9 times.
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find a four-digit natural number that is less than 2015. If the thousands digit it erase, the number will be decreased by 9 time
có ai biết câu trả lời chính xác ko?Giúp dùm mình
tìm một số tự nhiên có bốn chữ số ít hơn so với 2015. Nếu xóa chữ số hàng nghìn thì số đó sẽ giảm 9 lần.
Từ đó ta biết số đó là 1125.
Question 1:
The least common multiple of 330; 65; 15 is
Question 2:
Given seven numbers: 25; 17; 39; 43; 239; 1021; 1023.
The composite numbers are
(Write numbers in order from the least to the greatest and use ";")
Question 3:
The common factors of 18 and 27 are
(Write numbers in order from the least to the greatest and use ";")
Question 4:
Given the set of even numbers: {2; 4; 6; …; 100}.The number of elements is
Question 5:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 6:
Find a four-digit natural number that is less than 2015.If the thousands digit is erased,the number will be decreased by 9 times.
Answer:The number is
Question 7:
Calculate: 1×2+2×3+⋯+100×101=
Question 8:
The term of the expression A=1-7+13-19+25-31+⋯ is
Question 9:
Given the expression A= ...
Find the value of n such that 2A+3=
Answer: n=
Question 10:
A natural number has six digits and the units digit is 4.If the units digit is moved to the first row then the number will be increasedby 4 times.The number is
Find a four-digit natural number that is less than 2015.If the thousands digit is erased,the number will be decreased by 9 times.
if delete the last digit of a 3-digit number then it will be decreased by 93 units. Find the original number. Answer the original number is
ab3 - ab = 93
ab x 10 + 3 - ab = 93
ab x (10 - 1) =93 - 3
ab x 9 = 90
ab = 90 : 9
ab = 10
the original number is 103
Find all natural numbers having two digit , knowing that twice the units digit 1 more than the ten digit , and if we write that two digits in reverse order, we get a new number which is 27 less than the old one
Tell the numbers to find are \(\overline{ab}\)
\(\Rightarrow\left\{{}\begin{matrix}2b-a=1\\\overline{ab}-\overline{ba}=27\end{matrix}\right.\)
=> 10a + b - 10b - a = 27
=> 9a - 9b = 27
=> a-b = 3
=> a = b + 3
=> 2b - 1 = b+3
=> 2b - b = 3 + 1
=> b = 4
=> a = \(2\cdot4-1=7\)
So he number to find is 74
in a 4-digit number, the ones digit is the possible largest number, the hundreds digit is the smallest odd number and the tens digit is 1 more than the hundreds digit. The thousands digit is the sum of the hundreds and the tens digit. Find the number
:
In a 4-digit number, the ones digit is the possible largest number, the hundreds digit is the smallest odd number and the tens digit is 1 more than the hundreds digit. The thousands digit is the sum of the hundreds and the tens digit. Find the number.
Answer: The number is
In a 4-digit number, the ones digit is the possible biggest number, the hundreds digit is the smallest odd number and the tens digit is 1 more than the hundreds digit. The thousands digit is the sum of the hundreds and tens digit . Find the number. nhanh lên nhé
The ones digit: 9
The tens digit: 2
The hundreds digit: 1
The thousands digit: 3
Answer: 3129
