\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)tìm \(\frac{x}{y}\)
giúp với nha mấy bạn
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)tìm \(\frac{x}{y}\)
giúp vs nha
4x(3y + 11)=6y(2x + 8) =>12xy + 44x =12xy + 48y
=>44x = 48y =>\(\frac{x}{y}\)=\(\frac{48}{44}\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)tìm \(\frac{x}{y}\)
Giúp mình với
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\).tìm x/y
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
<=>4x(3y+11)=6y(2x+8)
<=>12xy+44x=12xy+48y
<=>44x=48y(cùng bớt đi 12xy)
do đó x/y=48/44=12/11
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
Ta có:4x*3y+44x=6y*2x+48y
12xy+44x=12yx+48y
44x=48y
=>\(\frac{x}{y}=\frac{48}{44}\)
=>x/y=\(\frac{12}{11}\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}.\frac{x}{y}=?\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
Tính :\(\frac{x}{y}\)
từ trên
=>4x(3y+11)=6y(2x+8)
=>12xy+44=12xy+48
=>\(\frac{x}{y}=\frac{12}{11}\)
Tìm \(\frac{x}{y}\)biết:
\(\frac{3x+2y}{2x-3y}=\frac{5x-y}{4x-6y}=\frac{-2x+3y}{-2x+3y}=1\)
Cho mik ý kiến nka các bạn!
Mjk giải vầy các pax nhận xét nka!
\(\Rightarrow\frac{3x+2y}{2x-3y}=1\)
\(\Rightarrow3x+2y=\left(2x-3y\right)1\)
\(\Rightarrow3x+2y=2x-3y\)
\(\Rightarrow3x-2x=-3y-2y\)
\(\Rightarrow x=-5y\)
\(\Rightarrow\frac{x}{y}=-5\)
Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\).Vậy \(\frac{x}{y}=.......\)
Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\). Vậy\(\frac{x}{y}\) =...
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)
\(44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)
\(\Leftrightarrow44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)
Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)vậy \(\frac{x}{y}\)=........