Tim x thoa man : -12.(x-5)+7.(3-x0) =5 .
tim cap so tu nhien X0 Y0 thoa man 92*x+1)*(x-5)=12
Tim x thoa man -12 * (x-5) + 7(3-x )=5
-12x+60+21-7x=5
-12x-7x=-60-21+5
-19x=-76
x=4
-12.x + 12.5+7.3-7.x=5
-12.x+ 60+21-7.x=5
-19.x=76
=> không có x
tim x thoa man: -12(x-5)+7(3-x)=5
<=>(-12)(x-5)+7(3-x)=-(19x-81)
=>-(19x-81)=5
<=>81-19x=5
=>-19x=-76
=>x=(-76):(-19)
=>x=4
tim x thoa man -12*(x-5)+7*(3-x)=5
(-12) (x - 5) + 7(3 - x) = 5
=> -12x + 60 + 21 - 7x - 5 = 0
=> -19x + 76 = 0
=> -19x = -76
=> x = 4
-12(x-5)+7(3-x)=5
<=>(-12x)-(-60)+21-7x=5
<=>(-12x)+60+21-7x=5
<=>(-12x-7x)+81=5
<=>(-19x)=-76<=>x=4
vậy x=4
tim x thoa man -12(x-5)+7(3-x) =5
Tìm x thoa man:-12(x-5)+7(3-x)=5
Giúp mình (violympic lớp 8 vòng 7)
goi x0 la gia tri cua x thoa man (3x^3+x^2-13x+5)/(x^2+2x-1)=0 khi do 3x0=
tim x thoa man :12(x-5)+7(3-x)=5
12(x-5)+7(3-x)=5
<=>12x-60+21-7x=5
<=>12x-39-7x=5
<=>12x-7x=39+5
<=>5x=44<=>x=44/5
Vậy x=44/5
tim x thoa man 42+(3x+7):2=2^5+3^4
42+(3x+7):2=2^5+3^4
42+(3x+7):2=32+81
42+(3x+7):2=113
(3x+7):2=113-42
(3x+7):2=71
3x+7=71x2
3x+7=142
3x=142:7
3x=142/7
x=142/7:3
x=142/21