There are three different natural numbers. Their sum is 1267 . When the greatest common divisor of these is the largest. Find three numbers
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The sum of four natural numbers is 1111. Find the largest possible values of highest common factor of these four numbers.
The average of five different natural numbers is 4. If the different between the largest and smallest of these numbers is as large as possible, what is the average of the other three numbers?
The average of five different natural numbers is 4. If the different between the largest and smallest of these numbers is as large as possible, what is the average of the other three numbers?
The average of five different natural numbers is 4. If the different between the largest and smallest of these numbers is as large as possible, what is the average of the other three numbers?
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Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n overline{1ab1}. Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Đọc tiếp
Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n = \(\overline{1ab1}\). Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
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Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
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Question 9:
The average of five different natural numbers is 4. If the different between the largest and smallest of these numbers is as large as possible, what is the average of the other three numbers?
The average of five different natural numbers is 4.If the difference between the largest and smallest of these numbers is as large as possible,what is the average of the other three numbers?
The sum of two natural numbers is 520 and there are nineteen other natural numbers between them. Find the greatest number.
The sum of two natural numbers is 520 and there are nineteen other natural numbers between them. Find the greatest number.
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Dịch: Tổng của hai số tự nhiên là 520 và có 19 số tự nhiên khác giữa chúng. Tìm số lớn nhất.
Bài Làm: Vì giữa chúng có 19 số tự nhiên khác
=> Hiệu của 2 số đó là: 19 + 1 = 20 (đơn vị)
Số lớn hơn trong 2 số đó là: ( 520 + 20 ) : 2 = 270
Số bé hơn trong 2 số đó là: 520 - 270 = 250
Đáp số: Số lớn: 270, số bé: 250
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