Tìm X
( 2x - 15 ) x ( 2y + 3 ) = -9
-2xy + x + y = 10
Những câu hỏi liên quan
tìm x:
a) (x-3)(x^2+3x+9)+x(x+2)(2-x)=1
b) (x+1)^3-(x-1)^3-6(x-1)^2=-10
tìm GTLN:
a) A= -x^2+2xy-4y^2+2x+10y+5
b) B= -x^2-2y^2-2xy+2x-2y-15
Phân tích thành nhân tử
1) 5x-5y+x(x-y)
2) x^2+4x+3
3) x^2-2xy+y^2-z^2
4) x(x-5)-3x+15
5) y^2-x^2+2x-1
6) 7x^2y+14y+7
7) x^3+x^2-4x-4
8) x^2-2x-15
9) x^2+3y-5
10) 2xy+z+2x+yz
1) \(5x-5y+x\left(x-y\right)\)
\(=5\left(x-y\right)+x\left(x-y\right)\)
\(=\left(x-y\right)\left(x+5\right)\)
2) \(x^2+4x+3\)
\(=\left(x^2+x\right)+\left(3x+3\right)\)
\(=x\left(x+1\right)+3\left(x+1\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
3) \(x^2-2xy+y^2-z^2\)
\(=\left(x-y\right)^2-z^2\)
\(=\left(x-y-z\right)\left(x-y+z\right)\)
4) \(x\left(x-5\right)-3x+15\)
\(=x\left(x-5\right)-3\left(x-5\right)\)
\(=\left(x-5\right)\left(x-3\right)\)
5) \(y^2-x^2+2x-1\)
\(=y^2-\left(x^2-2x+1\right)\)
\(=y^2-\left(x-1\right)^2\)
\(=\left(x+y-1\right)\left(y-x+1\right)\)
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\(1.\left(x-y\right)\left(x+5\right)\)
\(2.\left(x+1\right)\left(x+3\right)\)
\(3.\left(x-y-z\right)\left(x-y+z\right)\)
\(4.\left(x-3\right)\left(x-5\right)\)
\(5.\left(y-x+1\right)\left(y+x+1\right)\)
\(7.\left(x+1\right)\left(x-2\right)^2\)
\(8.\left(x-5\right)\left(x+3\right)\)
\(10.\left(y+1\right)\left(2x+z\right)\)
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Phân tích thành nhân tử
1) 5x-5y+x(x-y)
2) x^2+4x+3
3) x^2-2xy+y^2-z^2
4) x(x-5)-3x+15
5) y^2-x^2+2x-1
6) 7x^2y+14y+7
7) x^3+x^2-4x-4
8) x^2-2x-15
9) x^2+3y-5
10) 2xy+z+2x+yz
1)
5x - 5y + x ( x - y ) = (x-y)(5+x)
2)
x2+4x+3=x2+x+3x+3=(x+1)(x+3)
3)x2-2xy+y2-z2=\(\left(x-y\right)^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\)
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4)\(x\left(x-5\right)-3x+15=\left(x-3\right)\left(x-5\right)\)
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tt thôi nha dài lắmTruong minh quan cái này dễ mà cũng hỏi
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1)\(\begin{cases}x^4+2xy+6y-7x^2-2x^2y+9=0\\2x^2y-x^3=10\end{cases}\)
2)\(\begin{cases}2x^3-x^2y+x^2+y^2-2xy-y=0\\xy+x-2=0\end{cases}\)
Tìm số nguyên x biết
a,3x+3y-2xy=7
b,xy+2x+y+11=0
c,xy+x-y=4
d,2x.(3y-2)+(3y-2)=12
e,3x+4y-xy=15
f,xy+3x-2y=11
g,xy+12=x+y
h,xy-2x-y=-6
i,xy+4x=25+5y
ii,2xy-6y+x=9
iii,xy-x+2y=3
k,2.x^2.y-x^2-2y-2=0
l,x^2.y-x+xy=6
Tìm x; y thuộc N
a) 9 ( x-1).(y-2)= 4
b) x.(y+2)-2y = 1
c) 2xy - 2x-2y = 3
Bài 1
1) (x^2-2x+3)*(x-4)
2) (2x^2-3x-1)*(5x+2)
3) (x^2-2xy+y^2)*(y^2+2xy+x^2+1)
4) (x-7)*(x+5)*(x-5)
5) (x+2y)*(x-y)
6) (x+5)*(x^2-2x+3)
7) 2x(x+5)*(x-1)
8) (x-2y)*(x+2y)
9) (x-1)*(x^2+x+1)
10) (1-2x^2+x)*(x-4+x^2)
(x+2)^2-2x(x+1)+(x-3)(x+3)
(x+2y)(x^2-2xy+4y^2)-(x-2y)(x^2+2xy+4y^2)+2y^3
(3+x)(x^2-9)-(x-3)(x^2+3x+9)
(x-y)^3-(x-y)(x^2+xy+y^2)
rút gọn
a) 2x - 2y / x^2 - 2xy + y^2
b) 2 -2a / a^3 - 1
c) x^2 - 6x + 9 / x^2 - 8x + 15
d) x^4 - 2x^3 / 2x^4 - x^3
a) \(\dfrac{2x-2y}{x^2-2xy+y^2}=\dfrac{2\left(x-y\right)}{\left(x-y\right)^2}=\dfrac{2}{x-y}\)
b) \(\dfrac{2-2a}{a^3-1}=-\dfrac{2-2a}{1-a^3}=-\dfrac{2\left(1-a\right)}{\left(1-a\right)\left(1+a+a^2\right)}=\dfrac{-2}{\left(1+a+a^2\right)}\)
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c) \(\dfrac{x^2-6x+9}{x^2-8x+15}\)
\(=\dfrac{x^2-2.x.3+3^2}{x^2-3x-5x+15}\)
\(=\dfrac{\left(x-3\right)^2}{\left(x^2-3x\right)-\left(5x-15\right)}\)
\(=\dfrac{\left(x-3\right)^2}{x\left(x-3\right)-5\left(x-3\right)}\)
\(=\dfrac{\left(x-3\right)^2}{\left(x-3\right)\left(x-5\right)}\)
\(=\dfrac{x-3}{x-5}\)
d) \(\dfrac{x^4-2x^3}{2x^4-x^3}\)
\(=\dfrac{x^3\left(x-2\right)}{x^3\left(2x-1\right)}\)
\(=\dfrac{x-2}{2x-1}\)
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