Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\).Vậy \(\frac{x}{y}=.......\)
Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\). Vậy\(\frac{x}{y}\) =...
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)
\(44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)
\(\Leftrightarrow44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)
Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)vậy \(\frac{x}{y}\)=........
Biết \(\frac{4x}{6y}\)= \(\frac{2x+8}{3y+11}\). Vậy \(\frac{x}{y}=?\)
Biết \(\frac{4x}{6y}\)=\(\frac{2x+8}{3y+11}\) Vậy \(\frac{x}{y}\)=?
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}.\frac{x}{y}=?\)
Cho \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
Vậy \(\frac{x}{y}=????\)
=>4x(3y+11)=6y(2x+8)
12xy+44x=12xy+48y
=>12xy-12xy=-44x+48y
48y-44x=0
=>48y=44x
=>\(\frac{y}{44}=\frac{x}{48}\)
=>\(\frac{x}{y}=\frac{12}{11}\)
1. Biết \(\frac{4x}{6y}=\frac{2x+8}{3y+11}.\)Vậy x/y=
2. Tìm x,y,z biết \(\frac{x}{z+y+1}=\frac{y}{x+z+1}=\frac{z}{x+y-2}=x+y+z\)
3. tam giác ABC có: AB=6; AC=8, BC=10 và góc A = 5 góc B
Vậy góc C =
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\).tìm x/y
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
<=>4x(3y+11)=6y(2x+8)
<=>12xy+44x=12xy+48y
<=>44x=48y(cùng bớt đi 12xy)
do đó x/y=48/44=12/11
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)
Ta có:4x*3y+44x=6y*2x+48y
12xy+44x=12yx+48y
44x=48y
=>\(\frac{x}{y}=\frac{48}{44}\)
=>x/y=\(\frac{12}{11}\)
\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)tìm \(\frac{x}{y}\)
giúp vs nha
4x(3y + 11)=6y(2x + 8) =>12xy + 44x =12xy + 48y
=>44x = 48y =>\(\frac{x}{y}\)=\(\frac{48}{44}\)