(X-7) .(X+3) < 0
(9-X). (x-7) > 0
3 x 7 x ( 9 + 0 + 1 ) x 7 x 3 x ( 1 + 0 + 9 ) = ?
3 x 7 x ( 9 + 0 + 1 ) x 7 x 3 x ( 1 + 0 + 9 )
= 3 x 7 x 10 x 7 x 3 x 10
= 21 x 10 x 7 x 3 x 10
= 210 x 7 x 3 x 10
= 1470 x 3 x 10
= 4110 x 10
= 41100
k mk nha bn
= 44100 .
Xem đúng không rồi cho mình 1 k nha !
3 x 7 x ( 9 + 0 + 1 ) x 7 x 3 x ( 1 + 0 + 9 ) = 44100
9 : 0 = 7 x 7 = 9 x 7 = 8 x 9 = 0 x 3 = 0 : 9 = 7 : 0 =
9:0=0,7*7=49,9*7=63,7:0=0,8*9=72,0*3=0,0:9=0
9 : 0 = 0
7 x 7 = 49
9 x 7 =63
8 x 9 = 72
0 x 3 = 0
0 : 9 = 0
7 : 0 = 0
học tốt nha
0;49;63;72;0;0;0
Tính nhẩm:
7 x 3 =
7 x 8 =
7 x 2 =
7 x 1 =
7 x 5 =
7 x 6 =
7 x 10 =
0 x 7 =
7 x 7 =
7 x 4 =
7 x 9 =
7 x 0 =
7 x 3 = 21
7 x 8 = 56
7 x 2 = 14
7 x 1 = 7
7 x 4 = 35
7 x 6 = 42
7 x 10 = 70
0 x 7 = 0
7 x 7 = 49
7 x 4 = 28
7 x 9 = 63
7 x 0 = 0
7x3=21
7x8=56
7x2=14
7x1=7
7x5=35
7x6=42
7x10=70
0x7=0
7x7=49
7x4=28
7x9=63
7x0=0
Tính nhẩm:
7 x 1 =
7 x 8 =
7 x 6 =
7 x 5 =
7 x 2 =
7 x 9 =
7 x 4 =
0 x 7 =
7 x 3 =
7 x 7 =
7 x 0 =
7 x 10 =
7 x 1 = 7
7 x 8 = 56
7 x 6 = 42
7 x 5 = 35
7x 2 = 14
7 x 9 = 63
7 x 4 = 28
0 x 7 = 0
7x 3 = 21
7 x 7 = 49
7 x 0 = 0
7 x 10 = 70
Tính nhẩm
7 x 2 = ..... 7 x 5 = ..... 7 x 6 = ..... 0 x 7 = .....
7 x 4 = ..... 7 x 3 = ..... 7 x 9 = ..... 7 x 0 = .....
7 x 8 = ..... 7 x 1 = ..... 7 x 10 = ..... 1 x 7 = .....
7 x 2 = 14 7 x 5 = 35 7 x 6 = 42 0 x 7 = 0
7 x 4 = 28 7 x 3 = 21 7 x 9 = 63 7 x 0 = 0
7 x 8 = 56 7 x 1 = 7 7 x 10 =70 1 x 7 = 7
Bài 4: Tìm x:
1) x2 - 9x = 0 2) x(x - 4) – x2 = 7 3) 3x + 2(x – 5) = 5
4) 25x2 - 1 = 0 5) 3x(x - 2) - 5(x - 2) = 0 6) 3x(x - 7) + 4(x – 7) = 0
7) 4x2 – 9 = 0 8) 10x(x - 4) + 2x - 8 = 0 9) x(2x - 5) - 2x2 = 0
10) 2x2 – 4x = 0 11) 2x(3 - 4x) + 3(4x - 3) = 0 12) 2x (x – 5) – 2x2 = 3
mọi người giúp mình vs chiều 1g mình thi rồi! cảm ơn!
\(1,\Leftrightarrow x\left(x-9\right)=0\Leftrightarrow\left[{}\begin{matrix}x=9\\x=0\end{matrix}\right.\\ 2,\Leftrightarrow x^2-4x-x^2=7\Leftrightarrow-4x=7\Leftrightarrow x=-\dfrac{7}{4}\\ 3,\Leftrightarrow3x+2x-10=5\Leftrightarrow5x=15\Leftrightarrow x=3\\ 4,\Leftrightarrow\left(5x-1\right)\left(5x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=-\dfrac{1}{5}\end{matrix}\right.\\ 5,\Leftrightarrow\left(x-2\right)\left(3x-5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{5}{3}\end{matrix}\right.\\ 6,\Leftrightarrow\left(x-7\right)\left(3x+4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{4}{3}\end{matrix}\right.\)
\(7,\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\\ 8,\Leftrightarrow\left(x-4\right)\left(10x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{5}\\x=4\end{matrix}\right.\\ 9,\Leftrightarrow2x^2-5x-2x^2=0\Leftrightarrow x=0\\ 10,\Leftrightarrow2x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\\ 11,\Leftrightarrow\left(4x-3\right)\left(3-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{3}{2}\end{matrix}\right.\\ 12,\Leftrightarrow2x^2-10x-2x^2=3\Leftrightarrow-10x=3\Leftrightarrow x=-\dfrac{3}{10}\)
\(1,\Leftrightarrow x\left(x-9\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\\ 2,\Leftrightarrow x^2-4x-x^2=7\\ \Leftrightarrow-4x=7\\ \Leftrightarrow x=\dfrac{-7}{4}\\ 3,\Leftrightarrow3x+2x-10=5\\ \Leftrightarrow5x=15\\ \Leftrightarrow x=3\\ 4,\Leftrightarrow\left(5x-1\right)\left(5x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=-\dfrac{1}{5}\end{matrix}\right.\)
\(5,\Leftrightarrow\left(x-2\right)\left(3x-5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{5}{3}\end{matrix}\right.\\ 6,\Leftrightarrow\left(3x+4\right)\left(x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{4}{3}\\x=7\end{matrix}\right.\\ 7,\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)
\(8,\Leftrightarrow10x\left(x-4\right)+2\left(x-4\right)=0\\ \Leftrightarrow\left(x-4\right)\left(10x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{1}{5}\end{matrix}\right.\\ 9,\Leftrightarrow2x^2-5x-2x^2=0\\ \Leftrightarrow-5x=0\\ \Leftrightarrow x=0\\ 10,\Leftrightarrow2x\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
\(11,\Leftrightarrow\left(2x-3\right)\left(4x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{3}{4}\end{matrix}\right.\\ 12,\Leftrightarrow2x^2-10x-2x^2=3\\ \Leftrightarrow-10x=3\\ \Leftrightarrow x=-\dfrac{3}{10}\)
1) \(x^2-9x=0\Rightarrow x\left(x-9\right)=0\Rightarrow x=0;9\)
2) \(x\left(x-4\right)-x^2=7\Rightarrow-4x=7\Rightarrow x=-\dfrac{7}{4}\)
3) \(3x+2\left(x-5\right)=5\Rightarrow5x-10=5\Rightarrow5x=15\Rightarrow x=3\)
4) \(25x^2-1=0\Rightarrow x^2=\dfrac{1}{25}\Rightarrow x=\pm\dfrac{1}{5}\)
5) \(3x\left(x-2\right)-5\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(3x-5\right)=0\Rightarrow x=2;\dfrac{5}{3}\)
6) \(3x\left(x-7\right)+4\left(x-7\right)\Rightarrow\left(3x+4\right)\left(x-7\right)=0\Rightarrow x=-\dfrac{4}{3};7\)
7) \(4x^2-9=0\Rightarrow x^2=\dfrac{9}{4}\Rightarrow x=\pm\dfrac{3}{2}\)
8) \(10x\left(x-4\right)+2x-8=0\Rightarrow2\left(x-4\right)\left(5x+1\right)=0\Rightarrow x=4;-\dfrac{1}{5}\)
9) \(x\left(2x-5\right)-2x^2=0\Rightarrow x\left(2x-5-2x=0\right)\Rightarrow x=0\)
10) \(2x^2-4x=0\Rightarrow2x\left(x-2\right)=0\Rightarrow x=0;2\)
11) \(2x\left(3-4x\right)+3\left(4x-3\right)=0\Rightarrow2x\left(4x-3\right)-3\left(4x-3\right)=0\Rightarrow\left(4x-3\right)\left(2x-3\right)=0\Rightarrow x=\dfrac{3}{4};\dfrac{3}{2}\)
12) \(2x\left(x-5\right)-2x^2=3\Rightarrow-10x=3\Rightarrow x=-\dfrac{3}{10}\)
1, 72-3./x+1/=9
2, 17-(43-/x/)=45
3, 3/x-1/-5=7
4, -12.(x-5)+7.(3-x)=5
5, (x-2) . (x+4)=0
6, (x-2).(x+15)=0
7, (7-x).(x+19)=0
8, -5<x<1
9, /x/<3
10, (x.3).(x-5)<0
(X-7) .(X+3) < 0
(9-X). (x-7) > 0
Cho biểu thức sau : A = 9x +17/ x 1 Để A nguyên thì x cần đạt giá trị : Chọn câu trả lời đúng:
A. x ∈ { - 9 ; - 5 ; - 3 ; - 2 ; 0 ; 1 ; 4 ; 7 } B. x ∈ { - 9 ; - 5 ; - 3 ; - 2 ; 0 ; 1 ; 3 ; 8 }
C. x ∈ { - 8 ; - 5 ; - 3 ; - 2 ; 0 ; 1 ; 3 ; 7 } D. x ∈ { - 9 ; - 5 ; - 3 ; - 2 ; 0 ; 1 ; 3 ; 7 }