5x² + 10xy - 4x - 8y

= 5x(x + 2y) - 2(x - 2y)

= (5x - 2)(x + 2y)

=(5x² + 10xy) - (4x + 8y) = 5x.(x + 2y) - 4.(x + 2y) = (5x - 4).(x + 2y)

\(5x^2+10xy-4x-8y=\left(5x^2+10xy\right)-\left(4x+8y\right)=5x\left(x+2y\right)-4\left(x+2y\right)=\left(5x-4\right)\left(x+2y\right)\)

\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x\left[x^2-y^2+y+y-1\right]\)

\(=5x\left[x^2-y\left(y-1\right)+\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y+1\right)\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y^2-1^2\right)\right]\)

\(=5x\left[\left(x-y\right)\left(x+y\right)+1\right]\)

Lâu k làm, sai thông cảm 

Answer:

\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x[x^2-\left(y^2-2y+1\right)]\)

\(=5x[x^2-\left(y-1\right)^2]\)

\(=5x\left(x-y+1\right)\left(x+y-1\right)\)

5x\(^2\)- 10xy +5x\(^2\)-20z\(^2\)
= 5(x\(^2\)-2xy+x\(^2\)-4z\(^2\))
= 5(2x\(^2\)-2xy-4z\(^2\))
 

5^2-10xy+5x^2-20z^2

=5(x^2-2xy+y^2-4z^2)

=5((x-y)^2-4z^2)

=5(x-y-2z)(x-y+2z)

\(5x^3-5x^2y-10x^2+10xy=5x^2\left(x-y\right)-10x\left(x-y\right)=5x\left(x-2\right)\left(x-y\right)\)

5x²-10xy+5y²-20z²

=5(x²-2xy+y²-4z²)

=5[(x-y)²-4z²]

=5(x-y-2z)(x-y+2z)

dễ hiểu thôi.hơi vắn tắt 

\(=5\left(x-y\right)^2\)

<=> 5 ( x² - 2xy + y²)

<=> 5 ( x - y )²

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