(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)

=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200-45200)

=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0

=0

(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)

= (12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 45200 )

= (12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0

= 0 

= [ (12+88) + (77+23) + (34+66) + (45+55) ] x ( 45200 - 45200 )

= [ 100 + 100 + 100 + 100 ] x 0

= 400

ĐÁP ÁN  : 400

Giải:

( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 1808 .25 )

=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 45200 )

=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . 0

=0

Học tốt!!!

(12+77+34+23+88+45+55+66)* (45200-1808*25)

=(12+77+34+23+88+45+55+66)* (45200-45200)

=(12+17+34+23+88+45+55+66)* 0

=0

\(\left(12+77+34+23+88+45+55+66\right)\times\left(45200-1808\times25\right)\)

\(=\left(12+77+34+23+88+45+55+66\right)\times\left(45200-45200\right)\)

\(=\left(12+77+34+23+88+45+55+66\right)\times0\)

\(=0.\)

(45+75)*66+(75+45)*34

=(45+75)*(66+34)

=120*100

=12000

11+22+33+44+55+66+77+88+99:11

=11+22+33+44+55+66+77+88+9

=(11+9)+(22+88)+(33+77)+(44+66)+55

=20+110*3+55

=20+330+55

=405

Ta có :

a, (45 + 75) x 66 + (75 + 45) x 34

=  (45 + 75) x (66 + 34)

=   120  x 100

=  12000

11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99 : 11

= 33 + 77 + 121 + 165 + 9

= 405

\(11+22+33+44+55+66+77+88+99:11\)

\(\left(11+99\right)+\left(22+88\right)+\left(33+77\right)+\left(44+66\right)+55:11\)

\(110+110+110+110+55:11\)

\(440+55:11\)

\(445\)

Bài 2:

a: \(17-x=3\)

=>\(x=17-3\)

=>x=14(nhận)

b: \(2\cdot\left(x-1\right):3=6\)

=>\(2\left(x-1\right)=6\cdot3=18\)

=>x-1=18/2=9

=>x=9+1=10(nhận)

c: \(x+\left(-2\right)=\left(-11\right)+7\)

=>\(x-2=-4\)

=>\(x=-4+2=-2\left(loại\right)\)

d: \(\left(x-1\right)^2-5=20\)

=>\(\left(x-1\right)^2=25\)

=>\(\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(nhận\right)\\x=-4\left(loại\right)\end{matrix}\right.\)

Câu 3:

a: Đặt *=a

\(\overline{57a3}⋮9\)

=>\(5+7+a+3⋮9\)

=>\(a+15⋮3\)

mà 0<=a<=9

nên a=3

=>*=a

b: \(A=123\cdot7+8+9\)

123*7 là số lẻ

9 là số lẻ

=>123*7+9 chia hết cho 2

mà 8 chia hết cho 2

nên \(A=123\cdot7+9+8⋮2\)

\(123\cdot7⋮3;9⋮3;8⋮̸3\)

=>\(A=123\cdot7+9+8⋮̸3\)

c: \(B=3\cdot5\cdot7+10^{50}\)

\(=5\cdot3\cdot7+5\cdot5^{49}\cdot2^{49}\)

\(=5\left(3\cdot7+5^{49}\cdot2^{49}\right)⋮5\)

=>B là hợp số

= 11(1+2+3+4+5+6+7+8+9) = 11 * 9(9+1) = 11*9*10 = 990

11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99

= (11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55

= 110 + 110 + 110 + 110 + 55

= 110 x 4 + 55

= 440 + 55

= 495 

11+22+33+44+55+66+77+88+99

=(11+99)+(22+88)+(33+77)+(44+66)+55

=110+110+110+110+55

=110x4+55

=440+55

=495

11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99

= (11 + 88) + (22 + 77) + (33 + 66) + (44 + 55)  + 99

 =      99       +       99      +      99        +      99       + 99

= 99 x 5

= 495

11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99

= (11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55

=      110     +      110     +     110      +     110      + 55

= 495

11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99

= (11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55

= 110 +  110 +110 + 110 + 55

= 495

Tính bằng cách thuận tiện nhất:

                    11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99

                   = (11 + 88) + (22 + 77) + (33 + 66) + (44 + 55)  + 99

                   =      99       +       99      +      99        +      99       + 99

                   = 99 x 5

                   = 495