từ trên

=>4x(3y+11)=6y(2x+8)

=>12xy+44=12xy+48

=>\(\frac{x}{y}=\frac{12}{11}\)

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)

<=>4x(3y+11)=6y(2x+8)

<=>12xy+44x=12xy+48y

<=>44x=48y(cùng bớt đi 12xy)

do đó x/y=48/44=12/11

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)

Ta có:4x*3y+44x=6y*2x+48y

12xy+44x=12yx+48y

44x=48y

=>\(\frac{x}{y}=\frac{48}{44}\)

=>x/y=\(\frac{12}{11}\)

4x(3y + 11)=6y(2x + 8)  =>12xy + 44x =12xy + 48y

=>44x = 48y  =>\(\frac{x}{y}\)=\(\frac{48}{44}\)

c1:Thay số 

Q=\(\frac{5+2.4-3.3}{5-2.4+3.3}\)

O=\(\frac{4}{6}\)=\(\frac{2}{3}\)

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)

\(4x\left(3y+1\right)=6y\left(2x+8\right)\)

\(12xy+4x=12xy+48y\)

\(4x-48y=0\)

\(4x=48y\)

Ta có:\(\frac{4x}{48y}\)

\(\Leftrightarrow\)\(\frac{x}{y}=\frac{1}{12}\)

=>4x(3y+11)=6y(2x+8)

12xy+44x=12xy+48y

=>12xy-12xy=-44x+48y

48y-44x=0

=>48y=44x

=>\(\frac{y}{44}=\frac{x}{48}\)

=>\(\frac{x}{y}=\frac{12}{11}\)

\(\frac{12}{11}\)

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)

\(44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\Leftrightarrow4x\left(3y+11\right)=6y\left(2x+8\right)\Leftrightarrow12xy+44x=12xy+48y\)

\(\Leftrightarrow44x=48y\Leftrightarrow\frac{x}{y}=\frac{48}{44}=\frac{12}{11}\)