a)11x-7<8x+7

<-->11x-8x<7+7

<-->3x<14

<--->x<14/3 mà x nguyên dương 

---->x \(\in\){0;1;2;3;4}

b)x^2+2x+8/2-x^2-x+1>x^2-x+1/3-x+1/4

<-->6x^2+12x+48-2x^2+2x-2>4x^2-4x+4-3x-3(bo mau)

<--->6x^2+12x-2x^2+2x-4x^2+4x+3x>4-3+2-48

<--->21x>-45

--->x>-45/21=-15/7  mà x nguyên âm 

----->x \(\in\){-1;-2}

c)2(3-x)-1,5(x-4)<3-x

<--->6-2x-1,5x+6<3-x

<--->6+6-3<2x+1,5x-x

<--->9<2,5x

<--->3,6<x mà x la so nguyen nhỏ nhất 

--->x=4

Các câu na ná chắc nên mk làm mẫu 2 bài thui nha !

a, pt <=> x-23/24 + x-23/25 - x-23/26 - x-23/27 = 0

<=> (x-23).(1/24+1/25-1/26-1/27) = 0

<=> x-23=0 ( vì 1/24+1/25-1/26-1/27 > 0 )

<=> x=23

b, pt <=> (201-x/99 + 1)+(203-x/97 + 1)+(205-x/95 + 1) = 0

<=> 300-x/99 + 300-x/97 + 300-x/95 = 0

<=> (300-x).(1/99+1/97+1/95) = 0

<=> 300-x = 0 ( vì 1/99+1/97+1/95 > 0 )

<=> x=300

Tk mk nha

sory mình học lớp 7

em moi hoc lop 7 thoi a doi xong ki 2 nha

em mới học lớp 7 thôi

\(\frac{x^2-10x-29}{1971}+\frac{x^2-10x-27}{1973}=\frac{x^2-10x-1971}{29}+\frac{x^2-10x-1973}{27}\)

\(\Leftrightarrow\frac{x^2-10x-29}{1971}-1+\frac{x^2-10x-27}{1973}-1=\frac{x^2-10x-1971}{29}-1+\frac{x^2-10x-1973}{27}-1\)

\(\Leftrightarrow\frac{x^2-10x-29-1971}{1971}+\frac{x^2-10x-27-1973}{1973}=\frac{x^2-10x-1971-29}{29}+\frac{x^2-10x-193-27}{27}\)

\(\Leftrightarrow\frac{x^2-10x-2000}{1971}+\frac{x^2-10x-2000}{1973}-\frac{x^2-10x-2000}{29}-\frac{x^2-10x-2000}{27}=0\)

\(\Leftrightarrow\left(x^2-10x-2000\right)\left(\frac{1}{1971}+\frac{1}{1973}-\frac{1}{29}-\frac{1}{27}\right)=0\)

\(\Leftrightarrow x^2-10x-2000=0\)

\(\Leftrightarrow x^2-50x+40x-2000=0\)

\(\Leftrightarrow x\left(x-50\right)+40\left(x-50\right)=0\)

\(\Leftrightarrow\left(x-50\right)\left(x+40\right)=0\)

     Th1  \(x-50=0\Leftrightarrow x=50\)

    Th2  \(x+40=0\Leftrightarrow x=-40\)

Vậy tập nghiệm của phương trình là   \(S=\left\{50;-40\right\}\)

Ai làm đc câu nào thì làm giúp mình với ạ, cảm ơn trc:(((

\(1,3x-5x+5=-8\)

\(\Leftrightarrow-2x+5+8=0\)

\(\Leftrightarrow-2x=-13\)

\(\Leftrightarrow x=\frac{13}{2}\)

\(A=\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}-\frac{8x}{x^2-1}\right):\left(\frac{2x-2x^2-6}{x^2-1}-\frac{2}{x-1}\right)\)

\(A=\left(\frac{\left(x+1\right)^2}{\left(x-1\right)\left(x+1\right)}-\frac{\left(x-1\right)^2}{\left(x-1\right)\left(x+1\right)}-\frac{8x}{\left(x+1\right)\left(x-1\right)}\right):\left(\frac{2x-2x^2-6}{\left(x-1\right)\left(x+1\right)}-\frac{2\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\right)\)

\(A=\left(\frac{x^2+2x+1-x^2+2x-1-8x}{\left(x-1\right)\left(x+1\right)}\right):\left(\frac{2x-2x^2-6-2x-2}{\left(x+1\right)\left(x-1\right)}\right)\)

\(A=\left(\frac{4x-8x}{\left(x-1\right)\left(x+1\right)}\right).\frac{\left(x-1\right)\left(x+1\right)}{-2x^2-8}\)

.......... 

\(\frac{x+32}{2008}+\frac{x+31}{2009}+\frac{x+29}{2011}+\frac{x+28}{2012}+\frac{x+2056}{4}=0\) \(=0\)

\(\Leftrightarrow\)\(\frac{x+32}{2008}+1+\frac{x+31}{2009}+1+\frac{x+29}{2011}+1\)\(+\frac{x+28}{2012}+1+\frac{x+2056}{4}-4\)\(=0\)

\(\Leftrightarrow\)\(\frac{x+32}{2008}+\frac{2008}{2008}+\frac{x+31}{2009}+\frac{2009}{2009}+\)\(\frac{x+29}{2011}+\frac{2011}{2011}+\frac{x+28}{2012}+\frac{2012}{2012}+\)\(\frac{x+2056}{4}-\frac{16}{4}\)\(=0\)

\(\Leftrightarrow\)\(\frac{x+32+2008}{2008}+\frac{x+31+2009}{2009}\)\(+\frac{x+29+2011}{2011}+\frac{x+28+2012}{2012}\)\(+\frac{x+2056-16}{4}\)\(=0\)

\(\Leftrightarrow\)\(\frac{x+2040}{2008}+\frac{x+2040}{2009}+\frac{x+2040}{2011}\)\(+\frac{x+2040}{2012}+\frac{x+2040}{4}=0\)

\(\Leftrightarrow\)\(\left(x+2040\right).\left(\frac{1}{2008}+\frac{1}{2009}+\frac{1}{2011}+\frac{1}{2012}+\frac{1}{4}\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x+2040=0\\\frac{1}{2008}+\frac{1}{2009}+\frac{1}{2011}+\frac{1}{2012}+\frac{1}{4}=0\end{cases}}\)(vô lí)

\(\Leftrightarrow\)\(x=-2040\)

Vậy phương trình có nghiệm là : x = -2040

* \(\frac{x^2+x+1}{x^2+x+2}=\frac{7}{6}\) <=> \(6\left(x^2+x+1\right)=7\left(x^2+x+2\right)\) <=> \(6x^2+6x+6=7x^2+7x+14\)

<=> \(7x^2+7x+14-6x^2-6x-6=0\) <=> \(x^2+x+8=0\)

\(\Delta=b^2-4ac=1^2-4\cdot1\cdot8=1-32=-31< 0\)

Vậy phương trình vô nghiệm

Tập nghiệmcủa phương trình là x={ -1; 0}

Là mình ấn máy tính nó ra kết quả thế nhé